28700
Which of the following compounds is colourless
1 \(C{u_2}{(C{H_3}COO)_4}.2{H_2}O\)
2 \(C{u_2}C{l_2}\)
3 \(CuS{O_4}.5{H_2}O\)
4 \([Cu{(N{H_3})_4}]S{O_4}.4{H_2}O\)
Explanation:
(b) The anhydrous complex of \(C{u^ + }\) do not involve \(d-d\) transition and are thus colourless.
COORDINATION COMPOUNDS
28701
The type of magnetism exhibited by \({\left[ {Mn{{\left( {{H_2}O} \right)}_6}} \right]^{2 + }}\) ion is
1 Paramagnetism
2 Diamagnetism
3 Both \( (a) \) and \( (b) \)
4 None of these
Explanation:
(a) In presence of \({H_2}O\) which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.
COORDINATION COMPOUNDS
28702
The number of isomers possible for square planar complex \({K_2}\left[ {PdClB{r_2}(SCN)} \right]\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(6\)
Explanation:
(c) Geometrical isomers (cis and trans) and linkage isomers (\(-SCN\) and \( -NCS\)).
COORDINATION COMPOUNDS
28703
The number of unpaired electrons in \(Ni{(CO)_4}\) is
1 \(0\)
2 \(1\)
3 \(3\)
4 \(5\)
Explanation:
(a) Due to presence of strong ligand all the \({e^ - }\) get paired. So no. of unpaired electrons are \( 0\).
COORDINATION COMPOUNDS
28704
If the magnetic moment of \({\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}\) is zero, then the number of unpaired electrons will be
28700
Which of the following compounds is colourless
1 \(C{u_2}{(C{H_3}COO)_4}.2{H_2}O\)
2 \(C{u_2}C{l_2}\)
3 \(CuS{O_4}.5{H_2}O\)
4 \([Cu{(N{H_3})_4}]S{O_4}.4{H_2}O\)
Explanation:
(b) The anhydrous complex of \(C{u^ + }\) do not involve \(d-d\) transition and are thus colourless.
COORDINATION COMPOUNDS
28701
The type of magnetism exhibited by \({\left[ {Mn{{\left( {{H_2}O} \right)}_6}} \right]^{2 + }}\) ion is
1 Paramagnetism
2 Diamagnetism
3 Both \( (a) \) and \( (b) \)
4 None of these
Explanation:
(a) In presence of \({H_2}O\) which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.
COORDINATION COMPOUNDS
28702
The number of isomers possible for square planar complex \({K_2}\left[ {PdClB{r_2}(SCN)} \right]\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(6\)
Explanation:
(c) Geometrical isomers (cis and trans) and linkage isomers (\(-SCN\) and \( -NCS\)).
COORDINATION COMPOUNDS
28703
The number of unpaired electrons in \(Ni{(CO)_4}\) is
1 \(0\)
2 \(1\)
3 \(3\)
4 \(5\)
Explanation:
(a) Due to presence of strong ligand all the \({e^ - }\) get paired. So no. of unpaired electrons are \( 0\).
COORDINATION COMPOUNDS
28704
If the magnetic moment of \({\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}\) is zero, then the number of unpaired electrons will be
NEET Test Series from KOTA - 10 Papers In MS WORD
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COORDINATION COMPOUNDS
28700
Which of the following compounds is colourless
1 \(C{u_2}{(C{H_3}COO)_4}.2{H_2}O\)
2 \(C{u_2}C{l_2}\)
3 \(CuS{O_4}.5{H_2}O\)
4 \([Cu{(N{H_3})_4}]S{O_4}.4{H_2}O\)
Explanation:
(b) The anhydrous complex of \(C{u^ + }\) do not involve \(d-d\) transition and are thus colourless.
COORDINATION COMPOUNDS
28701
The type of magnetism exhibited by \({\left[ {Mn{{\left( {{H_2}O} \right)}_6}} \right]^{2 + }}\) ion is
1 Paramagnetism
2 Diamagnetism
3 Both \( (a) \) and \( (b) \)
4 None of these
Explanation:
(a) In presence of \({H_2}O\) which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.
