(a)\(SO_3^{2 - },{S^{2 - }}\)and \(SO_4^{2 - }\) salts from comparatively stronger acids (than \({H_2}C{O_3})\) in solution hence evolve \(C{O_2}\) with \(N{a_2}C{O_3}\) solution and give effervesence. While \(CO_3^{2 - }\) does not react with \(N{a_2}C{O_3}\) solution
PRACTICAL CHEMISTRY
37317
The number of hydroxide ions, produced by one molecule of sodium carbonate \((N{a_2}C{O_3})\) on hydrolysis is
1 \(2\)
2 \(1\)
3 \(3\)
4 \(4\)
Explanation:
(a) Hence, it is clear that \(2O{H^ - }\) ions will be formed on hydrolysis of one molecule of sodium corbonate. \(Na_2CO_3 + 2H_2O \to 2NaOH + H_2CO_3\) and \(2NaOH \, \overset {(ionisation)} \longleftrightarrow \, 2Na^+ + 2OH^-\)
PRACTICAL CHEMISTRY
37318
Gas \(A\) is bubbled through slaked lime when a white precipitate is formed. On prolonged bubbling, the precipitate is dissolved. on heating the resultant solution, the white precipitate reappears with the evolution of gas \(B\). The gases \(A\) and \(B\) respectively are
1 \(C{O_2}\) and \(CO\)
2 \(CO\) and \(C{O_2}\)
3 \(CO\) and \(CO\)
4 \(C{O_2}\) and \(C{O_2}\)
Explanation:
(d)According to the equation \(Ca{(OH)_2} + C{O_2}\xrightarrow{\Delta }CaC{O_3} + {H_2}O\), \(CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\) \(Ca{(HC{O_3})_2}\xrightarrow{\Delta }CaO + {H_2}O + 2C{O_2}\) Hence, the gas \(A\) and \( B\) are \(C{O_2}\)and \(C{O_2}\) respectively
PRACTICAL CHEMISTRY
37319
By passing \({H_2}S\) gas in acidified \(KMn{O_4}\) solution, we get
(a)\(SO_3^{2 - },{S^{2 - }}\)and \(SO_4^{2 - }\) salts from comparatively stronger acids (than \({H_2}C{O_3})\) in solution hence evolve \(C{O_2}\) with \(N{a_2}C{O_3}\) solution and give effervesence. While \(CO_3^{2 - }\) does not react with \(N{a_2}C{O_3}\) solution
PRACTICAL CHEMISTRY
37317
The number of hydroxide ions, produced by one molecule of sodium carbonate \((N{a_2}C{O_3})\) on hydrolysis is
1 \(2\)
2 \(1\)
3 \(3\)
4 \(4\)
Explanation:
(a) Hence, it is clear that \(2O{H^ - }\) ions will be formed on hydrolysis of one molecule of sodium corbonate. \(Na_2CO_3 + 2H_2O \to 2NaOH + H_2CO_3\) and \(2NaOH \, \overset {(ionisation)} \longleftrightarrow \, 2Na^+ + 2OH^-\)
PRACTICAL CHEMISTRY
37318
Gas \(A\) is bubbled through slaked lime when a white precipitate is formed. On prolonged bubbling, the precipitate is dissolved. on heating the resultant solution, the white precipitate reappears with the evolution of gas \(B\). The gases \(A\) and \(B\) respectively are
1 \(C{O_2}\) and \(CO\)
2 \(CO\) and \(C{O_2}\)
3 \(CO\) and \(CO\)
4 \(C{O_2}\) and \(C{O_2}\)
Explanation:
(d)According to the equation \(Ca{(OH)_2} + C{O_2}\xrightarrow{\Delta }CaC{O_3} + {H_2}O\), \(CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\) \(Ca{(HC{O_3})_2}\xrightarrow{\Delta }CaO + {H_2}O + 2C{O_2}\) Hence, the gas \(A\) and \( B\) are \(C{O_2}\)and \(C{O_2}\) respectively
PRACTICAL CHEMISTRY
37319
By passing \({H_2}S\) gas in acidified \(KMn{O_4}\) solution, we get
(a)\(SO_3^{2 - },{S^{2 - }}\)and \(SO_4^{2 - }\) salts from comparatively stronger acids (than \({H_2}C{O_3})\) in solution hence evolve \(C{O_2}\) with \(N{a_2}C{O_3}\) solution and give effervesence. While \(CO_3^{2 - }\) does not react with \(N{a_2}C{O_3}\) solution
PRACTICAL CHEMISTRY
37317
The number of hydroxide ions, produced by one molecule of sodium carbonate \((N{a_2}C{O_3})\) on hydrolysis is
1 \(2\)
2 \(1\)
3 \(3\)
4 \(4\)
Explanation:
(a) Hence, it is clear that \(2O{H^ - }\) ions will be formed on hydrolysis of one molecule of sodium corbonate. \(Na_2CO_3 + 2H_2O \to 2NaOH + H_2CO_3\) and \(2NaOH \, \overset {(ionisation)} \longleftrightarrow \, 2Na^+ + 2OH^-\)
PRACTICAL CHEMISTRY
37318
Gas \(A\) is bubbled through slaked lime when a white precipitate is formed. On prolonged bubbling, the precipitate is dissolved. on heating the resultant solution, the white precipitate reappears with the evolution of gas \(B\). The gases \(A\) and \(B\) respectively are
