00. A.C. Voltage in Resistor and Phasor
Alternating Current

154956 If voltage across a bulb rated $220 \mathrm{~V}, 100 \mathrm{~W}$ drops by $2.5 \%$ of its rated value, the percentage of the rated value by which the power would decrease is

1 $5 \%$
2 $10 \%$
3 $20 \%$
4 $2.5 \%$
Alternating Current

154958 A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V} .50 \mathrm{~Hz}$ AC supply. The rms value of the current in the circuit is

1 $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
2 $10 \mathrm{~A}$
3 $\frac{50}{\pi} \mathrm{A}$
4 $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Alternating Current

154959 A circuit element $X$ when connected to an a.c. supply of peak voltage $100 \mathrm{~V}$ gives a peak current of $5 \mathrm{~A}$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

1 $\frac{10}{\sqrt{2}}$
2 $\frac{5}{\sqrt{2}}$
3 $5 \sqrt{2}$
4 $\frac{5}{2}$
Alternating Current

154960 A $100 \mu \mathrm{F}$ capacitor is connected to a $100 \mathrm{~V}, 50$ $\mathrm{Hz}$ AC supply. The rms value of the current is

1 $3.14 \mathrm{~A}$
2 $4.75 \mathrm{~A}$
3 $2.33 \mathrm{~A}$
4 $5.5 \mathrm{~A}$
Alternating Current

154961 An alternating current is given by $i=i_{1} \cos \omega t+$ $i_{2} \sin \omega t$. The rms current is given by:

1 $\frac{i_{1}+i_{2}}{\sqrt{2}}$
2 $\frac{i_{2}-i_{1}}{\sqrt{2}}$
3 $\sqrt{\left(\frac{\dot{i}_{1}^{2}+i_{2}^{2}}{2}\right)}$
4 $\sqrt{\left(\frac{\dot{i}_{1}^{2}-i_{2}^{2}}{2}\right)}$
Alternating Current

154956 If voltage across a bulb rated $220 \mathrm{~V}, 100 \mathrm{~W}$ drops by $2.5 \%$ of its rated value, the percentage of the rated value by which the power would decrease is

1 $5 \%$
2 $10 \%$
3 $20 \%$
4 $2.5 \%$
Alternating Current

154958 A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V} .50 \mathrm{~Hz}$ AC supply. The rms value of the current in the circuit is

1 $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
2 $10 \mathrm{~A}$
3 $\frac{50}{\pi} \mathrm{A}$
4 $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Alternating Current

154959 A circuit element $X$ when connected to an a.c. supply of peak voltage $100 \mathrm{~V}$ gives a peak current of $5 \mathrm{~A}$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

1 $\frac{10}{\sqrt{2}}$
2 $\frac{5}{\sqrt{2}}$
3 $5 \sqrt{2}$
4 $\frac{5}{2}$
Alternating Current

154960 A $100 \mu \mathrm{F}$ capacitor is connected to a $100 \mathrm{~V}, 50$ $\mathrm{Hz}$ AC supply. The rms value of the current is

1 $3.14 \mathrm{~A}$
2 $4.75 \mathrm{~A}$
3 $2.33 \mathrm{~A}$
4 $5.5 \mathrm{~A}$
Alternating Current

154961 An alternating current is given by $i=i_{1} \cos \omega t+$ $i_{2} \sin \omega t$. The rms current is given by:

1 $\frac{i_{1}+i_{2}}{\sqrt{2}}$
2 $\frac{i_{2}-i_{1}}{\sqrt{2}}$
3 $\sqrt{\left(\frac{\dot{i}_{1}^{2}+i_{2}^{2}}{2}\right)}$
4 $\sqrt{\left(\frac{\dot{i}_{1}^{2}-i_{2}^{2}}{2}\right)}$
Alternating Current

154956 If voltage across a bulb rated $220 \mathrm{~V}, 100 \mathrm{~W}$ drops by $2.5 \%$ of its rated value, the percentage of the rated value by which the power would decrease is

1 $5 \%$
2 $10 \%$
3 $20 \%$
4 $2.5 \%$
Alternating Current

154958 A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V} .50 \mathrm{~Hz}$ AC supply. The rms value of the current in the circuit is

1 $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
2 $10 \mathrm{~A}$
3 $\frac{50}{\pi} \mathrm{A}$
4 $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Alternating Current

154959 A circuit element $X$ when connected to an a.c. supply of peak voltage $100 \mathrm{~V}$ gives a peak current of $5 \mathrm{~A}$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

1 $\frac{10}{\sqrt{2}}$
2 $\frac{5}{\sqrt{2}}$
3 $5 \sqrt{2}$
4 $\frac{5}{2}$
Alternating Current

