01. A.C. Voltage Applied to Inductance & Capacitor
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Alternating Current

155051 In the given circuit, the angular frequency of the voltage source is $70 \times 10^{3} \mathrm{rads}^{-1}$. The circuit effectively behaves like,

1 Purely resistive circuit
2 Series RL circuit
3 Series RC circuit
4 Series LC circuit with $\mathrm{R}=0$
AP EAMCET (23.04.2019) Shift-I
Alternating Current

155052 When an inductor $L$ and a resistor $R$ in series are connected across a $12 \mathrm{~V}, 50 \mathrm{~Hz}$ supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by $\frac{\pi}{3}$ radian. Then the value of $R$ is

1 \(10 \Omega\)
2 \(3 \Omega\)
3 \(12 \Omega\)
4 \(15 \Omega\)
AP EAMCET (22.04.2019) Shift-I
Alternating Current

155055 A Primary coil is connected with an AC source and a bulb is connected with the secondary coil. The voltage across the bulb is $6.0 \mathrm{~V}$ and the current through the bulb is $0.4 \mathrm{~A}$. The turns ratio is $5: 1\left(N_{p}: N_{s}=5: 1\right)$. Calculate the current in the primary coil.

1 $8 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $12.5 \mathrm{~A}$
4 None of the above
J and K CET-2018
Alternating Current

155056 An alternating voltage of $220 \mathrm{~V}, 50 \mathrm{~Hz}$ frequency is applied across a capacitor of capacitance $2 \mu \mathrm{F}$. The impedance of the circuit is

1 $\frac{\pi}{5000}$
2 $\frac{1000}{\pi}$
3 $500 \pi$
4 $\frac{5000}{\pi}$
VITEEE-2018
For More Updates join with Us
Alternating Current

155051 In the given circuit, the angular frequency of the voltage source is $70 \times 10^{3} \mathrm{rads}^{-1}$. The circuit effectively behaves like,

1 Purely resistive circuit
2 Series RL circuit
3 Series RC circuit
4 Series LC circuit with $\mathrm{R}=0$
AP EAMCET (23.04.2019) Shift-I
Alternating Current

155052 When an inductor $L$ and a resistor $R$ in series are connected across a $12 \mathrm{~V}, 50 \mathrm{~Hz}$ supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by $\frac{\pi}{3}$ radian. Then the value of $R$ is

1 \(10 \Omega\)
2 \(3 \Omega\)
3 \(12 \Omega\)
4 \(15 \Omega\)
AP EAMCET (22.04.2019) Shift-I
Alternating Current

155055 A Primary coil is connected with an AC source and a bulb is connected with the secondary coil. The voltage across the bulb is $6.0 \mathrm{~V}$ and the current through the bulb is $0.4 \mathrm{~A}$. The turns ratio is $5: 1\left(N_{p}: N_{s}=5: 1\right)$. Calculate the current in the primary coil.

1 $8 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $12.5 \mathrm{~A}$
4 None of the above
J and K CET-2018
Alternating Current

155056 An alternating voltage of $220 \mathrm{~V}, 50 \mathrm{~Hz}$ frequency is applied across a capacitor of capacitance $2 \mu \mathrm{F}$. The impedance of the circuit is

1 $\frac{\pi}{5000}$
2 $\frac{1000}{\pi}$
3 $500 \pi$
4 $\frac{5000}{\pi}$
VITEEE-2018
NEET DIGITAL LIBRARY
Alternating Current

155051 In the given circuit, the angular frequency of the voltage source is $70 \times 10^{3} \mathrm{rads}^{-1}$. The circuit effectively behaves like,

1 Purely resistive circuit
2 Series RL circuit
3 Series RC circuit
4 Series LC circuit with $\mathrm{R}=0$
AP EAMCET (23.04.2019) Shift-I
Alternating Current

155052 When an inductor $L$ and a resistor $R$ in series are connected across a $12 \mathrm{~V}, 50 \mathrm{~Hz}$ supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by $\frac{\pi}{3}$ radian. Then the value of $R$ is

1 \(10 \Omega\)
2 \(3 \Omega\)
3 \(12 \Omega\)
4 \(15 \Omega\)
AP EAMCET (22.04.2019) Shift-I
Alternating Current

155055 A Primary coil is connected with an AC source and a bulb is connected with the secondary coil. The voltage across the bulb is $6.0 \mathrm{~V}$ and the current through the bulb is $0.4 \mathrm{~A}$. The turns ratio is $5: 1\left(N_{p}: N_{s}=5: 1\right)$. Calculate the current in the primary coil.

1 $8 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $12.5 \mathrm{~A}$
4 None of the above
J and K CET-2018
Alternating Current

155056 An alternating voltage of $220 \mathrm{~V}, 50 \mathrm{~Hz}$ frequency is applied across a capacitor of capacitance $2 \mu \mathrm{F}$. The impedance of the circuit is

1 $\frac{\pi}{5000}$
2 $\frac{1000}{\pi}$
3 $500 \pi$
4 $\frac{5000}{\pi}$
VITEEE-2018
Join With Us for More Updates
Alternating Current

155051 In the given circuit, the angular frequency of the voltage source is $70 \times 10^{3} \mathrm{rads}^{-1}$. The circuit effectively behaves like,

1 Purely resistive circuit
2 Series RL circuit
3 Series RC circuit
4 Series LC circuit with $\mathrm{R}=0$
AP EAMCET (23.04.2019) Shift-I
Alternating Current

155052 When an inductor $L$ and a resistor $R$ in series are connected across a $12 \mathrm{~V}, 50 \mathrm{~Hz}$ supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by $\frac{\pi}{3}$ radian. Then the value of $R$ is

1 \(10 \Omega\)
2 \(3 \Omega\)
3 \(12 \Omega\)
4 \(15 \Omega\)
AP EAMCET (22.04.2019) Shift-I
Alternating Current

155055 A Primary coil is connected with an AC source and a bulb is connected with the secondary coil. The voltage across the bulb is $6.0 \mathrm{~V}$ and the current through the bulb is $0.4 \mathrm{~A}$. The turns ratio is $5: 1\left(N_{p}: N_{s}=5: 1\right)$. Calculate the current in the primary coil.

1 $8 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $12.5 \mathrm{~A}$
4 None of the above
J and K CET-2018
Alternating Current

155056 An alternating voltage of $220 \mathrm{~V}, 50 \mathrm{~Hz}$ frequency is applied across a capacitor of capacitance $2 \mu \mathrm{F}$. The impedance of the circuit is

1 $\frac{\pi}{5000}$
2 $\frac{1000}{\pi}$
3 $500 \pi$
4 $\frac{5000}{\pi}$
VITEEE-2018
For More Updates join with Us