COORDINATION COMPOUNDS
28702
The number of isomers possible for square planar complex \({K_2}\left[ {PdClB{r_2}(SCN)} \right]\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(6\)
Explanation:
(c) Geometrical isomers (cis and trans) and linkage isomers (\(-SCN\) and \( -NCS\)).
COORDINATION COMPOUNDS
28703
The number of unpaired electrons in \(Ni{(CO)_4}\) is
1 \(0\)
2 \(1\)
3 \(3\)
4 \(5\)
Explanation:
(a) Due to presence of strong ligand all the \({e^ - }\) get paired. So no. of unpaired electrons are \( 0\).
COORDINATION COMPOUNDS
28704
If the magnetic moment of \({\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}\) is zero, then the number of unpaired electrons will be
28700
Which of the following compounds is colourless
1 \(C{u_2}{(C{H_3}COO)_4}.2{H_2}O\)
2 \(C{u_2}C{l_2}\)
3 \(CuS{O_4}.5{H_2}O\)
4 \([Cu{(N{H_3})_4}]S{O_4}.4{H_2}O\)
Explanation:
(b) The anhydrous complex of \(C{u^ + }\) do not involve \(d-d\) transition and are thus colourless.
COORDINATION COMPOUNDS
28701
The type of magnetism exhibited by \({\left[ {Mn{{\left( {{H_2}O} \right)}_6}} \right]^{2 + }}\) ion is
1 Paramagnetism
2 Diamagnetism
3 Both \( (a) \) and \( (b) \)
4 None of these
Explanation:
(a) In presence of \({H_2}O\) which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.
COORDINATION COMPOUNDS
28702
The number of isomers possible for square planar complex \({K_2}\left[ {PdClB{r_2}(SCN)} \right]\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(6\)
Explanation:
(c) Geometrical isomers (cis and trans) and linkage isomers (\(-SCN\) and \( -NCS\)).
COORDINATION COMPOUNDS
28703
The number of unpaired electrons in \(Ni{(CO)_4}\) is
1 \(0\)
2 \(1\)
3 \(3\)
4 \(5\)
Explanation:
(a) Due to presence of strong ligand all the \({e^ - }\) get paired. So no. of unpaired electrons are \( 0\).
COORDINATION COMPOUNDS
28704
If the magnetic moment of \({\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}\) is zero, then the number of unpaired electrons will be
28700
Which of the following compounds is colourless
1 \(C{u_2}{(C{H_3}COO)_4}.2{H_2}O\)
2 \(C{u_2}C{l_2}\)
3 \(CuS{O_4}.5{H_2}O\)
4 \([Cu{(N{H_3})_4}]S{O_4}.4{H_2}O\)
Explanation:
(b) The anhydrous complex of \(C{u^ + }\) do not involve \(d-d\) transition and are thus colourless.
COORDINATION COMPOUNDS
28701
The type of magnetism exhibited by \({\left[ {Mn{{\left( {{H_2}O} \right)}_6}} \right]^{2 + }}\) ion is
1 Paramagnetism
2 Diamagnetism
3 Both \( (a) \) and \( (b) \)
4 None of these
Explanation:
(a) In presence of \({H_2}O\) which is a weak ligand no pairing occurs which results in unpaired electrons left in the compound, due to which it shows paramagnetism.
COORDINATION COMPOUNDS
28702
The number of isomers possible for square planar complex \({K_2}\left[ {PdClB{r_2}(SCN)} \right]\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(6\)
Explanation:
(c) Geometrical isomers (cis and trans) and linkage isomers (\(-SCN\) and \( -NCS\)).
COORDINATION COMPOUNDS
28703
The number of unpaired electrons in \(Ni{(CO)_4}\) is
1 \(0\)
2 \(1\)
3 \(3\)
4 \(5\)
Explanation:
(a) Due to presence of strong ligand all the \({e^ - }\) get paired. So no. of unpaired electrons are \( 0\).
COORDINATION COMPOUNDS
28704
If the magnetic moment of \({\left[ {Ag{{\left( {CN} \right)}_2}} \right]^{ - 1}}\) is zero, then the number of unpaired electrons will be
