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Hydrogen

27618 Hardness of water is due to presence of salts of

1

N a^{+}

and

K^{+}

2

C a^{2 +}

and

M g^{2 +}

3

C a^{2 +}

and

K^{+}

4

C a^{2 +}

and

N a^{+}

Explanation:

(b) Hardness of water is due to the presence of bicarbonates, chlorides and sulphates of $C a$ and $M g$ on it. These $C a^{2 +}$ and $M g^{2 +}$ ions react with the anions of fatty acids present in soaps to form curdy white precipitates. As a result, hard water does not produce lather with soap immediately.

Hydrogen

27619 In which of the following reaction hydrogen peroxide is a reducing agent

1

2 F e C l_{2} + 2 H C l + H_{2} O_{2} \to 2 F e C l_{3} + 2 H_{2} O

2

C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}

3

2 H I + H_{2} O_{2} \to 2 H_{2} O + I_{2}

4

H_{2} S O_{3} + H_{2} O_{2} \to H_{2} S O_{4} + H_{2} O

Explanation:

(b) $\underset{0}{C l_{2}} + H_{2} O_{2} \to \underset{- 1}{2 H C l} + O_{2}$
In this reaction $H_{2} O_{2}$ works as reducing agent

Hydrogen

27678 Saline hydrides react explosively with water, such fires can be extinguished by

1 Water

2 Carbon dioxide

3 Sand

4 None of these

Explanation:

(c) Fire due to action of water on saline hydrides cannot be extinguished with water or $C O_{2}$ . These hydrides can reduce $C O_{2}$ at high temperature to produce $O_{2}$ .

Hydrogen

27679 Metals of groups $7, 8$ and $9$ do not form metallic hydrides. This is termed as

1 Hydride gap

2 Hydride shift

3 Anhydride

4 Dehydride

Explanation:

Metals of groups $7, 8$ and $9$ do not from metallic hydrides. This is termed as hydride gap.

Hydrogen

27618 Hardness of water is due to presence of salts of

1

N a^{+}

and

K^{+}

2

C a^{2 +}

and

M g^{2 +}

3

C a^{2 +}

and

K^{+}

4

C a^{2 +}

and

N a^{+}

Explanation:

(b) Hardness of water is due to the presence of bicarbonates, chlorides and sulphates of $C a$ and $M g$ on it. These $C a^{2 +}$ and $M g^{2 +}$ ions react with the anions of fatty acids present in soaps to form curdy white precipitates. As a result, hard water does not produce lather with soap immediately.

Hydrogen

27619 In which of the following reaction hydrogen peroxide is a reducing agent

1

2 F e C l_{2} + 2 H C l + H_{2} O_{2} \to 2 F e C l_{3} + 2 H_{2} O

2

C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}

3

2 H I + H_{2} O_{2} \to 2 H_{2} O + I_{2}

4

H_{2} S O_{3} + H_{2} O_{2} \to H_{2} S O_{4} + H_{2} O

Explanation:

(b) $\underset{0}{C l_{2}} + H_{2} O_{2} \to \underset{- 1}{2 H C l} + O_{2}$
In this reaction $H_{2} O_{2}$ works as reducing agent

Hydrogen

27678 Saline hydrides react explosively with water, such fires can be extinguished by

1 Water

2 Carbon dioxide

3 Sand

4 None of these

Explanation:

(c) Fire due to action of water on saline hydrides cannot be extinguished with water or $C O_{2}$ . These hydrides can reduce $C O_{2}$ at high temperature to produce $O_{2}$ .

Hydrogen

27679 Metals of groups $7, 8$ and $9$ do not form metallic hydrides. This is termed as

1 Hydride gap

2 Hydride shift

3 Anhydride

4 Dehydride

Explanation:

Metals of groups $7, 8$ and $9$ do not from metallic hydrides. This is termed as hydride gap.

