Explanation:
C Given,
\(x^2=4 y\)
\(y^2=4 x\)
On solving equation (i) and (ii), we get -
\(\left(\frac{x^2}{4}\right)^2=4 x\)
\(\frac{x^4}{16}=4 x\)
\(x^4=64 x\)
\(x^4-64 x=0\)
\(x\left(x^3-64\right)=0\)
\(x=0, x^3=64\)
\(x=0, x=4\)
On putting the values of \(x\) in equation (i) and (ii) we get \(y=0\) and \(y=4,-4\)
\(\left(\because \mathrm{y}=-4\right.\) does not satisfy the equation \(\left.\mathrm{x}^2=4 \mathrm{y}\right)\)
Thus, the points of intersection are \((0,0)\) and \((4,4)\) Hence, the point other than origin is \((4,4)\)