QBManager

Electromagnetic Wave

155661 Match List I with List II of Electromagnetic waves with corresponding wavelength range:
|List I|List II|
|----|----|
|(A) Microwave|(I) $400 nm$ to $1 nm$ |
|(B) Ultraviolet|(II) $1 nm$ to $10^{- 3} nm$ |
|(C) X-Ray|(III) $1 nm$ to $700 nm$ |
|(D) Infra-red|(IV) $0.1 m$ to $1 mm$ |
Choose the correct answer form the options given below:

1 (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

2 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation:

B Increasing order of wavelength -
|Electromagnetic wavelength|Range of wave|
|
|X-ray| $1 nm$ to $10^{- 3} nm$ |
|Ultra Violet| $400 nm$ to $1 nm$ |
|Infra red| $1 nm$ to $700 nm$ |
|Micro wave|0.1 m to 1 mm|

JEE Main-15.04.2023

Electromagnetic Wave

155663 If a source of power $100 kW$ produces $1.5 \times$ $10^{20}$ photons $/ \sec$ . The radiation belongs to spectrum called as $(h = 6.63 \times 10^{- 34} J / s)$

1 Gamma rays

2 X-rays

3 Ultraviolet rays

4 Microwave rays

Explanation:

B Given,
$∵$ Power $(P) = 100 kW$
Photon per second $= \frac{n}{t} = 1.5 \times 10^{20}$
$P = \frac{n}{t} h v$
Where, $v =$ frequency
$10^{3} \times 100 = 1.5 \times 10^{20} \times 6.63 \times 10^{- 34} \times v$
$v = \frac{100 \times 10^{3}}{1.5 \times 10^{20} \times 6.63 \times 10^{- 34}}$
$v = 0.10055 \times 10^{19}$
This frequency lies in the spectrum of X-rays.

TS EAMCET 31.07.2022

Electromagnetic Wave

155664 Match the following Type of EM wave
| | Type of EM wave | Wavelength Range |
| :---: | :---: | :---: |
| A) | Microwave | I) $1 mm$ to $700 nm$ |
| B) | IR | II) $400 mm$ to $1 nm$ |
| C) | X-ray | III) $< 10^{- 3} nm$ |
| | Ultraviolet | IV) $0.1 m$ to $1 mr$ |
| | Gamma rays | V) $1 nm$ to $10^{- 3} nm$ |

1 A- IV,B- I,C- II,D- V,E- VIII

2 A- I,B- III,C- II,D- V,E- IV

3 A- V,B- III,C- V,D- III,E- II

4 A- IV,B- I,C- V,D- II,E- III

Explanation:

D Microwave- The wavelength between $1 mm$ to $0.1 m$ . Microwaves are used to send radio message and cook food.
IR- Infrared has wavelength between $700 nm$ to $1 mm$ $X$ -ray- X-rays have a wavelength in the range of $10^{- 3}$ $nm$ to $1 nm$ .
Ultraviolet - The wavelength between $1 nm$ to $400 mm$ Gamma rays. The wavelength between $< 10^{- 3} nm$ .

TS EAMCET 31.07.2022

Electromagnetic Wave

155665 If a source of electromagnetic radiation having power $15 kW$ produces $10^{16}$ photons per second, the radiation belong to a part of spectrum is.
(Take Planck constant $h = 6 \times 10^{- 34} Js$ )

1 Micro Waves

2 Gamma rays

3 Radio waves

4 Ultraviolet rays

Explanation:

B Given,
Power $= 15 kW = 15 \times 10^{3} W$
No. of photon per second $= 10^{16}$
Since, we know that-
Energy of one photon $(E) = \frac{Power}{Photon frequency}$
$E = \frac{15 \times 10^{3}}{10^{16}}$
$h v = \frac{15 \times 10^{3}}{10^{16}} = 15 \times 10^{- 13}$
$v = \frac{15 \times 10^{- 13}}{h} = \frac{15 \times 10^{- 13}}{6 \times 10^{- 34}}$
$v = 2.5 \times 10^{21} \sec^{- 1}$
Hence, it will come in the range of gamma rays.