154960 A $100 \mu \mathrm{F}$ capacitor is connected to a $100 \mathrm{~V}, 50$ $\mathrm{Hz}$ AC supply. The rms value of the current is

1 $3.14 \mathrm{~A}$
2 $4.75 \mathrm{~A}$
3 $2.33 \mathrm{~A}$
4 $5.5 \mathrm{~A}$
Alternating Current

154961 An alternating current is given by $i=i_{1} \cos \omega t+$ $i_{2} \sin \omega t$. The rms current is given by:

1 $\frac{i_{1}+i_{2}}{\sqrt{2}}$
2 $\frac{i_{2}-i_{1}}{\sqrt{2}}$
3 $\sqrt{\left(\frac{\dot{i}_{1}^{2}+i_{2}^{2}}{2}\right)}$
4 $\sqrt{\left(\frac{\dot{i}_{1}^{2}-i_{2}^{2}}{2}\right)}$
Alternating Current

154956 If voltage across a bulb rated $220 \mathrm{~V}, 100 \mathrm{~W}$ drops by $2.5 \%$ of its rated value, the percentage of the rated value by which the power would decrease is

1 $5 \%$
2 $10 \%$
3 $20 \%$
4 $2.5 \%$
Alternating Current

154958 A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V} .50 \mathrm{~Hz}$ AC supply. The rms value of the current in the circuit is

1 $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
2 $10 \mathrm{~A}$
3 $\frac{50}{\pi} \mathrm{A}$
4 $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Alternating Current

154959 A circuit element $X$ when connected to an a.c. supply of peak voltage $100 \mathrm{~V}$ gives a peak current of $5 \mathrm{~A}$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

1 $\frac{10}{\sqrt{2}}$
2 $\frac{5}{\sqrt{2}}$
3 $5 \sqrt{2}$
4 $\frac{5}{2}$
Alternating Current

154960 A $100 \mu \mathrm{F}$ capacitor is connected to a $100 \mathrm{~V}, 50$ $\mathrm{Hz}$ AC supply. The rms value of the current is

1 $3.14 \mathrm{~A}$
2 $4.75 \mathrm{~A}$
3 $2.33 \mathrm{~A}$
4 $5.5 \mathrm{~A}$
Alternating Current

154961 An alternating current is given by $i=i_{1} \cos \omega t+$ $i_{2} \sin \omega t$. The rms current is given by:

1 $\frac{i_{1}+i_{2}}{\sqrt{2}}$
2 $\frac{i_{2}-i_{1}}{\sqrt{2}}$
3 $\sqrt{\left(\frac{\dot{i}_{1}^{2}+i_{2}^{2}}{2}\right)}$
4 $\sqrt{\left(\frac{\dot{i}_{1}^{2}-i_{2}^{2}}{2}\right)}$
Alternating Current

154956 If voltage across a bulb rated $220 \mathrm{~V}, 100 \mathrm{~W}$ drops by $2.5 \%$ of its rated value, the percentage of the rated value by which the power would decrease is

1 $5 \%$
2 $10 \%$
3 $20 \%$
4 $2.5 \%$
Alternating Current

154958 A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V} .50 \mathrm{~Hz}$ AC supply. The rms value of the current in the circuit is

1 $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
2 $10 \mathrm{~A}$
3 $\frac{50}{\pi} \mathrm{A}$
4 $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Alternating Current

154959 A circuit element $X$ when connected to an a.c. supply of peak voltage $100 \mathrm{~V}$ gives a peak current of $5 \mathrm{~A}$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

1 $\frac{10}{\sqrt{2}}$
2 $\frac{5}{\sqrt{2}}$
3 $5 \sqrt{2}$
4 $\frac{5}{2}$
Alternating Current

154960 A $100 \mu \mathrm{F}$ capacitor is connected to a $100 \mathrm{~V}, 50$ $\mathrm{Hz}$ AC supply. The rms value of the current is

1 $3.14 \mathrm{~A}$
2 $4.75 \mathrm{~A}$
3 $2.33 \mathrm{~A}$
4 $5.5 \mathrm{~A}$
Alternating Current

154961 An alternating current is given by $i=i_{1} \cos \omega t+$ $i_{2} \sin \omega t$. The rms current is given by:

1 $\frac{i_{1}+i_{2}}{\sqrt{2}}$
2 $\frac{i_{2}-i_{1}}{\sqrt{2}}$
3 $\sqrt{\left(\frac{\dot{i}_{1}^{2}+i_{2}^{2}}{2}\right)}$
4 $\sqrt{\left(\frac{\dot{i}_{1}^{2}-i_{2}^{2}}{2}\right)}$