(a) Electrovalent compounds generally have high \(m.pt\) and high \(b.pt\) due to stronger coulombic forces of attractions.
Chemical Bonding and Molecular Structure
11858
Many ionic crystals dissolve in water because
1 Water is an amphiprotic solvent
2 Water is a high boiling liquid
3 The process is accompanied by a positive heat of solution
4 Water decreases the interionic attraction in the crystal lattice due to solvation
Explanation:
(d) Water is a polar solvent so it decreases the interionic attraction in the crystal lattice due to solvation.
Chemical Bonding and Molecular Structure
11859
Chloride of metal is \(MC{l_2}\). The formula of its phosphate will be
1 \({M_2}P{O_4}\)
2 \({M_3}{\left( {P{O_4}} \right)_2}\)
3 \({M_2}{\left( {P{O_4}} \right)_3}\)
4 \(MP{O_4}\)
Explanation:
(b) Since the chloride of a metal is \(MC{l_2}\) therefore metal \(‘M’\) must be divalent i.e. \({M^{2 + }}\). As a result the formula of its phosphate is \({M_3}{(P{O_4})_2}\).
Chemical Bonding and Molecular Structure
11860
The phosphate of a metal has the formula \(MP{O_4}\). The formula of its nitrate will be
1 \(MN{O_3}\)
2 \({M_2}{\left( {N{O_3}} \right)_2}\)
3 \(M{\left( {N{O_3}} \right)_2}\)
4 \(M{\left( {N{O_3}} \right)_3}\)
Explanation:
(d) In \(MP{O_4}\) the oxidation state of \(M\) is \(+3.\) Hence, the formula of nitrate is \(M{(\,N{O_3})_3}.\)
Chemical Bonding and Molecular Structure
11861
In the transition of \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the
1 Number of valency electrons
2 Atomic weight
3 Atomic number
4 Equivalent weight
Explanation:
(a) Ion is formed by gaining or losing electrons. To form cation electron are lost from the valency shell, so \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the no. of valency electron.
(a) Electrovalent compounds generally have high \(m.pt\) and high \(b.pt\) due to stronger coulombic forces of attractions.
Chemical Bonding and Molecular Structure
11858
Many ionic crystals dissolve in water because
1 Water is an amphiprotic solvent
2 Water is a high boiling liquid
3 The process is accompanied by a positive heat of solution
4 Water decreases the interionic attraction in the crystal lattice due to solvation
Explanation:
(d) Water is a polar solvent so it decreases the interionic attraction in the crystal lattice due to solvation.
Chemical Bonding and Molecular Structure
11859
Chloride of metal is \(MC{l_2}\). The formula of its phosphate will be
1 \({M_2}P{O_4}\)
2 \({M_3}{\left( {P{O_4}} \right)_2}\)
3 \({M_2}{\left( {P{O_4}} \right)_3}\)
4 \(MP{O_4}\)
Explanation:
(b) Since the chloride of a metal is \(MC{l_2}\) therefore metal \(‘M’\) must be divalent i.e. \({M^{2 + }}\). As a result the formula of its phosphate is \({M_3}{(P{O_4})_2}\).
Chemical Bonding and Molecular Structure
11860
The phosphate of a metal has the formula \(MP{O_4}\). The formula of its nitrate will be
1 \(MN{O_3}\)
2 \({M_2}{\left( {N{O_3}} \right)_2}\)
3 \(M{\left( {N{O_3}} \right)_2}\)
4 \(M{\left( {N{O_3}} \right)_3}\)
Explanation:
(d) In \(MP{O_4}\) the oxidation state of \(M\) is \(+3.\) Hence, the formula of nitrate is \(M{(\,N{O_3})_3}.\)
Chemical Bonding and Molecular Structure
11861
In the transition of \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the
1 Number of valency electrons
2 Atomic weight
3 Atomic number
4 Equivalent weight
Explanation:
(a) Ion is formed by gaining or losing electrons. To form cation electron are lost from the valency shell, so \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the no. of valency electron.
(a) Electrovalent compounds generally have high \(m.pt\) and high \(b.pt\) due to stronger coulombic forces of attractions.
Chemical Bonding and Molecular Structure
11858
Many ionic crystals dissolve in water because
1 Water is an amphiprotic solvent
2 Water is a high boiling liquid
3 The process is accompanied by a positive heat of solution
4 Water decreases the interionic attraction in the crystal lattice due to solvation
Explanation:
(d) Water is a polar solvent so it decreases the interionic attraction in the crystal lattice due to solvation.
Chemical Bonding and Molecular Structure
11859
Chloride of metal is \(MC{l_2}\). The formula of its phosphate will be
1 \({M_2}P{O_4}\)
2 \({M_3}{\left( {P{O_4}} \right)_2}\)
3 \({M_2}{\left( {P{O_4}} \right)_3}\)
4 \(MP{O_4}\)
Explanation:
(b) Since the chloride of a metal is \(MC{l_2}\) therefore metal \(‘M’\) must be divalent i.e. \({M^{2 + }}\). As a result the formula of its phosphate is \({M_3}{(P{O_4})_2}\).
