NEET Test Series from KOTA - 10 Papers In MS WORD
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Some Basic Concepts of Chemistry
186154
In a hydrocarbon, mass ratio of hydrogen and carbon is \(1 : 3\), the empirical formula of hydrocarbon is
1 \(CH_4\)
2 \(CH_2\)
3 \(C_2H\)
4 \(CH_3\)
Explanation:
Mass ratio of \(H : C = 1 : 12\) However, given mass ratio of \(H : C = 1 : 3\) Therefore, for every \(C\) atom, there are \(4\, H\) atoms, hence empirical formula \(= CH_4\)
Some Basic Concepts of Chemistry
186155
The vapour density of a mixture containing \(NO_2\) and \(N_2O_4\) is \(27.6\). Mole fraction of \(NO_2\) in the mixture is
A picometre is a unit of length in the metric system, equal to \(1 \times 10^{-12}\,m\), or one trillionth \((11000000000000)\) of a metre, which is the \(SI\) base unit of length.
186154
In a hydrocarbon, mass ratio of hydrogen and carbon is \(1 : 3\), the empirical formula of hydrocarbon is
1 \(CH_4\)
2 \(CH_2\)
3 \(C_2H\)
4 \(CH_3\)
Explanation:
Mass ratio of \(H : C = 1 : 12\) However, given mass ratio of \(H : C = 1 : 3\) Therefore, for every \(C\) atom, there are \(4\, H\) atoms, hence empirical formula \(= CH_4\)
Some Basic Concepts of Chemistry
186155
The vapour density of a mixture containing \(NO_2\) and \(N_2O_4\) is \(27.6\). Mole fraction of \(NO_2\) in the mixture is
A picometre is a unit of length in the metric system, equal to \(1 \times 10^{-12}\,m\), or one trillionth \((11000000000000)\) of a metre, which is the \(SI\) base unit of length.
186154
In a hydrocarbon, mass ratio of hydrogen and carbon is \(1 : 3\), the empirical formula of hydrocarbon is
1 \(CH_4\)
2 \(CH_2\)
3 \(C_2H\)
4 \(CH_3\)
Explanation:
Mass ratio of \(H : C = 1 : 12\) However, given mass ratio of \(H : C = 1 : 3\) Therefore, for every \(C\) atom, there are \(4\, H\) atoms, hence empirical formula \(= CH_4\)
Some Basic Concepts of Chemistry
186155
The vapour density of a mixture containing \(NO_2\) and \(N_2O_4\) is \(27.6\). Mole fraction of \(NO_2\) in the mixture is
A picometre is a unit of length in the metric system, equal to \(1 \times 10^{-12}\,m\), or one trillionth \((11000000000000)\) of a metre, which is the \(SI\) base unit of length.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Some Basic Concepts of Chemistry
186154
In a hydrocarbon, mass ratio of hydrogen and carbon is \(1 : 3\), the empirical formula of hydrocarbon is
1 \(CH_4\)
2 \(CH_2\)
3 \(C_2H\)
4 \(CH_3\)
Explanation:
Mass ratio of \(H : C = 1 : 12\) However, given mass ratio of \(H : C = 1 : 3\) Therefore, for every \(C\) atom, there are \(4\, H\) atoms, hence empirical formula \(= CH_4\)
Some Basic Concepts of Chemistry
186155
The vapour density of a mixture containing \(NO_2\) and \(N_2O_4\) is \(27.6\). Mole fraction of \(NO_2\) in the mixture is
A picometre is a unit of length in the metric system, equal to \(1 \times 10^{-12}\,m\), or one trillionth \((11000000000000)\) of a metre, which is the \(SI\) base unit of length.