JEE Main-31.01.2023

Electromagnetic Wave

155670 Match List - I with List - II
| List- I | | List-II | |
| :--- | :--- | :--- | :--- |
| (a) | UV rays | (i) | diagnostic tool in \lt br> medicine |
| (b) | X-rays | (ii) | water \lt br> purification |
| (c) | Microwave | (iii) | Communication, \lt br> Radar |
| (d) | Infrared wave | (iv) | Improving \lt br> visibility in foggy \lt br> days |
Choose the correct answer from the options given below:

1 (a)-( iii), (b)-(ii), (c)-(i), (d)-(iv)

2 (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

3 (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

4 (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Explanation:

B UV-Rays $\to$ Water purification
$X$ - Rays $\to$ Diagnostic tool in medicine
Microwave $\to$ Communication, radar
Infrared $\to$ Improving visibility in foggy days.

JEE Main-29.07.2022

Electromagnetic Wave

155661 Match List I with List II of Electromagnetic waves with corresponding wavelength range:
|List I|List II|
|----|----|
|(A) Microwave|(I) $400 nm$ to $1 nm$ |
|(B) Ultraviolet|(II) $1 nm$ to $10^{- 3} nm$ |
|(C) X-Ray|(III) $1 nm$ to $700 nm$ |
|(D) Infra-red|(IV) $0.1 m$ to $1 mm$ |
Choose the correct answer form the options given below:

1 (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

2 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation:

B Increasing order of wavelength -
|Electromagnetic wavelength|Range of wave|
|
|X-ray| $1 nm$ to $10^{- 3} nm$ |
|Ultra Violet| $400 nm$ to $1 nm$ |
|Infra red| $1 nm$ to $700 nm$ |
|Micro wave|0.1 m to 1 mm|

JEE Main-15.04.2023

Electromagnetic Wave

155663 If a source of power $100 kW$ produces $1.5 \times$ $10^{20}$ photons $/ \sec$ . The radiation belongs to spectrum called as $(h = 6.63 \times 10^{- 34} J / s)$

1 Gamma rays

2 X-rays

3 Ultraviolet rays

4 Microwave rays

Explanation:

B Given,
$∵$ Power $(P) = 100 kW$
Photon per second $= \frac{n}{t} = 1.5 \times 10^{20}$
$P = \frac{n}{t} h v$
Where, $v =$ frequency
$10^{3} \times 100 = 1.5 \times 10^{20} \times 6.63 \times 10^{- 34} \times v$
$v = \frac{100 \times 10^{3}}{1.5 \times 10^{20} \times 6.63 \times 10^{- 34}}$
$v = 0.10055 \times 10^{19}$
This frequency lies in the spectrum of X-rays.

TS EAMCET 31.07.2022

Electromagnetic Wave

155664 Match the following Type of EM wave
| | Type of EM wave | Wavelength Range |
| :---: | :---: | :---: |
| A) | Microwave | I) $1 mm$ to $700 nm$ |
| B) | IR | II) $400 mm$ to $1 nm$ |
| C) | X-ray | III) $< 10^{- 3} nm$ |
| | Ultraviolet | IV) $0.1 m$ to $1 mr$ |
| | Gamma rays | V) $1 nm$ to $10^{- 3} nm$ |

1 A- IV,B- I,C- II,D- V,E- VIII

2 A- I,B- III,C- II,D- V,E- IV

3 A- V,B- III,C- V,D- III,E- II

4 A- IV,B- I,C- V,D- II,E- III

Explanation:

D Microwave- The wavelength between $1 mm$ to $0.1 m$ . Microwaves are used to send radio message and cook food.
IR- Infrared has wavelength between $700 nm$ to $1 mm$ $X$ -ray- X-rays have a wavelength in the range of $10^{- 3}$ $nm$ to $1 nm$ .
Ultraviolet - The wavelength between $1 nm$ to $400 mm$ Gamma rays. The wavelength between $< 10^{- 3} nm$ .