Chemical Bonding and Molecular Structure
11860
The phosphate of a metal has the formula \(MP{O_4}\). The formula of its nitrate will be
1 \(MN{O_3}\)
2 \({M_2}{\left( {N{O_3}} \right)_2}\)
3 \(M{\left( {N{O_3}} \right)_2}\)
4 \(M{\left( {N{O_3}} \right)_3}\)
Explanation:
(d) In \(MP{O_4}\) the oxidation state of \(M\) is \(+3.\) Hence, the formula of nitrate is \(M{(\,N{O_3})_3}.\)
Chemical Bonding and Molecular Structure
11861
In the transition of \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the
1 Number of valency electrons
2 Atomic weight
3 Atomic number
4 Equivalent weight
Explanation:
(a) Ion is formed by gaining or losing electrons. To form cation electron are lost from the valency shell, so \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the no. of valency electron.
(a) Electrovalent compounds generally have high \(m.pt\) and high \(b.pt\) due to stronger coulombic forces of attractions.
Chemical Bonding and Molecular Structure
11858
Many ionic crystals dissolve in water because
1 Water is an amphiprotic solvent
2 Water is a high boiling liquid
3 The process is accompanied by a positive heat of solution
4 Water decreases the interionic attraction in the crystal lattice due to solvation
Explanation:
(d) Water is a polar solvent so it decreases the interionic attraction in the crystal lattice due to solvation.
Chemical Bonding and Molecular Structure
11859
Chloride of metal is \(MC{l_2}\). The formula of its phosphate will be
1 \({M_2}P{O_4}\)
2 \({M_3}{\left( {P{O_4}} \right)_2}\)
3 \({M_2}{\left( {P{O_4}} \right)_3}\)
4 \(MP{O_4}\)
Explanation:
(b) Since the chloride of a metal is \(MC{l_2}\) therefore metal \(‘M’\) must be divalent i.e. \({M^{2 + }}\). As a result the formula of its phosphate is \({M_3}{(P{O_4})_2}\).
Chemical Bonding and Molecular Structure
11860
The phosphate of a metal has the formula \(MP{O_4}\). The formula of its nitrate will be
1 \(MN{O_3}\)
2 \({M_2}{\left( {N{O_3}} \right)_2}\)
3 \(M{\left( {N{O_3}} \right)_2}\)
4 \(M{\left( {N{O_3}} \right)_3}\)
Explanation:
(d) In \(MP{O_4}\) the oxidation state of \(M\) is \(+3.\) Hence, the formula of nitrate is \(M{(\,N{O_3})_3}.\)
Chemical Bonding and Molecular Structure
11861
In the transition of \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the
1 Number of valency electrons
2 Atomic weight
3 Atomic number
4 Equivalent weight
Explanation:
(a) Ion is formed by gaining or losing electrons. To form cation electron are lost from the valency shell, so \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the no. of valency electron.
(a) Electrovalent compounds generally have high \(m.pt\) and high \(b.pt\) due to stronger coulombic forces of attractions.
Chemical Bonding and Molecular Structure
11858
Many ionic crystals dissolve in water because
1 Water is an amphiprotic solvent
2 Water is a high boiling liquid
3 The process is accompanied by a positive heat of solution
4 Water decreases the interionic attraction in the crystal lattice due to solvation
Explanation:
(d) Water is a polar solvent so it decreases the interionic attraction in the crystal lattice due to solvation.
Chemical Bonding and Molecular Structure
11859
Chloride of metal is \(MC{l_2}\). The formula of its phosphate will be
1 \({M_2}P{O_4}\)
2 \({M_3}{\left( {P{O_4}} \right)_2}\)
3 \({M_2}{\left( {P{O_4}} \right)_3}\)
4 \(MP{O_4}\)
Explanation:
(b) Since the chloride of a metal is \(MC{l_2}\) therefore metal \(‘M’\) must be divalent i.e. \({M^{2 + }}\). As a result the formula of its phosphate is \({M_3}{(P{O_4})_2}\).
Chemical Bonding and Molecular Structure
11860
The phosphate of a metal has the formula \(MP{O_4}\). The formula of its nitrate will be
1 \(MN{O_3}\)
2 \({M_2}{\left( {N{O_3}} \right)_2}\)
3 \(M{\left( {N{O_3}} \right)_2}\)
4 \(M{\left( {N{O_3}} \right)_3}\)
Explanation:
(d) In \(MP{O_4}\) the oxidation state of \(M\) is \(+3.\) Hence, the formula of nitrate is \(M{(\,N{O_3})_3}.\)
Chemical Bonding and Molecular Structure
11861
In the transition of \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the
1 Number of valency electrons
2 Atomic weight
3 Atomic number
4 Equivalent weight
Explanation:
(a) Ion is formed by gaining or losing electrons. To form cation electron are lost from the valency shell, so \(Zn\) atoms to \(Z{n^{ + + }}\) ions there is a decrease in the no. of valency electron.
