06. Measuring Instrument (Meter Bridge, Galvanometer, Ammeter, Voltmeter, Potentiometer)
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Current Electricity

152890 Unknown resistance ' $X$ ' $\Omega$ is connected in the left gap of meterbridge and $30 \Omega$ resistance is connected in the right gap of meterbridge. Balance point is obtained in the middle of the wire. Where will be the null point if $40 \Omega$ resistance is used in right gap, keeping ' $\mathrm{X}$ ' in the left gap?

1 $42.8 \mathrm{~cm}$
2 $50 \mathrm{~cm}$
3 $66.6 \mathrm{~cm}$
4 $62.8 \mathrm{~cm}$
MHT-CET 2019
Current Electricity

152892 In the network shown cell ' $E$ ' has internal resistance ' $r$ ' and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf ' $2 E$ ' and internal resistance ' $3 r$ ' keeping everything else identical then

1 the galvanometer will show zero deflection
2 current will flow from B to A
3 the galvanometer will show deflection of 10 divisions
4 current will flow from A to B
MHT-CET 2019
Current Electricity

152893 A potentiometer wire has length ' $L$ '. For given cell of e.m.f. ' $E$ ', the balancing length is ' $L / 3$ ' from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$ then for the same cell, the balance point is obtained at length

1 $\frac{\mathrm{L}}{2}$ from the positive end
2 $\frac{\mathrm{L}}{3}$ from the positive end
3 $\frac{\mathrm{L}}{5}$ from positive end
4 $\frac{\mathrm{L}}{4}$ from the positive end
MHT-CET 2019
Current Electricity

152894 With a resistance of ' $X$ ' in the left gap and a resistance of $9 \Omega$ in the right gap of a meter bridge, the balance point is obtained at $40 \mathrm{~cm}$ from the left end. In what way and to which resistance $3 \Omega$ resistance be connected to obtain the balance at $50 \mathrm{~cm}$ from the left end ?

1 in series with $9 \Omega$
2 parallel to $9 \Omega$
3 parallel to $\mathrm{X} \Omega$
4 In series with $\mathrm{X} \Omega$
MHT-CET 2019
Current Electricity

152895 The current in $1 \Omega$ resistor in the following circuit is

1 $1 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $0.5 \mathrm{~A}$
4 $1.1 \mathrm{~A}$
MHT-CET 2019
NEET DIGITAL LIBRARY
Current Electricity

152890 Unknown resistance ' $X$ ' $\Omega$ is connected in the left gap of meterbridge and $30 \Omega$ resistance is connected in the right gap of meterbridge. Balance point is obtained in the middle of the wire. Where will be the null point if $40 \Omega$ resistance is used in right gap, keeping ' $\mathrm{X}$ ' in the left gap?

1 $42.8 \mathrm{~cm}$
2 $50 \mathrm{~cm}$
3 $66.6 \mathrm{~cm}$
4 $62.8 \mathrm{~cm}$
MHT-CET 2019
Current Electricity

152892 In the network shown cell ' $E$ ' has internal resistance ' $r$ ' and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf ' $2 E$ ' and internal resistance ' $3 r$ ' keeping everything else identical then

1 the galvanometer will show zero deflection
2 current will flow from B to A
3 the galvanometer will show deflection of 10 divisions
4 current will flow from A to B
MHT-CET 2019
Current Electricity

152893 A potentiometer wire has length ' $L$ '. For given cell of e.m.f. ' $E$ ', the balancing length is ' $L / 3$ ' from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$ then for the same cell, the balance point is obtained at length

1 $\frac{\mathrm{L}}{2}$ from the positive end
2 $\frac{\mathrm{L}}{3}$ from the positive end
3 $\frac{\mathrm{L}}{5}$ from positive end
4 $\frac{\mathrm{L}}{4}$ from the positive end
MHT-CET 2019
Current Electricity

152894 With a resistance of ' $X$ ' in the left gap and a resistance of $9 \Omega$ in the right gap of a meter bridge, the balance point is obtained at $40 \mathrm{~cm}$ from the left end. In what way and to which resistance $3 \Omega$ resistance be connected to obtain the balance at $50 \mathrm{~cm}$ from the left end ?

1 in series with $9 \Omega$
2 parallel to $9 \Omega$
3 parallel to $\mathrm{X} \Omega$
4 In series with $\mathrm{X} \Omega$
MHT-CET 2019
Current Electricity

152895 The current in $1 \Omega$ resistor in the following circuit is

1 $1 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $0.5 \mathrm{~A}$
4 $1.1 \mathrm{~A}$
MHT-CET 2019
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Current Electricity

152890 Unknown resistance ' $X$ ' $\Omega$ is connected in the left gap of meterbridge and $30 \Omega$ resistance is connected in the right gap of meterbridge. Balance point is obtained in the middle of the wire. Where will be the null point if $40 \Omega$ resistance is used in right gap, keeping ' $\mathrm{X}$ ' in the left gap?

1 $42.8 \mathrm{~cm}$
2 $50 \mathrm{~cm}$
3 $66.6 \mathrm{~cm}$
4 $62.8 \mathrm{~cm}$
MHT-CET 2019
Current Electricity

152892 In the network shown cell ' $E$ ' has internal resistance ' $r$ ' and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf ' $2 E$ ' and internal resistance ' $3 r$ ' keeping everything else identical then

1 the galvanometer will show zero deflection
2 current will flow from B to A
3 the galvanometer will show deflection of 10 divisions
4 current will flow from A to B
MHT-CET 2019
Current Electricity

152893 A potentiometer wire has length ' $L$ '. For given cell of e.m.f. ' $E$ ', the balancing length is ' $L / 3$ ' from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$ then for the same cell, the balance point is obtained at length

1 $\frac{\mathrm{L}}{2}$ from the positive end
2 $\frac{\mathrm{L}}{3}$ from the positive end
3 $\frac{\mathrm{L}}{5}$ from positive end
4 $\frac{\mathrm{L}}{4}$ from the positive end
MHT-CET 2019
Current Electricity

152894 With a resistance of ' $X$ ' in the left gap and a resistance of $9 \Omega$ in the right gap of a meter bridge, the balance point is obtained at $40 \mathrm{~cm}$ from the left end. In what way and to which resistance $3 \Omega$ resistance be connected to obtain the balance at $50 \mathrm{~cm}$ from the left end ?

