9711
An element have atomic weight \(40\) and it’s electronic configuration is \(1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}.\) Then its atomic number and number of neutrons will be
1 \(18\) and \(22\)
2 \(22\) and \( 18\)
3 \(26 \) and \(20\)
4 \(40 \) and \(18\)
Explanation:
(a) \(Ar_{18}^{40}\) = atomic number \(18\) and no. of Neutron in case of \(A{r_{22}}\) Neutron = Atomic mass $-$ Atomic number \( = 40 - 18 = 22\)
9711
An element have atomic weight \(40\) and it’s electronic configuration is \(1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}.\) Then its atomic number and number of neutrons will be
1 \(18\) and \(22\)
2 \(22\) and \( 18\)
3 \(26 \) and \(20\)
4 \(40 \) and \(18\)
Explanation:
(a) \(Ar_{18}^{40}\) = atomic number \(18\) and no. of Neutron in case of \(A{r_{22}}\) Neutron = Atomic mass $-$ Atomic number \( = 40 - 18 = 22\)
9711
An element have atomic weight \(40\) and it’s electronic configuration is \(1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}.\) Then its atomic number and number of neutrons will be
1 \(18\) and \(22\)
2 \(22\) and \( 18\)
3 \(26 \) and \(20\)
4 \(40 \) and \(18\)
Explanation:
(a) \(Ar_{18}^{40}\) = atomic number \(18\) and no. of Neutron in case of \(A{r_{22}}\) Neutron = Atomic mass $-$ Atomic number \( = 40 - 18 = 22\)
9711
An element have atomic weight \(40\) and it’s electronic configuration is \(1{s^2}2{s^2}2{p^6}3{s^2}3{p^6}.\) Then its atomic number and number of neutrons will be
1 \(18\) and \(22\)
2 \(22\) and \( 18\)
3 \(26 \) and \(20\)
4 \(40 \) and \(18\)
Explanation:
(a) \(Ar_{18}^{40}\) = atomic number \(18\) and no. of Neutron in case of \(A{r_{22}}\) Neutron = Atomic mass $-$ Atomic number \( = 40 - 18 = 22\)