\(Be ^{2+}\) is isoelectronic with \(Li ^{+}\). Both contain \(2\) electrons. They have an electronic configuration \(Be ^2=1 s ^2= Li ^{+}\). This is equal to the electronic configuration of \(He\).
Structure of Atom
9702
An isostere is
1 \(NO_2^ - \) and \({O_3}\)
2 \(NO_2^ - \) and \(PO_4^{3 - }\)
3 \(C{O_2},\,{N_2}O,\,NO_3^ - \)
4 \(ClO_4^ - \) and \(OC{N^ - }\)
Explanation:
(a) \(NO_2^ - \) and \({O_3}\) are isostere. The number of atoms in these \(( = 3)\) and number of electrons \((24)\) are same.
Structure of Atom
9703
Nitrogen atom has an atomic number of \(7 \) and oxygen has an atomic number \(8.\) The total number of electrons in a nitrate ion will be
1 \(8\)
2 \(16\)
3 \(32\)
4 \(64\)
Explanation:
(c) Number of electrons in nitrogen \( = 7\) and number of electron is oxygen \( = 8 \) we know that formula of nitrate ion is \(NO_3^ - \) we also know that number of electron \(= (1 × \) Number of electrons in nitrogen) \(+ (3 × \) number of electrons in oxygen) \(+ 1\) \(= (1 × 7) + (3 × 8) + 1 = 32.\)
Structure of Atom
9704
If molecular mass and atomic mass of sulphur are \(256\) and \(32\) respectively, its atomicity is
\(Be ^{2+}\) is isoelectronic with \(Li ^{+}\). Both contain \(2\) electrons. They have an electronic configuration \(Be ^2=1 s ^2= Li ^{+}\). This is equal to the electronic configuration of \(He\).
Structure of Atom
9702
An isostere is
1 \(NO_2^ - \) and \({O_3}\)
2 \(NO_2^ - \) and \(PO_4^{3 - }\)
3 \(C{O_2},\,{N_2}O,\,NO_3^ - \)
4 \(ClO_4^ - \) and \(OC{N^ - }\)
Explanation:
(a) \(NO_2^ - \) and \({O_3}\) are isostere. The number of atoms in these \(( = 3)\) and number of electrons \((24)\) are same.
Structure of Atom
9703
Nitrogen atom has an atomic number of \(7 \) and oxygen has an atomic number \(8.\) The total number of electrons in a nitrate ion will be
1 \(8\)
2 \(16\)
3 \(32\)
4 \(64\)
Explanation:
(c) Number of electrons in nitrogen \( = 7\) and number of electron is oxygen \( = 8 \) we know that formula of nitrate ion is \(NO_3^ - \) we also know that number of electron \(= (1 × \) Number of electrons in nitrogen) \(+ (3 × \) number of electrons in oxygen) \(+ 1\) \(= (1 × 7) + (3 × 8) + 1 = 32.\)
Structure of Atom
9704
If molecular mass and atomic mass of sulphur are \(256\) and \(32\) respectively, its atomicity is
\(Be ^{2+}\) is isoelectronic with \(Li ^{+}\). Both contain \(2\) electrons. They have an electronic configuration \(Be ^2=1 s ^2= Li ^{+}\). This is equal to the electronic configuration of \(He\).
Structure of Atom
9702
An isostere is
1 \(NO_2^ - \) and \({O_3}\)
2 \(NO_2^ - \) and \(PO_4^{3 - }\)
3 \(C{O_2},\,{N_2}O,\,NO_3^ - \)
4 \(ClO_4^ - \) and \(OC{N^ - }\)
Explanation:
(a) \(NO_2^ - \) and \({O_3}\) are isostere. The number of atoms in these \(( = 3)\) and number of electrons \((24)\) are same.
Structure of Atom
9703
Nitrogen atom has an atomic number of \(7 \) and oxygen has an atomic number \(8.\) The total number of electrons in a nitrate ion will be
1 \(8\)
2 \(16\)
3 \(32\)
4 \(64\)
Explanation:
(c) Number of electrons in nitrogen \( = 7\) and number of electron is oxygen \( = 8 \) we know that formula of nitrate ion is \(NO_3^ - \) we also know that number of electron \(= (1 × \) Number of electrons in nitrogen) \(+ (3 × \) number of electrons in oxygen) \(+ 1\) \(= (1 × 7) + (3 × 8) + 1 = 32.\)
Structure of Atom
9704
If molecular mass and atomic mass of sulphur are \(256\) and \(32\) respectively, its atomicity is
\(Be ^{2+}\) is isoelectronic with \(Li ^{+}\). Both contain \(2\) electrons. They have an electronic configuration \(Be ^2=1 s ^2= Li ^{+}\). This is equal to the electronic configuration of \(He\).
Structure of Atom
9702
An isostere is
1 \(NO_2^ - \) and \({O_3}\)
2 \(NO_2^ - \) and \(PO_4^{3 - }\)
3 \(C{O_2},\,{N_2}O,\,NO_3^ - \)
4 \(ClO_4^ - \) and \(OC{N^ - }\)
Explanation:
(a) \(NO_2^ - \) and \({O_3}\) are isostere. The number of atoms in these \(( = 3)\) and number of electrons \((24)\) are same.
Structure of Atom
9703
Nitrogen atom has an atomic number of \(7 \) and oxygen has an atomic number \(8.\) The total number of electrons in a nitrate ion will be
1 \(8\)
2 \(16\)
3 \(32\)
4 \(64\)
Explanation:
(c) Number of electrons in nitrogen \( = 7\) and number of electron is oxygen \( = 8 \) we know that formula of nitrate ion is \(NO_3^ - \) we also know that number of electron \(= (1 × \) Number of electrons in nitrogen) \(+ (3 × \) number of electrons in oxygen) \(+ 1\) \(= (1 × 7) + (3 × 8) + 1 = 32.\)
Structure of Atom
9704
If molecular mass and atomic mass of sulphur are \(256\) and \(32\) respectively, its atomicity is
\(Be ^{2+}\) is isoelectronic with \(Li ^{+}\). Both contain \(2\) electrons. They have an electronic configuration \(Be ^2=1 s ^2= Li ^{+}\). This is equal to the electronic configuration of \(He\).
Structure of Atom
9702
An isostere is
1 \(NO_2^ - \) and \({O_3}\)
2 \(NO_2^ - \) and \(PO_4^{3 - }\)
3 \(C{O_2},\,{N_2}O,\,NO_3^ - \)
4 \(ClO_4^ - \) and \(OC{N^ - }\)
Explanation:
(a) \(NO_2^ - \) and \({O_3}\) are isostere. The number of atoms in these \(( = 3)\) and number of electrons \((24)\) are same.
Structure of Atom
9703
Nitrogen atom has an atomic number of \(7 \) and oxygen has an atomic number \(8.\) The total number of electrons in a nitrate ion will be
1 \(8\)
2 \(16\)
3 \(32\)
4 \(64\)
Explanation:
(c) Number of electrons in nitrogen \( = 7\) and number of electron is oxygen \( = 8 \) we know that formula of nitrate ion is \(NO_3^ - \) we also know that number of electron \(= (1 × \) Number of electrons in nitrogen) \(+ (3 × \) number of electrons in oxygen) \(+ 1\) \(= (1 × 7) + (3 × 8) + 1 = 32.\)
Structure of Atom
9704
If molecular mass and atomic mass of sulphur are \(256\) and \(32\) respectively, its atomicity is