TS EAMCET 31.07.2022

Electromagnetic Wave

155665 If a source of electromagnetic radiation having power $15 kW$ produces $10^{16}$ photons per second, the radiation belong to a part of spectrum is.
(Take Planck constant $h = 6 \times 10^{- 34} Js$ )

1 Micro Waves

2 Gamma rays

3 Radio waves

4 Ultraviolet rays

Explanation:

B Given,
Power $= 15 kW = 15 \times 10^{3} W$
No. of photon per second $= 10^{16}$
Since, we know that-
Energy of one photon $(E) = \frac{Power}{Photon frequency}$
$E = \frac{15 \times 10^{3}}{10^{16}}$
$h v = \frac{15 \times 10^{3}}{10^{16}} = 15 \times 10^{- 13}$
$v = \frac{15 \times 10^{- 13}}{h} = \frac{15 \times 10^{- 13}}{6 \times 10^{- 34}}$
$v = 2.5 \times 10^{21} \sec^{- 1}$
Hence, it will come in the range of gamma rays.

JEE Main-31.01.2023

Electromagnetic Wave

155670 Match List - I with List - II
| List- I | | List-II | |
| :--- | :--- | :--- | :--- |
| (a) | UV rays | (i) | diagnostic tool in \lt br> medicine |
| (b) | X-rays | (ii) | water \lt br> purification |
| (c) | Microwave | (iii) | Communication, \lt br> Radar |
| (d) | Infrared wave | (iv) | Improving \lt br> visibility in foggy \lt br> days |
Choose the correct answer from the options given below:

1 (a)-( iii), (b)-(ii), (c)-(i), (d)-(iv)

2 (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

3 (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

4 (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Explanation:

B UV-Rays $\to$ Water purification
$X$ - Rays $\to$ Diagnostic tool in medicine
Microwave $\to$ Communication, radar
Infrared $\to$ Improving visibility in foggy days.

JEE Main-29.07.2022

Electromagnetic Wave

155661 Match List I with List II of Electromagnetic waves with corresponding wavelength range:
|List I|List II|
|----|----|
|(A) Microwave|(I) $400 nm$ to $1 nm$ |
|(B) Ultraviolet|(II) $1 nm$ to $10^{- 3} nm$ |
|(C) X-Ray|(III) $1 nm$ to $700 nm$ |
|(D) Infra-red|(IV) $0.1 m$ to $1 mm$ |
Choose the correct answer form the options given below:

1 (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

2 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation:

B Increasing order of wavelength -
|Electromagnetic wavelength|Range of wave|
|
|X-ray| $1 nm$ to $10^{- 3} nm$ |
|Ultra Violet| $400 nm$ to $1 nm$ |
|Infra red| $1 nm$ to $700 nm$ |
|Micro wave|0.1 m to 1 mm|

JEE Main-15.04.2023

Electromagnetic Wave

155663 If a source of power $100 kW$ produces $1.5 \times$ $10^{20}$ photons $/ \sec$ . The radiation belongs to spectrum called as $(h = 6.63 \times 10^{- 34} J / s)$

1 Gamma rays

2 X-rays

3 Ultraviolet rays

4 Microwave rays

Explanation:

B Given,
$∵$ Power $(P) = 100 kW$
Photon per second $= \frac{n}{t} = 1.5 \times 10^{20}$
$P = \frac{n}{t} h v$
Where, $v =$ frequency
$10^{3} \times 100 = 1.5 \times 10^{20} \times 6.63 \times 10^{- 34} \times v$
$v = \frac{100 \times 10^{3}}{1.5 \times 10^{20} \times 6.63 \times 10^{- 34}}$
$v = 0.10055 \times 10^{19}$
This frequency lies in the spectrum of X-rays.

TS EAMCET 31.07.2022

Electromagnetic Wave

155664 Match the following Type of EM wave
| | Type of EM wave | Wavelength Range |
| :---: | :---: | :---: |
| A) | Microwave | I) $1 mm$ to $700 nm$ |
| B) | IR | II) $400 mm$ to $1 nm$ |
| C) | X-ray | III) $< 10^{- 3} nm$ |
| | Ultraviolet | IV) $0.1 m$ to $1 mr$ |
| | Gamma rays | V) $1 nm$ to $10^{- 3} nm$ |

1 A- IV,B- I,C- II,D- V,E- VIII

2 A- I,B- III,C- II,D- V,E- IV

3 A- V,B- III,C- V,D- III,E- II

4 A- IV,B- I,C- V,D- II,E- III

Explanation:

D Microwave- The wavelength between $1 mm$ to $0.1 m$ . Microwaves are used to send radio message and cook food.
IR- Infrared has wavelength between $700 nm$ to $1 mm$ $X$ -ray- X-rays have a wavelength in the range of $10^{- 3}$ $nm$ to $1 nm$ .
Ultraviolet - The wavelength between $1 nm$ to $400 mm$ Gamma rays. The wavelength between $< 10^{- 3} nm$ .

