140349 Two springs of force constant $300 \mathrm{~N} / \mathrm{m}$ (Spring A) and $400 \mathrm{~N} / \mathrm{m}$ (Spring B) are joined together in series. The combination is compressed by $8.75 \mathrm{~cm}$. The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}}$. Then $\frac{E_{A}}{E_{B}}$ is equal to:
140350 A block of mass $1 \mathrm{~kg}$ tied to a long spring of spring constant $100 \mathrm{Nm}^{-1}$ is at rest on a horizontal frictionless surface. The block is pulled through a distance $5 \mathrm{~cm}$ from its, equilibrium position and released. Then the total energy of the block when it is at a distance $\mathbf{4} \mathbf{~ c m}$ from the equilibrium positions is
140349 Two springs of force constant $300 \mathrm{~N} / \mathrm{m}$ (Spring A) and $400 \mathrm{~N} / \mathrm{m}$ (Spring B) are joined together in series. The combination is compressed by $8.75 \mathrm{~cm}$. The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}}$. Then $\frac{E_{A}}{E_{B}}$ is equal to:
140350 A block of mass $1 \mathrm{~kg}$ tied to a long spring of spring constant $100 \mathrm{Nm}^{-1}$ is at rest on a horizontal frictionless surface. The block is pulled through a distance $5 \mathrm{~cm}$ from its, equilibrium position and released. Then the total energy of the block when it is at a distance $\mathbf{4} \mathbf{~ c m}$ from the equilibrium positions is
140349 Two springs of force constant $300 \mathrm{~N} / \mathrm{m}$ (Spring A) and $400 \mathrm{~N} / \mathrm{m}$ (Spring B) are joined together in series. The combination is compressed by $8.75 \mathrm{~cm}$. The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}}$. Then $\frac{E_{A}}{E_{B}}$ is equal to:
140350 A block of mass $1 \mathrm{~kg}$ tied to a long spring of spring constant $100 \mathrm{Nm}^{-1}$ is at rest on a horizontal frictionless surface. The block is pulled through a distance $5 \mathrm{~cm}$ from its, equilibrium position and released. Then the total energy of the block when it is at a distance $\mathbf{4} \mathbf{~ c m}$ from the equilibrium positions is
140349 Two springs of force constant $300 \mathrm{~N} / \mathrm{m}$ (Spring A) and $400 \mathrm{~N} / \mathrm{m}$ (Spring B) are joined together in series. The combination is compressed by $8.75 \mathrm{~cm}$. The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}}$. Then $\frac{E_{A}}{E_{B}}$ is equal to:
140350 A block of mass $1 \mathrm{~kg}$ tied to a long spring of spring constant $100 \mathrm{Nm}^{-1}$ is at rest on a horizontal frictionless surface. The block is pulled through a distance $5 \mathrm{~cm}$ from its, equilibrium position and released. Then the total energy of the block when it is at a distance $\mathbf{4} \mathbf{~ c m}$ from the equilibrium positions is
140349 Two springs of force constant $300 \mathrm{~N} / \mathrm{m}$ (Spring A) and $400 \mathrm{~N} / \mathrm{m}$ (Spring B) are joined together in series. The combination is compressed by $8.75 \mathrm{~cm}$. The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}}$. Then $\frac{E_{A}}{E_{B}}$ is equal to:
140350 A block of mass $1 \mathrm{~kg}$ tied to a long spring of spring constant $100 \mathrm{Nm}^{-1}$ is at rest on a horizontal frictionless surface. The block is pulled through a distance $5 \mathrm{~cm}$ from its, equilibrium position and released. Then the total energy of the block when it is at a distance $\mathbf{4} \mathbf{~ c m}$ from the equilibrium positions is