05. Dynamo, Transformer Inductance
Alternating Current

155447 A current of $5 \mathrm{~A}$ is flowing at $220 \mathrm{~V}$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \mathrm{~V}$ and $50 \%$ of power is lost, then the current in the secondary will be

1 $2.5 \mathrm{~A}$
2 $5 \mathrm{~A}$
3 $0.25 \mathrm{~A}$
4 $0.5 \mathrm{~A}$
Alternating Current

155448 The ratio of the secondary to the primary turns in a transformer is $3: 2$ and the output power is $P$. Neglecting all power losses, the input power must be

1 $\frac{P}{2}$
2 $\mathrm{P}$
3 $\frac{2 P}{3}$
4 $\frac{3 P}{2}$
Alternating Current

155449 The number of turns of the primary and the secondary coil of a transformer are $\mathbf{1 0}$ and $\mathbf{1 0 0}$ respectively. The primary voltage and the current are given as $2 \mathrm{~V}$ and $1 \mathrm{~A}$. Assuming the efficiency of the transformer as $90 \%$, the secondary voltage and the current respectively are

1 $20 \mathrm{~V}$ and $0.1 \mathrm{~A}$
2 $0.2 \mathrm{~V}$ and $1 \mathrm{~A}$
3 $20 \mathrm{~V}$ and $0.09 \mathrm{~A}$
4 $0.2 \mathrm{~V}$ and $0.9 \mathrm{~A}$
Alternating Current

155450 A transformer is used to light a 140 watt, 24 volt lamp from $240 \mathrm{~V}$ AC mains. The current in the mains cable is $0.7 \mathrm{amp}$. The efficiency of the transformer is

1 $48 \%$
2 $63.8 \%$
3 $83.3 \%$
4 $90 \%$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Alternating Current

155447 A current of $5 \mathrm{~A}$ is flowing at $220 \mathrm{~V}$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \mathrm{~V}$ and $50 \%$ of power is lost, then the current in the secondary will be

1 $2.5 \mathrm{~A}$
2 $5 \mathrm{~A}$
3 $0.25 \mathrm{~A}$
4 $0.5 \mathrm{~A}$
Alternating Current

155448 The ratio of the secondary to the primary turns in a transformer is $3: 2$ and the output power is $P$. Neglecting all power losses, the input power must be

1 $\frac{P}{2}$
2 $\mathrm{P}$
3 $\frac{2 P}{3}$
4 $\frac{3 P}{2}$
Alternating Current

155449 The number of turns of the primary and the secondary coil of a transformer are $\mathbf{1 0}$ and $\mathbf{1 0 0}$ respectively. The primary voltage and the current are given as $2 \mathrm{~V}$ and $1 \mathrm{~A}$. Assuming the efficiency of the transformer as $90 \%$, the secondary voltage and the current respectively are

1 $20 \mathrm{~V}$ and $0.1 \mathrm{~A}$
2 $0.2 \mathrm{~V}$ and $1 \mathrm{~A}$
3 $20 \mathrm{~V}$ and $0.09 \mathrm{~A}$
4 $0.2 \mathrm{~V}$ and $0.9 \mathrm{~A}$
Alternating Current

155450 A transformer is used to light a 140 watt, 24 volt lamp from $240 \mathrm{~V}$ AC mains. The current in the mains cable is $0.7 \mathrm{amp}$. The efficiency of the transformer is

1 $48 \%$
2 $63.8 \%$
3 $83.3 \%$
4 $90 \%$
Alternating Current

155447 A current of $5 \mathrm{~A}$ is flowing at $220 \mathrm{~V}$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \mathrm{~V}$ and $50 \%$ of power is lost, then the current in the secondary will be

1 $2.5 \mathrm{~A}$
2 $5 \mathrm{~A}$
3 $0.25 \mathrm{~A}$
4 $0.5 \mathrm{~A}$
Alternating Current

155448 The ratio of the secondary to the primary turns in a transformer is $3: 2$ and the output power is $P$. Neglecting all power losses, the input power must be

1 $\frac{P}{2}$
2 $\mathrm{P}$
3 $\frac{2 P}{3}$
4 $\frac{3 P}{2}$
Alternating Current

155449 The number of turns of the primary and the secondary coil of a transformer are $\mathbf{1 0}$ and $\mathbf{1 0 0}$ respectively. The primary voltage and the current are given as $2 \mathrm{~V}$ and $1 \mathrm{~A}$. Assuming the efficiency of the transformer as $90 \%$, the secondary voltage and the current respectively are

1 $20 \mathrm{~V}$ and $0.1 \mathrm{~A}$
2 $0.2 \mathrm{~V}$ and $1 \mathrm{~A}$
3 $20 \mathrm{~V}$ and $0.09 \mathrm{~A}$
4 $0.2 \mathrm{~V}$ and $0.9 \mathrm{~A}$
Alternating Current

155450 A transformer is used to light a 140 watt, 24 volt lamp from $240 \mathrm{~V}$ AC mains. The current in the mains cable is $0.7 \mathrm{amp}$. The efficiency of the transformer is

1 $48 \%$
2 $63.8 \%$
3 $83.3 \%$
4 $90 \%$
Alternating Current

155447 A current of $5 \mathrm{~A}$ is flowing at $220 \mathrm{~V}$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \mathrm{~V}$ and $50 \%$ of power is lost, then the current in the secondary will be

1 $2.5 \mathrm{~A}$
2 $5 \mathrm{~A}$
3 $0.25 \mathrm{~A}$
4 $0.5 \mathrm{~A}$
Alternating Current

155448 The ratio of the secondary to the primary turns in a transformer is $3: 2$ and the output power is $P$. Neglecting all power losses, the input power must be

1 $\frac{P}{2}$
2 $\mathrm{P}$
3 $\frac{2 P}{3}$
4 $\frac{3 P}{2}$
Alternating Current

155449 The number of turns of the primary and the secondary coil of a transformer are $\mathbf{1 0}$ and $\mathbf{1 0 0}$ respectively. The primary voltage and the current are given as $2 \mathrm{~V}$ and $1 \mathrm{~A}$. Assuming the efficiency of the transformer as $90 \%$, the secondary voltage and the current respectively are

1 $20 \mathrm{~V}$ and $0.1 \mathrm{~A}$
2 $0.2 \mathrm{~V}$ and $1 \mathrm{~A}$
3 $20 \mathrm{~V}$ and $0.09 \mathrm{~A}$
4 $0.2 \mathrm{~V}$ and $0.9 \mathrm{~A}$
Alternating Current

155450 A transformer is used to light a 140 watt, 24 volt lamp from $240 \mathrm{~V}$ AC mains. The current in the mains cable is $0.7 \mathrm{amp}$. The efficiency of the transformer is

1 $48 \%$
2 $63.8 \%$
3 $83.3 \%$
4 $90 \%$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here