1 \(C{O_2}\) and \(CO\)
2 \(CO\) and \(C{O_2}\)
3 \(CO\) and \(CO\)
4 \(C{O_2}\) and \(C{O_2}\)
Explanation:
(d)According to the equation \(Ca{(OH)_2} + C{O_2}\xrightarrow{\Delta }CaC{O_3} + {H_2}O\), \(CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\) \(Ca{(HC{O_3})_2}\xrightarrow{\Delta }CaO + {H_2}O + 2C{O_2}\) Hence, the gas \(A\) and \( B\) are \(C{O_2}\)and \(C{O_2}\) respectively
PRACTICAL CHEMISTRY
37319
By passing \({H_2}S\) gas in acidified \(KMn{O_4}\) solution, we get
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PRACTICAL CHEMISTRY
37316
\(N{a_2}C{O_3}\)cannot be used to identify
1 \(CO_3^{2 - }\)
2 \(SO_3^{2 - }\)
3 \({S^{2 - }}\)
4 \(SO_4^{2 - }\)
Explanation:
(a)\(SO_3^{2 - },{S^{2 - }}\)and \(SO_4^{2 - }\) salts from comparatively stronger acids (than \({H_2}C{O_3})\) in solution hence evolve \(C{O_2}\) with \(N{a_2}C{O_3}\) solution and give effervesence. While \(CO_3^{2 - }\) does not react with \(N{a_2}C{O_3}\) solution
PRACTICAL CHEMISTRY
37317
The number of hydroxide ions, produced by one molecule of sodium carbonate \((N{a_2}C{O_3})\) on hydrolysis is
1 \(2\)
2 \(1\)
3 \(3\)
4 \(4\)
Explanation:
(a) Hence, it is clear that \(2O{H^ - }\) ions will be formed on hydrolysis of one molecule of sodium corbonate. \(Na_2CO_3 + 2H_2O \to 2NaOH + H_2CO_3\) and \(2NaOH \, \overset {(ionisation)} \longleftrightarrow \, 2Na^+ + 2OH^-\)
PRACTICAL CHEMISTRY
37318
Gas \(A\) is bubbled through slaked lime when a white precipitate is formed. On prolonged bubbling, the precipitate is dissolved. on heating the resultant solution, the white precipitate reappears with the evolution of gas \(B\). The gases \(A\) and \(B\) respectively are
1 \(C{O_2}\) and \(CO\)
2 \(CO\) and \(C{O_2}\)
3 \(CO\) and \(CO\)
4 \(C{O_2}\) and \(C{O_2}\)
Explanation:
(d)According to the equation \(Ca{(OH)_2} + C{O_2}\xrightarrow{\Delta }CaC{O_3} + {H_2}O\), \(CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\) \(Ca{(HC{O_3})_2}\xrightarrow{\Delta }CaO + {H_2}O + 2C{O_2}\) Hence, the gas \(A\) and \( B\) are \(C{O_2}\)and \(C{O_2}\) respectively
PRACTICAL CHEMISTRY
37319
By passing \({H_2}S\) gas in acidified \(KMn{O_4}\) solution, we get
(a)\(SO_3^{2 - },{S^{2 - }}\)and \(SO_4^{2 - }\) salts from comparatively stronger acids (than \({H_2}C{O_3})\) in solution hence evolve \(C{O_2}\) with \(N{a_2}C{O_3}\) solution and give effervesence. While \(CO_3^{2 - }\) does not react with \(N{a_2}C{O_3}\) solution
PRACTICAL CHEMISTRY
37317
The number of hydroxide ions, produced by one molecule of sodium carbonate \((N{a_2}C{O_3})\) on hydrolysis is
1 \(2\)
2 \(1\)
3 \(3\)
4 \(4\)
Explanation:
(a) Hence, it is clear that \(2O{H^ - }\) ions will be formed on hydrolysis of one molecule of sodium corbonate. \(Na_2CO_3 + 2H_2O \to 2NaOH + H_2CO_3\) and \(2NaOH \, \overset {(ionisation)} \longleftrightarrow \, 2Na^+ + 2OH^-\)
PRACTICAL CHEMISTRY
37318
Gas \(A\) is bubbled through slaked lime when a white precipitate is formed. On prolonged bubbling, the precipitate is dissolved. on heating the resultant solution, the white precipitate reappears with the evolution of gas \(B\). The gases \(A\) and \(B\) respectively are
1 \(C{O_2}\) and \(CO\)
2 \(CO\) and \(C{O_2}\)
3 \(CO\) and \(CO\)
4 \(C{O_2}\) and \(C{O_2}\)
Explanation:
(d)According to the equation \(Ca{(OH)_2} + C{O_2}\xrightarrow{\Delta }CaC{O_3} + {H_2}O\), \(CaC{{O}_{3}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}Ca{{(HC{{O}_{3}})}_{2}}\) \(Ca{(HC{O_3})_2}\xrightarrow{\Delta }CaO + {H_2}O + 2C{O_2}\) Hence, the gas \(A\) and \( B\) are \(C{O_2}\)and \(C{O_2}\) respectively
PRACTICAL CHEMISTRY
37319
By passing \({H_2}S\) gas in acidified \(KMn{O_4}\) solution, we get