TS EAMCET 31.07.2022

Electromagnetic Wave

155665 If a source of electromagnetic radiation having power $15 kW$ produces $10^{16}$ photons per second, the radiation belong to a part of spectrum is.
(Take Planck constant $h = 6 \times 10^{- 34} Js$ )

1 Micro Waves

2 Gamma rays

3 Radio waves

4 Ultraviolet rays

Explanation:

B Given,
Power $= 15 kW = 15 \times 10^{3} W$
No. of photon per second $= 10^{16}$
Since, we know that-
Energy of one photon $(E) = \frac{Power}{Photon frequency}$
$E = \frac{15 \times 10^{3}}{10^{16}}$
$h v = \frac{15 \times 10^{3}}{10^{16}} = 15 \times 10^{- 13}$
$v = \frac{15 \times 10^{- 13}}{h} = \frac{15 \times 10^{- 13}}{6 \times 10^{- 34}}$
$v = 2.5 \times 10^{21} \sec^{- 1}$
Hence, it will come in the range of gamma rays.

JEE Main-31.01.2023

Electromagnetic Wave

155670 Match List - I with List - II
| List- I | | List-II | |
| :--- | :--- | :--- | :--- |
| (a) | UV rays | (i) | diagnostic tool in \lt br> medicine |
| (b) | X-rays | (ii) | water \lt br> purification |
| (c) | Microwave | (iii) | Communication, \lt br> Radar |
| (d) | Infrared wave | (iv) | Improving \lt br> visibility in foggy \lt br> days |
Choose the correct answer from the options given below:

1 (a)-( iii), (b)-(ii), (c)-(i), (d)-(iv)

2 (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

3 (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

4 (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Explanation:

B UV-Rays $\to$ Water purification
$X$ - Rays $\to$ Diagnostic tool in medicine
Microwave $\to$ Communication, radar
Infrared $\to$ Improving visibility in foggy days.

JEE Main-29.07.2022

Electromagnetic Wave

155661 Match List I with List II of Electromagnetic waves with corresponding wavelength range:
|List I|List II|
|----|----|
|(A) Microwave|(I) $400 nm$ to $1 nm$ |
|(B) Ultraviolet|(II) $1 nm$ to $10^{- 3} nm$ |
|(C) X-Ray|(III) $1 nm$ to $700 nm$ |
|(D) Infra-red|(IV) $0.1 m$ to $1 mm$ |
Choose the correct answer form the options given below:

1 (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

2 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation:

B Increasing order of wavelength -
|Electromagnetic wavelength|Range of wave|
|
|X-ray| $1 nm$ to $10^{- 3} nm$ |
|Ultra Violet| $400 nm$ to $1 nm$ |
|Infra red| $1 nm$ to $700 nm$ |
|Micro wave|0.1 m to 1 mm|

JEE Main-15.04.2023

Electromagnetic Wave

155663 If a source of power $100 kW$ produces $1.5 \times$ $10^{20}$ photons $/ \sec$ . The radiation belongs to spectrum called as $(h = 6.63 \times 10^{- 34} J / s)$

1 Gamma rays

2 X-rays

3 Ultraviolet rays

4 Microwave rays

Explanation:

B Given,
$∵$ Power $(P) = 100 kW$
Photon per second $= \frac{n}{t} = 1.5 \times 10^{20}$
$P = \frac{n}{t} h v$
Where, $v =$ frequency
$10^{3} \times 100 = 1.5 \times 10^{20} \times 6.63 \times 10^{- 34} \times v$
$v = \frac{100 \times 10^{3}}{1.5 \times 10^{20} \times 6.63 \times 10^{- 34}}$
$v = 0.10055 \times 10^{19}$
This frequency lies in the spectrum of X-rays.