Hydrogen

27618 Hardness of water is due to presence of salts of

1

N a^{+}

and

K^{+}

2

C a^{2 +}

and

M g^{2 +}

3

C a^{2 +}

and

K^{+}

4

C a^{2 +}

and

N a^{+}

Explanation:

(b) Hardness of water is due to the presence of bicarbonates, chlorides and sulphates of $C a$ and $M g$ on it. These $C a^{2 +}$ and $M g^{2 +}$ ions react with the anions of fatty acids present in soaps to form curdy white precipitates. As a result, hard water does not produce lather with soap immediately.

Hydrogen

27619 In which of the following reaction hydrogen peroxide is a reducing agent

1

2 F e C l_{2} + 2 H C l + H_{2} O_{2} \to 2 F e C l_{3} + 2 H_{2} O

2

C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}

3

2 H I + H_{2} O_{2} \to 2 H_{2} O + I_{2}

4

H_{2} S O_{3} + H_{2} O_{2} \to H_{2} S O_{4} + H_{2} O

Explanation:

(b) $\underset{0}{C l_{2}} + H_{2} O_{2} \to \underset{- 1}{2 H C l} + O_{2}$
In this reaction $H_{2} O_{2}$ works as reducing agent

Hydrogen

27678 Saline hydrides react explosively with water, such fires can be extinguished by

1 Water

2 Carbon dioxide

3 Sand

4 None of these

Explanation:

(c) Fire due to action of water on saline hydrides cannot be extinguished with water or $C O_{2}$ . These hydrides can reduce $C O_{2}$ at high temperature to produce $O_{2}$ .

Hydrogen

27679 Metals of groups $7, 8$ and $9$ do not form metallic hydrides. This is termed as

1 Hydride gap

2 Hydride shift

3 Anhydride

4 Dehydride

Explanation:

Metals of groups $7, 8$ and $9$ do not from metallic hydrides. This is termed as hydride gap.

Hydrogen

27618 Hardness of water is due to presence of salts of

1

N a^{+}

and

K^{+}

2

C a^{2 +}

and

M g^{2 +}

3

C a^{2 +}

and

K^{+}

4

C a^{2 +}

and

N a^{+}

Explanation:

(b) Hardness of water is due to the presence of bicarbonates, chlorides and sulphates of $C a$ and $M g$ on it. These $C a^{2 +}$ and $M g^{2 +}$ ions react with the anions of fatty acids present in soaps to form curdy white precipitates. As a result, hard water does not produce lather with soap immediately.

Hydrogen

27619 In which of the following reaction hydrogen peroxide is a reducing agent

1

2 F e C l_{2} + 2 H C l + H_{2} O_{2} \to 2 F e C l_{3} + 2 H_{2} O

2

C l_{2} + H_{2} O_{2} \to 2 H C l + O_{2}

3

2 H I + H_{2} O_{2} \to 2 H_{2} O + I_{2}

4

H_{2} S O_{3} + H_{2} O_{2} \to H_{2} S O_{4} + H_{2} O

Explanation:

(b) $\underset{0}{C l_{2}} + H_{2} O_{2} \to \underset{- 1}{2 H C l} + O_{2}$
In this reaction $H_{2} O_{2}$ works as reducing agent

Hydrogen

27678 Saline hydrides react explosively with water, such fires can be extinguished by

1 Water

2 Carbon dioxide

3 Sand

4 None of these

Explanation:

(c) Fire due to action of water on saline hydrides cannot be extinguished with water or $C O_{2}$ . These hydrides can reduce $C O_{2}$ at high temperature to produce $O_{2}$ .

Hydrogen

27679 Metals of groups $7, 8$ and $9$ do not form metallic hydrides. This is termed as

1 Hydride gap

2 Hydride shift

3 Anhydride

4 Dehydride

Explanation:

Metals of groups $7, 8$ and $9$ do not from metallic hydrides. This is termed as hydride gap.

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