1 in series with $9 \Omega$
2 parallel to $9 \Omega$
3 parallel to $\mathrm{X} \Omega$
4 In series with $\mathrm{X} \Omega$
MHT-CET 2019
Current Electricity

152895 The current in $1 \Omega$ resistor in the following circuit is

1 $1 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $0.5 \mathrm{~A}$
4 $1.1 \mathrm{~A}$
MHT-CET 2019
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Current Electricity

152890 Unknown resistance ' $X$ ' $\Omega$ is connected in the left gap of meterbridge and $30 \Omega$ resistance is connected in the right gap of meterbridge. Balance point is obtained in the middle of the wire. Where will be the null point if $40 \Omega$ resistance is used in right gap, keeping ' $\mathrm{X}$ ' in the left gap?

1 $42.8 \mathrm{~cm}$
2 $50 \mathrm{~cm}$
3 $66.6 \mathrm{~cm}$
4 $62.8 \mathrm{~cm}$
MHT-CET 2019
Current Electricity

152892 In the network shown cell ' $E$ ' has internal resistance ' $r$ ' and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf ' $2 E$ ' and internal resistance ' $3 r$ ' keeping everything else identical then

1 the galvanometer will show zero deflection
2 current will flow from B to A
3 the galvanometer will show deflection of 10 divisions
4 current will flow from A to B
MHT-CET 2019
Current Electricity

152893 A potentiometer wire has length ' $L$ '. For given cell of e.m.f. ' $E$ ', the balancing length is ' $L / 3$ ' from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$ then for the same cell, the balance point is obtained at length

1 $\frac{\mathrm{L}}{2}$ from the positive end
2 $\frac{\mathrm{L}}{3}$ from the positive end
3 $\frac{\mathrm{L}}{5}$ from positive end
4 $\frac{\mathrm{L}}{4}$ from the positive end
MHT-CET 2019
Current Electricity

152894 With a resistance of ' $X$ ' in the left gap and a resistance of $9 \Omega$ in the right gap of a meter bridge, the balance point is obtained at $40 \mathrm{~cm}$ from the left end. In what way and to which resistance $3 \Omega$ resistance be connected to obtain the balance at $50 \mathrm{~cm}$ from the left end ?

1 in series with $9 \Omega$
2 parallel to $9 \Omega$
3 parallel to $\mathrm{X} \Omega$
4 In series with $\mathrm{X} \Omega$
MHT-CET 2019
Current Electricity

152895 The current in $1 \Omega$ resistor in the following circuit is

1 $1 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $0.5 \mathrm{~A}$
4 $1.1 \mathrm{~A}$
MHT-CET 2019
NEET DIGITAL LIBRARY
Current Electricity

152890 Unknown resistance ' $X$ ' $\Omega$ is connected in the left gap of meterbridge and $30 \Omega$ resistance is connected in the right gap of meterbridge. Balance point is obtained in the middle of the wire. Where will be the null point if $40 \Omega$ resistance is used in right gap, keeping ' $\mathrm{X}$ ' in the left gap?

1 $42.8 \mathrm{~cm}$
2 $50 \mathrm{~cm}$
3 $66.6 \mathrm{~cm}$
4 $62.8 \mathrm{~cm}$
MHT-CET 2019
Current Electricity

152892 In the network shown cell ' $E$ ' has internal resistance ' $r$ ' and the galvanometer shows zero deflection. If the cell is replaced by a new cell of emf ' $2 E$ ' and internal resistance ' $3 r$ ' keeping everything else identical then

1 the galvanometer will show zero deflection
2 current will flow from B to A
3 the galvanometer will show deflection of 10 divisions
4 current will flow from A to B
MHT-CET 2019
Current Electricity

152893 A potentiometer wire has length ' $L$ '. For given cell of e.m.f. ' $E$ ', the balancing length is ' $L / 3$ ' from the positive end of the wire. If the length of potentiometer wire is increased by $50 \%$ then for the same cell, the balance point is obtained at length

1 $\frac{\mathrm{L}}{2}$ from the positive end
2 $\frac{\mathrm{L}}{3}$ from the positive end
3 $\frac{\mathrm{L}}{5}$ from positive end
4 $\frac{\mathrm{L}}{4}$ from the positive end
MHT-CET 2019
Current Electricity

152894 With a resistance of ' $X$ ' in the left gap and a resistance of $9 \Omega$ in the right gap of a meter bridge, the balance point is obtained at $40 \mathrm{~cm}$ from the left end. In what way and to which resistance $3 \Omega$ resistance be connected to obtain the balance at $50 \mathrm{~cm}$ from the left end ?

1 in series with $9 \Omega$
2 parallel to $9 \Omega$
3 parallel to $\mathrm{X} \Omega$
4 In series with $\mathrm{X} \Omega$
MHT-CET 2019
Current Electricity

152895 The current in $1 \Omega$ resistor in the following circuit is

1 $1 \mathrm{~A}$
2 $0.8 \mathrm{~A}$
3 $0.5 \mathrm{~A}$
4 $1.1 \mathrm{~A}$
MHT-CET 2019