TS EAMCET 31.07.2022

Electromagnetic Wave

155664 Match the following Type of EM wave
| | Type of EM wave | Wavelength Range |
| :---: | :---: | :---: |
| A) | Microwave | I) $1 mm$ to $700 nm$ |
| B) | IR | II) $400 mm$ to $1 nm$ |
| C) | X-ray | III) $< 10^{- 3} nm$ |
| | Ultraviolet | IV) $0.1 m$ to $1 mr$ |
| | Gamma rays | V) $1 nm$ to $10^{- 3} nm$ |

1 A- IV,B- I,C- II,D- V,E- VIII

2 A- I,B- III,C- II,D- V,E- IV

3 A- V,B- III,C- V,D- III,E- II

4 A- IV,B- I,C- V,D- II,E- III

Explanation:

D Microwave- The wavelength between $1 mm$ to $0.1 m$ . Microwaves are used to send radio message and cook food.
IR- Infrared has wavelength between $700 nm$ to $1 mm$ $X$ -ray- X-rays have a wavelength in the range of $10^{- 3}$ $nm$ to $1 nm$ .
Ultraviolet - The wavelength between $1 nm$ to $400 mm$ Gamma rays. The wavelength between $< 10^{- 3} nm$ .

TS EAMCET 31.07.2022

Electromagnetic Wave

155665 If a source of electromagnetic radiation having power $15 kW$ produces $10^{16}$ photons per second, the radiation belong to a part of spectrum is.
(Take Planck constant $h = 6 \times 10^{- 34} Js$ )

1 Micro Waves

2 Gamma rays

3 Radio waves

4 Ultraviolet rays

Explanation:

B Given,
Power $= 15 kW = 15 \times 10^{3} W$
No. of photon per second $= 10^{16}$
Since, we know that-
Energy of one photon $(E) = \frac{Power}{Photon frequency}$
$E = \frac{15 \times 10^{3}}{10^{16}}$
$h v = \frac{15 \times 10^{3}}{10^{16}} = 15 \times 10^{- 13}$
$v = \frac{15 \times 10^{- 13}}{h} = \frac{15 \times 10^{- 13}}{6 \times 10^{- 34}}$
$v = 2.5 \times 10^{21} \sec^{- 1}$
Hence, it will come in the range of gamma rays.

JEE Main-31.01.2023

Electromagnetic Wave

155670 Match List - I with List - II
| List- I | | List-II | |
| :--- | :--- | :--- | :--- |
| (a) | UV rays | (i) | diagnostic tool in \lt br> medicine |
| (b) | X-rays | (ii) | water \lt br> purification |
| (c) | Microwave | (iii) | Communication, \lt br> Radar |
| (d) | Infrared wave | (iv) | Improving \lt br> visibility in foggy \lt br> days |
Choose the correct answer from the options given below:

1 (a)-( iii), (b)-(ii), (c)-(i), (d)-(iv)

2 (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

3 (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

4 (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Explanation:

B UV-Rays $\to$ Water purification
$X$ - Rays $\to$ Diagnostic tool in medicine
Microwave $\to$ Communication, radar
Infrared $\to$ Improving visibility in foggy days.

JEE Main-29.07.2022

Electromagnetic Wave

155661 Match List I with List II of Electromagnetic waves with corresponding wavelength range:
|List I|List II|
|----|----|
|(A) Microwave|(I) $400 nm$ to $1 nm$ |
|(B) Ultraviolet|(II) $1 nm$ to $10^{- 3} nm$ |
|(C) X-Ray|(III) $1 nm$ to $700 nm$ |
|(D) Infra-red|(IV) $0.1 m$ to $1 mm$ |
Choose the correct answer form the options given below:

1 (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

2 (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

3 (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

4 (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Explanation:

B Increasing order of wavelength -
|Electromagnetic wavelength|Range of wave|
|
|X-ray| $1 nm$ to $10^{- 3} nm$ |
|Ultra Violet| $400 nm$ to $1 nm$ |
|Infra red| $1 nm$ to $700 nm$ |
|Micro wave|0.1 m to 1 mm|

