11955
The number of electrons shared by each outermost shell of \({N_2}\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(5\)
Explanation:
(b) Each nitrogen share \(3\) electrons to form triple bond.
Chemical Bonding and Molecular Structure
11956
Which of the following substances when dissolved in water will give a solution that does not conduct electricity
1 Hydrogen chloride
2 Potassium hydroxide
3 Sodium acetate
4 Urea
Explanation:
(d) Urea solution does not conduct electricity because it is a covalent compound.
Chemical Bonding and Molecular Structure
11957
Which of the following atoms has minimum covalent radius
1 \(B\)
2 \(C\)
3 \(N\)
4 \(Si\)
Explanation:
As we move along a period radius decreases and as we move down the group, radius increases. Hence, \(B (5)\,>\, C (6)\,>\, N (7)\). Also, \(\left( r ^{ n } \propto \frac{1}{Z}\right.\) along a period)
Chemical Bonding and Molecular Structure
11958
Boron form covalent compound due to
1 Small size
2 Higher ionization energy
3 Lower ionization energy
4 Both \((a)\) and \((b)\)
Explanation:
(d) Due to the small size and higher ionization energy, boron forms covalent compound.
11955
The number of electrons shared by each outermost shell of \({N_2}\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(5\)
Explanation:
(b) Each nitrogen share \(3\) electrons to form triple bond.
Chemical Bonding and Molecular Structure
11956
Which of the following substances when dissolved in water will give a solution that does not conduct electricity
1 Hydrogen chloride
2 Potassium hydroxide
3 Sodium acetate
4 Urea
Explanation:
(d) Urea solution does not conduct electricity because it is a covalent compound.
Chemical Bonding and Molecular Structure
11957
Which of the following atoms has minimum covalent radius
1 \(B\)
2 \(C\)
3 \(N\)
4 \(Si\)
Explanation:
As we move along a period radius decreases and as we move down the group, radius increases. Hence, \(B (5)\,>\, C (6)\,>\, N (7)\). Also, \(\left( r ^{ n } \propto \frac{1}{Z}\right.\) along a period)
Chemical Bonding and Molecular Structure
11958
Boron form covalent compound due to
1 Small size
2 Higher ionization energy
3 Lower ionization energy
4 Both \((a)\) and \((b)\)
Explanation:
(d) Due to the small size and higher ionization energy, boron forms covalent compound.
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Chemical Bonding and Molecular Structure
11955
The number of electrons shared by each outermost shell of \({N_2}\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(5\)
Explanation:
(b) Each nitrogen share \(3\) electrons to form triple bond.
Chemical Bonding and Molecular Structure
11956
Which of the following substances when dissolved in water will give a solution that does not conduct electricity
1 Hydrogen chloride
2 Potassium hydroxide
3 Sodium acetate
4 Urea
Explanation:
(d) Urea solution does not conduct electricity because it is a covalent compound.
Chemical Bonding and Molecular Structure
11957
Which of the following atoms has minimum covalent radius
1 \(B\)
2 \(C\)
3 \(N\)
4 \(Si\)
Explanation:
As we move along a period radius decreases and as we move down the group, radius increases. Hence, \(B (5)\,>\, C (6)\,>\, N (7)\). Also, \(\left( r ^{ n } \propto \frac{1}{Z}\right.\) along a period)
Chemical Bonding and Molecular Structure
11958
Boron form covalent compound due to
1 Small size
2 Higher ionization energy
3 Lower ionization energy
4 Both \((a)\) and \((b)\)
Explanation:
(d) Due to the small size and higher ionization energy, boron forms covalent compound.
11955
The number of electrons shared by each outermost shell of \({N_2}\) is
1 \(2\)
2 \(3\)
3 \(4\)
4 \(5\)
Explanation:
(b) Each nitrogen share \(3\) electrons to form triple bond.
Chemical Bonding and Molecular Structure
11956
Which of the following substances when dissolved in water will give a solution that does not conduct electricity
1 Hydrogen chloride
2 Potassium hydroxide
3 Sodium acetate
4 Urea
Explanation:
(d) Urea solution does not conduct electricity because it is a covalent compound.
Chemical Bonding and Molecular Structure
11957
Which of the following atoms has minimum covalent radius
1 \(B\)
2 \(C\)
3 \(N\)
4 \(Si\)
Explanation:
As we move along a period radius decreases and as we move down the group, radius increases. Hence, \(B (5)\,>\, C (6)\,>\, N (7)\). Also, \(\left( r ^{ n } \propto \frac{1}{Z}\right.\) along a period)
Chemical Bonding and Molecular Structure
11958
Boron form covalent compound due to
1 Small size
2 Higher ionization energy
3 Lower ionization energy
4 Both \((a)\) and \((b)\)
Explanation:
(d) Due to the small size and higher ionization energy, boron forms covalent compound.