NEET Test Series from KOTA - 10 Papers In MS WORD
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ALDEHYDES, KETONES AND CARBOXYLIC ACID
26590
\({C_6}{H_6} + CO + HCl \xrightarrow{{{\text{Anhy }}AlC{l_3}}}X + HCl\) Compound \(X\) is
1 \({C_6}{H_5}C{H_3}\)
2 \({C_6}{H_5}C{H_2}Cl\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}COOH\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26591
Which of the following gases when passed through warm dilute solution of \({H_2}S{O_4}\) in presence of \(HgS{O_4}\) gives acetaldehyde
1 \(C{H_4}\)
2 \({C_2}{H_6}\)
3 \({C_2}{H_4}\)
4 \({C_2}{H_2}\)
Explanation:
The overall reaction taking place here is "Oxymercuration-Demercuration" the final product formed is acetaldehyde.And, The explanation is in the attachment below.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26593
Propyne on hydrolysis in presence of \(HCl\) and \(HgS{O_4}\) gives
1 Acetaldehyde
2 Acetone
3 Formaldehyde
4 None of these
Explanation:
above reaction is an example of oxymercuration-demercuration
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26594
Which of the following on reaction with \(N{H_3}\) gives urinary antiseptic compound
1 \(HCHO\)
2 \(C{H_3}CHO\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}C{H_2}CHO\)
Explanation:
\(NH _3\) react differently with all this reactant as follow. \(\text { (i) } 6 HCHO +4 NH _3 \rightarrow\left( CH _2\right)_6 N _4+6 H _2 O\) \((ii)\) \(CH _3 CHO + NH _3 \rightarrow CH _3 CH ( OH ) NH _2\) \(\text { (iii) } C _6 H _5 CHO + NH _3 \rightarrow C _6 H _5- CH \left( NCHC _6 H _5\right)_2 \text { }\)
26590
\({C_6}{H_6} + CO + HCl \xrightarrow{{{\text{Anhy }}AlC{l_3}}}X + HCl\) Compound \(X\) is
1 \({C_6}{H_5}C{H_3}\)
2 \({C_6}{H_5}C{H_2}Cl\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}COOH\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26591
Which of the following gases when passed through warm dilute solution of \({H_2}S{O_4}\) in presence of \(HgS{O_4}\) gives acetaldehyde
1 \(C{H_4}\)
2 \({C_2}{H_6}\)
3 \({C_2}{H_4}\)
4 \({C_2}{H_2}\)
Explanation:
The overall reaction taking place here is "Oxymercuration-Demercuration" the final product formed is acetaldehyde.And, The explanation is in the attachment below.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26593
Propyne on hydrolysis in presence of \(HCl\) and \(HgS{O_4}\) gives
1 Acetaldehyde
2 Acetone
3 Formaldehyde
4 None of these
Explanation:
above reaction is an example of oxymercuration-demercuration
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26594
Which of the following on reaction with \(N{H_3}\) gives urinary antiseptic compound
1 \(HCHO\)
2 \(C{H_3}CHO\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}C{H_2}CHO\)
Explanation:
\(NH _3\) react differently with all this reactant as follow. \(\text { (i) } 6 HCHO +4 NH _3 \rightarrow\left( CH _2\right)_6 N _4+6 H _2 O\) \((ii)\) \(CH _3 CHO + NH _3 \rightarrow CH _3 CH ( OH ) NH _2\) \(\text { (iii) } C _6 H _5 CHO + NH _3 \rightarrow C _6 H _5- CH \left( NCHC _6 H _5\right)_2 \text { }\)
26590
\({C_6}{H_6} + CO + HCl \xrightarrow{{{\text{Anhy }}AlC{l_3}}}X + HCl\) Compound \(X\) is
1 \({C_6}{H_5}C{H_3}\)
2 \({C_6}{H_5}C{H_2}Cl\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}COOH\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26591
Which of the following gases when passed through warm dilute solution of \({H_2}S{O_4}\) in presence of \(HgS{O_4}\) gives acetaldehyde
1 \(C{H_4}\)
2 \({C_2}{H_6}\)
3 \({C_2}{H_4}\)
4 \({C_2}{H_2}\)
Explanation:
The overall reaction taking place here is "Oxymercuration-Demercuration" the final product formed is acetaldehyde.And, The explanation is in the attachment below.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26593
Propyne on hydrolysis in presence of \(HCl\) and \(HgS{O_4}\) gives
1 Acetaldehyde
2 Acetone
3 Formaldehyde
4 None of these
Explanation:
above reaction is an example of oxymercuration-demercuration
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26594
Which of the following on reaction with \(N{H_3}\) gives urinary antiseptic compound
1 \(HCHO\)
2 \(C{H_3}CHO\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}C{H_2}CHO\)
Explanation:
\(NH _3\) react differently with all this reactant as follow. \(\text { (i) } 6 HCHO +4 NH _3 \rightarrow\left( CH _2\right)_6 N _4+6 H _2 O\) \((ii)\) \(CH _3 CHO + NH _3 \rightarrow CH _3 CH ( OH ) NH _2\) \(\text { (iii) } C _6 H _5 CHO + NH _3 \rightarrow C _6 H _5- CH \left( NCHC _6 H _5\right)_2 \text { }\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26590
\({C_6}{H_6} + CO + HCl \xrightarrow{{{\text{Anhy }}AlC{l_3}}}X + HCl\) Compound \(X\) is
1 \({C_6}{H_5}C{H_3}\)
2 \({C_6}{H_5}C{H_2}Cl\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}COOH\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26591
Which of the following gases when passed through warm dilute solution of \({H_2}S{O_4}\) in presence of \(HgS{O_4}\) gives acetaldehyde
1 \(C{H_4}\)
2 \({C_2}{H_6}\)
3 \({C_2}{H_4}\)
4 \({C_2}{H_2}\)
Explanation:
The overall reaction taking place here is "Oxymercuration-Demercuration" the final product formed is acetaldehyde.And, The explanation is in the attachment below.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26593
Propyne on hydrolysis in presence of \(HCl\) and \(HgS{O_4}\) gives
1 Acetaldehyde
2 Acetone
3 Formaldehyde
4 None of these
Explanation:
above reaction is an example of oxymercuration-demercuration
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26594
Which of the following on reaction with \(N{H_3}\) gives urinary antiseptic compound
1 \(HCHO\)
2 \(C{H_3}CHO\)
3 \({C_6}{H_5}CHO\)
4 \({C_6}{H_5}C{H_2}CHO\)
Explanation:
\(NH _3\) react differently with all this reactant as follow. \(\text { (i) } 6 HCHO +4 NH _3 \rightarrow\left( CH _2\right)_6 N _4+6 H _2 O\) \((ii)\) \(CH _3 CHO + NH _3 \rightarrow CH _3 CH ( OH ) NH _2\) \(\text { (iii) } C _6 H _5 CHO + NH _3 \rightarrow C _6 H _5- CH \left( NCHC _6 H _5\right)_2 \text { }\)
