80221 Let \(f:[0,1] \rightarrow \mathrm{R}\) (the set of all real numbers) be a function. Suppose the function \(f\) is twice differentiable, \(f(0)=f(1)=0\) and satisfies \(f^{\prime \prime}(x)-2 f^{\prime}(x)+f(x) \geq e^{x}, x \in[0,1]\). If the function \(\mathrm{e}^{-\mathrm{x}} f(\mathrm{x})\) assumes its minimum in the interval \([0,1]\) at \(x=\frac{1}{4}\), which of the following is true?
80221 Let \(f:[0,1] \rightarrow \mathrm{R}\) (the set of all real numbers) be a function. Suppose the function \(f\) is twice differentiable, \(f(0)=f(1)=0\) and satisfies \(f^{\prime \prime}(x)-2 f^{\prime}(x)+f(x) \geq e^{x}, x \in[0,1]\). If the function \(\mathrm{e}^{-\mathrm{x}} f(\mathrm{x})\) assumes its minimum in the interval \([0,1]\) at \(x=\frac{1}{4}\), which of the following is true?
80221 Let \(f:[0,1] \rightarrow \mathrm{R}\) (the set of all real numbers) be a function. Suppose the function \(f\) is twice differentiable, \(f(0)=f(1)=0\) and satisfies \(f^{\prime \prime}(x)-2 f^{\prime}(x)+f(x) \geq e^{x}, x \in[0,1]\). If the function \(\mathrm{e}^{-\mathrm{x}} f(\mathrm{x})\) assumes its minimum in the interval \([0,1]\) at \(x=\frac{1}{4}\), which of the following is true?
80221 Let \(f:[0,1] \rightarrow \mathrm{R}\) (the set of all real numbers) be a function. Suppose the function \(f\) is twice differentiable, \(f(0)=f(1)=0\) and satisfies \(f^{\prime \prime}(x)-2 f^{\prime}(x)+f(x) \geq e^{x}, x \in[0,1]\). If the function \(\mathrm{e}^{-\mathrm{x}} f(\mathrm{x})\) assumes its minimum in the interval \([0,1]\) at \(x=\frac{1}{4}\), which of the following is true?