JEE Main-15.04.2023

Electromagnetic Wave

155663 If a source of power $100 kW$ produces $1.5 \times$ $10^{20}$ photons $/ \sec$ . The radiation belongs to spectrum called as $(h = 6.63 \times 10^{- 34} J / s)$

1 Gamma rays

2 X-rays

3 Ultraviolet rays

4 Microwave rays

Explanation:

B Given,
$∵$ Power $(P) = 100 kW$
Photon per second $= \frac{n}{t} = 1.5 \times 10^{20}$
$P = \frac{n}{t} h v$
Where, $v =$ frequency
$10^{3} \times 100 = 1.5 \times 10^{20} \times 6.63 \times 10^{- 34} \times v$
$v = \frac{100 \times 10^{3}}{1.5 \times 10^{20} \times 6.63 \times 10^{- 34}}$
$v = 0.10055 \times 10^{19}$
This frequency lies in the spectrum of X-rays.

TS EAMCET 31.07.2022

Electromagnetic Wave

155664 Match the following Type of EM wave
| | Type of EM wave | Wavelength Range |
| :---: | :---: | :---: |
| A) | Microwave | I) $1 mm$ to $700 nm$ |
| B) | IR | II) $400 mm$ to $1 nm$ |
| C) | X-ray | III) $< 10^{- 3} nm$ |
| | Ultraviolet | IV) $0.1 m$ to $1 mr$ |
| | Gamma rays | V) $1 nm$ to $10^{- 3} nm$ |

1 A- IV,B- I,C- II,D- V,E- VIII

2 A- I,B- III,C- II,D- V,E- IV

3 A- V,B- III,C- V,D- III,E- II

4 A- IV,B- I,C- V,D- II,E- III

Explanation:

D Microwave- The wavelength between $1 mm$ to $0.1 m$ . Microwaves are used to send radio message and cook food.
IR- Infrared has wavelength between $700 nm$ to $1 mm$ $X$ -ray- X-rays have a wavelength in the range of $10^{- 3}$ $nm$ to $1 nm$ .
Ultraviolet - The wavelength between $1 nm$ to $400 mm$ Gamma rays. The wavelength between $< 10^{- 3} nm$ .

TS EAMCET 31.07.2022

Electromagnetic Wave

155665 If a source of electromagnetic radiation having power $15 kW$ produces $10^{16}$ photons per second, the radiation belong to a part of spectrum is.
(Take Planck constant $h = 6 \times 10^{- 34} Js$ )

1 Micro Waves

2 Gamma rays

3 Radio waves

4 Ultraviolet rays

Explanation:

B Given,
Power $= 15 kW = 15 \times 10^{3} W$
No. of photon per second $= 10^{16}$
Since, we know that-
Energy of one photon $(E) = \frac{Power}{Photon frequency}$
$E = \frac{15 \times 10^{3}}{10^{16}}$
$h v = \frac{15 \times 10^{3}}{10^{16}} = 15 \times 10^{- 13}$
$v = \frac{15 \times 10^{- 13}}{h} = \frac{15 \times 10^{- 13}}{6 \times 10^{- 34}}$
$v = 2.5 \times 10^{21} \sec^{- 1}$
Hence, it will come in the range of gamma rays.

JEE Main-31.01.2023

Electromagnetic Wave

155670 Match List - I with List - II
| List- I | | List-II | |
| :--- | :--- | :--- | :--- |
| (a) | UV rays | (i) | diagnostic tool in \lt br> medicine |
| (b) | X-rays | (ii) | water \lt br> purification |
| (c) | Microwave | (iii) | Communication, \lt br> Radar |
| (d) | Infrared wave | (iv) | Improving \lt br> visibility in foggy \lt br> days |
Choose the correct answer from the options given below:

1 (a)-( iii), (b)-(ii), (c)-(i), (d)-(iv)

2 (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)

3 (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

4 (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)

Explanation:

B UV-Rays $\to$ Water purification
$X$ - Rays $\to$ Diagnostic tool in medicine
Microwave $\to$ Communication, radar
Infrared $\to$ Improving visibility in foggy days.

JEE Main-29.07.2022

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