28837
The oxidation number of cobalt in \(K[Co{(CO)_4}]\) is
1 \(1\)
2 \(-1\)
3 \(3\)
4 \(-3\)
Explanation:
(b) \(1 \times ( + 1) + x + 4 \times (0) = 0\) \(1 + x = 0 \Rightarrow x = - 1\) Oxidation number of Co \( = - 1\).
COORDINATION COMPOUNDS
28838
The complex salt can be made by the combination of \({[C{o^{III}}{(N{H_3})_5}Cl]^x}\) with:
1 \(PO_4^{3 - }\)
2 \(C{l^ - }\)
3 \(2C{l^ - }\)
4 \(2{K^ + }\)
Explanation:
(c) In the complex ion \({[C{o^{{\text{(III)}}}}{(N{H_3})_5}Cl]^x}\), charge on the complex ion \(x = 3 + (0 \times 5) + ( - 1)\) \(x = 3 - 1 = 2\) Hence, it will combine with that species which have \(-2\) charge to produce a neutral complex salt. So it will combine with \(2C{l^ - }\) to produce \([Co{(N{H_3})_5}Cl]\,C{l_2}\) complex.
COORDINATION COMPOUNDS
28839
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour (Atomic number : \(Zn = 30\), \(Cr = 24\), \(Co = 27\), \(Ni = 28\))
1 \({[Zn{(N{H_3})_6}]^{2 + }}\)
2 \({[Cr{(N{H_3})_6}]^{3 + }}\)
3 \({[Co{(N{H_3})_6}]^{3 + }}\)
4 \({[Ni{(N{H_3})_6}]^{2 + }}\)
Explanation:
(c) \({[Co{(N{H_3})_6}]^{3 + }}\) \(O. N.\) of \(Co = + 3\) \(C{o^{3 + }}({d^6})\) \({[Co{(N{H_3})_6}]^{3 + }}\) Due to paired \({e^ - }\) it is diamagnetic.
28837
The oxidation number of cobalt in \(K[Co{(CO)_4}]\) is
1 \(1\)
2 \(-1\)
3 \(3\)
4 \(-3\)
Explanation:
(b) \(1 \times ( + 1) + x + 4 \times (0) = 0\) \(1 + x = 0 \Rightarrow x = - 1\) Oxidation number of Co \( = - 1\).
COORDINATION COMPOUNDS
28838
The complex salt can be made by the combination of \({[C{o^{III}}{(N{H_3})_5}Cl]^x}\) with:
1 \(PO_4^{3 - }\)
2 \(C{l^ - }\)
3 \(2C{l^ - }\)
4 \(2{K^ + }\)
Explanation:
(c) In the complex ion \({[C{o^{{\text{(III)}}}}{(N{H_3})_5}Cl]^x}\), charge on the complex ion \(x = 3 + (0 \times 5) + ( - 1)\) \(x = 3 - 1 = 2\) Hence, it will combine with that species which have \(-2\) charge to produce a neutral complex salt. So it will combine with \(2C{l^ - }\) to produce \([Co{(N{H_3})_5}Cl]\,C{l_2}\) complex.
COORDINATION COMPOUNDS
28839
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour (Atomic number : \(Zn = 30\), \(Cr = 24\), \(Co = 27\), \(Ni = 28\))
1 \({[Zn{(N{H_3})_6}]^{2 + }}\)
2 \({[Cr{(N{H_3})_6}]^{3 + }}\)
3 \({[Co{(N{H_3})_6}]^{3 + }}\)
4 \({[Ni{(N{H_3})_6}]^{2 + }}\)
Explanation:
(c) \({[Co{(N{H_3})_6}]^{3 + }}\) \(O. N.\) of \(Co = + 3\) \(C{o^{3 + }}({d^6})\) \({[Co{(N{H_3})_6}]^{3 + }}\) Due to paired \({e^ - }\) it is diamagnetic.
