87042 You are given a curve, \(y=\ln (x+e)\). What will be the area enclosed between this curve and the coordinate axes?

87043 The area of the region \(A=\{(x, y): 0 \leq y \leq x|x|+1\) and \(-1 \leq \mathrm{x} \leq 1)\}\) in sq. units , is

87047 The area (in sq. units) of the region \(\left[(x, y) \in R^{2}\right.\) : \(\left.\mathrm{x}^{2} \leq \mathrm{y} \leq \mathbf{3}-\mathbf{2 x}\right\}\) is

87048 Given, \(f(x)=\left\{\begin{array}{l}x, &0 \leq x\lt \frac{1}{2} \\ \frac{1}{2},& x=\frac{1}{2} \\ 1-x,& \frac{1}{2}\lt x \leq 1\end{array}\right.\) and \(g(x)=\)
\(\left(x-\frac{1}{2}\right)^{2}, x \in R\). Then the area (in sq. units) of the region bounded by the curves \(y=f(x)\) and \(y=g(x)\) between eh lines, \(2 x=1\) and \(2 x=\sqrt{3}\), is

87049 The area (in sq. units) of the region \(\left\{(x, y) \in R^{2}\right.\) \(\left.\mid 4 x^{2} \leq y \leq 8 x+12\right)\) is

87042 You are given a curve, \(y=\ln (x+e)\). What will be the area enclosed between this curve and the coordinate axes?

87043 The area of the region \(A=\{(x, y): 0 \leq y \leq x|x|+1\) and \(-1 \leq \mathrm{x} \leq 1)\}\) in sq. units , is

87047 The area (in sq. units) of the region \(\left[(x, y) \in R^{2}\right.\) : \(\left.\mathrm{x}^{2} \leq \mathrm{y} \leq \mathbf{3}-\mathbf{2 x}\right\}\) is

87048 Given, \(f(x)=\left\{\begin{array}{l}x, &0 \leq x\lt \frac{1}{2} \\ \frac{1}{2},& x=\frac{1}{2} \\ 1-x,& \frac{1}{2}\lt x \leq 1\end{array}\right.\) and \(g(x)=\)
\(\left(x-\frac{1}{2}\right)^{2}, x \in R\). Then the area (in sq. units) of the region bounded by the curves \(y=f(x)\) and \(y=g(x)\) between eh lines, \(2 x=1\) and \(2 x=\sqrt{3}\), is

87049 The area (in sq. units) of the region \(\left\{(x, y) \in R^{2}\right.\) \(\left.\mid 4 x^{2} \leq y \leq 8 x+12\right)\) is

87042 You are given a curve, \(y=\ln (x+e)\). What will be the area enclosed between this curve and the coordinate axes?

87043 The area of the region \(A=\{(x, y): 0 \leq y \leq x|x|+1\) and \(-1 \leq \mathrm{x} \leq 1)\}\) in sq. units , is

87047 The area (in sq. units) of the region \(\left[(x, y) \in R^{2}\right.\) : \(\left.\mathrm{x}^{2} \leq \mathrm{y} \leq \mathbf{3}-\mathbf{2 x}\right\}\) is

87048 Given, \(f(x)=\left\{\begin{array}{l}x, &0 \leq x\lt \frac{1}{2} \\ \frac{1}{2},& x=\frac{1}{2} \\ 1-x,& \frac{1}{2}\lt x \leq 1\end{array}\right.\) and \(g(x)=\)
\(\left(x-\frac{1}{2}\right)^{2}, x \in R\). Then the area (in sq. units) of the region bounded by the curves \(y=f(x)\) and \(y=g(x)\) between eh lines, \(2 x=1\) and \(2 x=\sqrt{3}\), is

87049 The area (in sq. units) of the region \(\left\{(x, y) \in R^{2}\right.\) \(\left.\mid 4 x^{2} \leq y \leq 8 x+12\right)\) is

87042 You are given a curve, \(y=\ln (x+e)\). What will be the area enclosed between this curve and the coordinate axes?

87043 The area of the region \(A=\{(x, y): 0 \leq y \leq x|x|+1\) and \(-1 \leq \mathrm{x} \leq 1)\}\) in sq. units , is

87047 The area (in sq. units) of the region \(\left[(x, y) \in R^{2}\right.\) : \(\left.\mathrm{x}^{2} \leq \mathrm{y} \leq \mathbf{3}-\mathbf{2 x}\right\}\) is

87048 Given, \(f(x)=\left\{\begin{array}{l}x, &0 \leq x\lt \frac{1}{2} \\ \frac{1}{2},& x=\frac{1}{2} \\ 1-x,& \frac{1}{2}\lt x \leq 1\end{array}\right.\) and \(g(x)=\)
\(\left(x-\frac{1}{2}\right)^{2}, x \in R\). Then the area (in sq. units) of the region bounded by the curves \(y=f(x)\) and \(y=g(x)\) between eh lines, \(2 x=1\) and \(2 x=\sqrt{3}\), is

87049 The area (in sq. units) of the region \(\left\{(x, y) \in R^{2}\right.\) \(\left.\mid 4 x^{2} \leq y \leq 8 x+12\right)\) is

87042 You are given a curve, \(y=\ln (x+e)\). What will be the area enclosed between this curve and the coordinate axes?

87043 The area of the region \(A=\{(x, y): 0 \leq y \leq x|x|+1\) and \(-1 \leq \mathrm{x} \leq 1)\}\) in sq. units , is

87047 The area (in sq. units) of the region \(\left[(x, y) \in R^{2}\right.\) : \(\left.\mathrm{x}^{2} \leq \mathrm{y} \leq \mathbf{3}-\mathbf{2 x}\right\}\) is

87048 Given, \(f(x)=\left\{\begin{array}{l}x, &0 \leq x\lt \frac{1}{2} \\ \frac{1}{2},& x=\frac{1}{2} \\ 1-x,& \frac{1}{2}\lt x \leq 1\end{array}\right.\) and \(g(x)=\)
\(\left(x-\frac{1}{2}\right)^{2}, x \in R\). Then the area (in sq. units) of the region bounded by the curves \(y=f(x)\) and \(y=g(x)\) between eh lines, \(2 x=1\) and \(2 x=\sqrt{3}\), is

87049 The area (in sq. units) of the region \(\left\{(x, y) \in R^{2}\right.\) \(\left.\mid 4 x^{2} \leq y \leq 8 x+12\right)\) is