153884
The maximum velocity to which a proton can be accelerated in a cyclotron of $10 \mathrm{MHz}$ frequency and radius $50 \mathrm{~cm}$ is
1 $6.28 \times 10^{8} \mathrm{~m} / \mathrm{s}$
2 $3.14 \times 10^{8} \mathrm{~m} / \mathrm{s}$
3 $6.28 \times 10^{7} \mathrm{~m} / \mathrm{s}$
4 $3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
Explanation:
D Given, $\mathrm{r}=50 \mathrm{~cm}=50 \times 10^{-2} \mathrm{~m}, \mathrm{f}=10 \mathrm{MHz}=$ $10 \times 10^{6} \mathrm{~Hz}$ The motion of proton in magnetic field will be $\mathrm{v}=2 \pi \mathrm{rf}$ $\mathrm{v}=2 \times 3.14 \times 50 \times 10^{-2} \times 10 \times 10^{6}$ $\mathrm{v}=3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
AMU-2010
Moving Charges & Magnetism
153885
A cyclotron is operated at a oscillator frequency of $24 \mathrm{MHz}$ and has a dee radius of 60 $\mathrm{cm}$. Find the magnitude of the magnetic field needed for deuterons to be accelerated in the cyclotron
153858
In cyclotron, the frequency of revolution of the charged particle in a magnetic field is independent of
1 its mass
2 its energy
3 oscillatory frequency (d)
4 magnetic field
5 its charge
Explanation:
B Cyclotron uses the fact that the frequency of revolution of the charged particle in a magnetic field is independent of its energy.
Kerala CEE 2021
Moving Charges & Magnetism
153859
The particle that cannot be accelerated by a cyclotron is
1 proton
2 $\alpha$-particle
3 electron
4 deuteron nucleus
Explanation:
C Electron is subatomic particles that revolve around the nucleus of an atom in orbits. A cyclotron is a device used to accelerated positively charged particles. So, electron is the particle that cannot be accelerated by a cyclotron.
153884
The maximum velocity to which a proton can be accelerated in a cyclotron of $10 \mathrm{MHz}$ frequency and radius $50 \mathrm{~cm}$ is
1 $6.28 \times 10^{8} \mathrm{~m} / \mathrm{s}$
2 $3.14 \times 10^{8} \mathrm{~m} / \mathrm{s}$
3 $6.28 \times 10^{7} \mathrm{~m} / \mathrm{s}$
4 $3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
Explanation:
D Given, $\mathrm{r}=50 \mathrm{~cm}=50 \times 10^{-2} \mathrm{~m}, \mathrm{f}=10 \mathrm{MHz}=$ $10 \times 10^{6} \mathrm{~Hz}$ The motion of proton in magnetic field will be $\mathrm{v}=2 \pi \mathrm{rf}$ $\mathrm{v}=2 \times 3.14 \times 50 \times 10^{-2} \times 10 \times 10^{6}$ $\mathrm{v}=3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
AMU-2010
Moving Charges & Magnetism
153885
A cyclotron is operated at a oscillator frequency of $24 \mathrm{MHz}$ and has a dee radius of 60 $\mathrm{cm}$. Find the magnitude of the magnetic field needed for deuterons to be accelerated in the cyclotron
153858
In cyclotron, the frequency of revolution of the charged particle in a magnetic field is independent of
1 its mass
2 its energy
3 oscillatory frequency (d)
4 magnetic field
5 its charge
Explanation:
B Cyclotron uses the fact that the frequency of revolution of the charged particle in a magnetic field is independent of its energy.
Kerala CEE 2021
Moving Charges & Magnetism
153859
The particle that cannot be accelerated by a cyclotron is
1 proton
2 $\alpha$-particle
3 electron
4 deuteron nucleus
Explanation:
C Electron is subatomic particles that revolve around the nucleus of an atom in orbits. A cyclotron is a device used to accelerated positively charged particles. So, electron is the particle that cannot be accelerated by a cyclotron.