28837
The oxidation number of cobalt in \(K[Co{(CO)_4}]\) is
1 \(1\)
2 \(-1\)
3 \(3\)
4 \(-3\)
Explanation:
(b) \(1 \times ( + 1) + x + 4 \times (0) = 0\) \(1 + x = 0 \Rightarrow x = - 1\) Oxidation number of Co \( = - 1\).
COORDINATION COMPOUNDS
28838
The complex salt can be made by the combination of \({[C{o^{III}}{(N{H_3})_5}Cl]^x}\) with:
1 \(PO_4^{3 - }\)
2 \(C{l^ - }\)
3 \(2C{l^ - }\)
4 \(2{K^ + }\)
Explanation:
(c) In the complex ion \({[C{o^{{\text{(III)}}}}{(N{H_3})_5}Cl]^x}\), charge on the complex ion \(x = 3 + (0 \times 5) + ( - 1)\) \(x = 3 - 1 = 2\) Hence, it will combine with that species which have \(-2\) charge to produce a neutral complex salt. So it will combine with \(2C{l^ - }\) to produce \([Co{(N{H_3})_5}Cl]\,C{l_2}\) complex.
COORDINATION COMPOUNDS
28839
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour (Atomic number : \(Zn = 30\), \(Cr = 24\), \(Co = 27\), \(Ni = 28\))
1 \({[Zn{(N{H_3})_6}]^{2 + }}\)
2 \({[Cr{(N{H_3})_6}]^{3 + }}\)
3 \({[Co{(N{H_3})_6}]^{3 + }}\)
4 \({[Ni{(N{H_3})_6}]^{2 + }}\)
Explanation:
(c) \({[Co{(N{H_3})_6}]^{3 + }}\) \(O. N.\) of \(Co = + 3\) \(C{o^{3 + }}({d^6})\) \({[Co{(N{H_3})_6}]^{3 + }}\) Due to paired \({e^ - }\) it is diamagnetic.
28837
The oxidation number of cobalt in \(K[Co{(CO)_4}]\) is
1 \(1\)
2 \(-1\)
3 \(3\)
4 \(-3\)
Explanation:
(b) \(1 \times ( + 1) + x + 4 \times (0) = 0\) \(1 + x = 0 \Rightarrow x = - 1\) Oxidation number of Co \( = - 1\).
COORDINATION COMPOUNDS
28838
The complex salt can be made by the combination of \({[C{o^{III}}{(N{H_3})_5}Cl]^x}\) with:
1 \(PO_4^{3 - }\)
2 \(C{l^ - }\)
3 \(2C{l^ - }\)
4 \(2{K^ + }\)
Explanation:
(c) In the complex ion \({[C{o^{{\text{(III)}}}}{(N{H_3})_5}Cl]^x}\), charge on the complex ion \(x = 3 + (0 \times 5) + ( - 1)\) \(x = 3 - 1 = 2\) Hence, it will combine with that species which have \(-2\) charge to produce a neutral complex salt. So it will combine with \(2C{l^ - }\) to produce \([Co{(N{H_3})_5}Cl]\,C{l_2}\) complex.
COORDINATION COMPOUNDS
28839
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour (Atomic number : \(Zn = 30\), \(Cr = 24\), \(Co = 27\), \(Ni = 28\))
1 \({[Zn{(N{H_3})_6}]^{2 + }}\)
2 \({[Cr{(N{H_3})_6}]^{3 + }}\)
3 \({[Co{(N{H_3})_6}]^{3 + }}\)
4 \({[Ni{(N{H_3})_6}]^{2 + }}\)
Explanation:
(c) \({[Co{(N{H_3})_6}]^{3 + }}\) \(O. N.\) of \(Co = + 3\) \(C{o^{3 + }}({d^6})\) \({[Co{(N{H_3})_6}]^{3 + }}\) Due to paired \({e^ - }\) it is diamagnetic.