153884
The maximum velocity to which a proton can be accelerated in a cyclotron of $10 \mathrm{MHz}$ frequency and radius $50 \mathrm{~cm}$ is
1 $6.28 \times 10^{8} \mathrm{~m} / \mathrm{s}$
2 $3.14 \times 10^{8} \mathrm{~m} / \mathrm{s}$
3 $6.28 \times 10^{7} \mathrm{~m} / \mathrm{s}$
4 $3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
Explanation:
D Given, $\mathrm{r}=50 \mathrm{~cm}=50 \times 10^{-2} \mathrm{~m}, \mathrm{f}=10 \mathrm{MHz}=$ $10 \times 10^{6} \mathrm{~Hz}$ The motion of proton in magnetic field will be $\mathrm{v}=2 \pi \mathrm{rf}$ $\mathrm{v}=2 \times 3.14 \times 50 \times 10^{-2} \times 10 \times 10^{6}$ $\mathrm{v}=3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
AMU-2010
Moving Charges & Magnetism
153885
A cyclotron is operated at a oscillator frequency of $24 \mathrm{MHz}$ and has a dee radius of 60 $\mathrm{cm}$. Find the magnitude of the magnetic field needed for deuterons to be accelerated in the cyclotron
153858
In cyclotron, the frequency of revolution of the charged particle in a magnetic field is independent of
1 its mass
2 its energy
3 oscillatory frequency (d)
4 magnetic field
5 its charge
Explanation:
B Cyclotron uses the fact that the frequency of revolution of the charged particle in a magnetic field is independent of its energy.
Kerala CEE 2021
Moving Charges & Magnetism
153859
The particle that cannot be accelerated by a cyclotron is
1 proton
2 $\alpha$-particle
3 electron
4 deuteron nucleus
Explanation:
C Electron is subatomic particles that revolve around the nucleus of an atom in orbits. A cyclotron is a device used to accelerated positively charged particles. So, electron is the particle that cannot be accelerated by a cyclotron.
153884
The maximum velocity to which a proton can be accelerated in a cyclotron of $10 \mathrm{MHz}$ frequency and radius $50 \mathrm{~cm}$ is
1 $6.28 \times 10^{8} \mathrm{~m} / \mathrm{s}$
2 $3.14 \times 10^{8} \mathrm{~m} / \mathrm{s}$
3 $6.28 \times 10^{7} \mathrm{~m} / \mathrm{s}$
4 $3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
Explanation:
D Given, $\mathrm{r}=50 \mathrm{~cm}=50 \times 10^{-2} \mathrm{~m}, \mathrm{f}=10 \mathrm{MHz}=$ $10 \times 10^{6} \mathrm{~Hz}$ The motion of proton in magnetic field will be $\mathrm{v}=2 \pi \mathrm{rf}$ $\mathrm{v}=2 \times 3.14 \times 50 \times 10^{-2} \times 10 \times 10^{6}$ $\mathrm{v}=3.14 \times 10^{7} \mathrm{~m} / \mathrm{s}$
AMU-2010
Moving Charges & Magnetism
153885
A cyclotron is operated at a oscillator frequency of $24 \mathrm{MHz}$ and has a dee radius of 60 $\mathrm{cm}$. Find the magnitude of the magnetic field needed for deuterons to be accelerated in the cyclotron
153858
In cyclotron, the frequency of revolution of the charged particle in a magnetic field is independent of
1 its mass
2 its energy
3 oscillatory frequency (d)
4 magnetic field
5 its charge
Explanation:
B Cyclotron uses the fact that the frequency of revolution of the charged particle in a magnetic field is independent of its energy.
Kerala CEE 2021
Moving Charges & Magnetism
153859
The particle that cannot be accelerated by a cyclotron is
1 proton
2 $\alpha$-particle
3 electron
4 deuteron nucleus
Explanation:
C Electron is subatomic particles that revolve around the nucleus of an atom in orbits. A cyclotron is a device used to accelerated positively charged particles. So, electron is the particle that cannot be accelerated by a cyclotron.
