04. Cells, Internal Resistance and Cell Combination, Thermocouple
Current Electricity

152576 When a battery connected across a resistor of $16 \Omega$, the voltage across the resistor is $12 \mathrm{~V}$. When the same battery is connected across a resistor of $10 \Omega$, voltage across it is $11 \mathrm{~V}$. The internal resistance of the battery in $\mathrm{ohm}$ is

1 $\frac{10}{7}$
2 $\frac{20}{7}$
3 $\frac{25}{7}$
4 $\frac{30}{7}$
Current Electricity

152577 A battery of constant voltage is available. How to adjust a system of three identical capacitors to get high electrostatic energy with the given battery?

1 Three in parallel
2 Whatever may be combination, it will always have same electrostatic energy
3 Two parallel and one in series
4 Three in series
Current Electricity

152578 For driving current of $2 \mathrm{~A}$ for $6 \mathrm{~min}$ in a circuit, $1000 \mathrm{~J}$ of work is to be done. The emf of the source in the circuit is :

1 $2.03 \mathrm{~V}$
2 $2.54 \mathrm{~V}$
3 $1.25 \mathrm{~V}$
4 $1.39 \mathrm{~V}$
Current Electricity

152579 Under what conditions current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_{2}$ ? The internal resistances of the two batteries are $r_{1}$ and $r_{2}$ respectively.

1 $\mathrm{E}_{2} \mathrm{r}_{1}>\mathrm{E}_{1}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
2 $\mathrm{E}_{1} \mathrm{r}_{2}\lt\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
3 $\mathrm{E}_{2} \mathrm{r}_{2}\lt\mathrm{E}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
4 $\mathrm{E}_{1} \mathrm{r}_{1}>\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
Current Electricity

152580 A voltmeter of resistance $998 \Omega$ is connected across a cell of emf $2 \mathrm{~V}$ and internal resistance $2 \Omega$. The potential difference across the voltmeter is

1 $1.99 \mathrm{~V}$
2 $3.5 \mathrm{~V}$
3 $5 \mathrm{~V}$
4 $6 \mathrm{~V}$
Current Electricity

152576 When a battery connected across a resistor of $16 \Omega$, the voltage across the resistor is $12 \mathrm{~V}$. When the same battery is connected across a resistor of $10 \Omega$, voltage across it is $11 \mathrm{~V}$. The internal resistance of the battery in $\mathrm{ohm}$ is

1 $\frac{10}{7}$
2 $\frac{20}{7}$
3 $\frac{25}{7}$
4 $\frac{30}{7}$
Current Electricity

152577 A battery of constant voltage is available. How to adjust a system of three identical capacitors to get high electrostatic energy with the given battery?

1 Three in parallel
2 Whatever may be combination, it will always have same electrostatic energy
3 Two parallel and one in series
4 Three in series
Current Electricity

152578 For driving current of $2 \mathrm{~A}$ for $6 \mathrm{~min}$ in a circuit, $1000 \mathrm{~J}$ of work is to be done. The emf of the source in the circuit is :

1 $2.03 \mathrm{~V}$
2 $2.54 \mathrm{~V}$
3 $1.25 \mathrm{~V}$
4 $1.39 \mathrm{~V}$
Current Electricity

152579 Under what conditions current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_{2}$ ? The internal resistances of the two batteries are $r_{1}$ and $r_{2}$ respectively.

1 $\mathrm{E}_{2} \mathrm{r}_{1}>\mathrm{E}_{1}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
2 $\mathrm{E}_{1} \mathrm{r}_{2}\lt\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
3 $\mathrm{E}_{2} \mathrm{r}_{2}\lt\mathrm{E}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
4 $\mathrm{E}_{1} \mathrm{r}_{1}>\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
Current Electricity

152580 A voltmeter of resistance $998 \Omega$ is connected across a cell of emf $2 \mathrm{~V}$ and internal resistance $2 \Omega$. The potential difference across the voltmeter is

1 $1.99 \mathrm{~V}$
2 $3.5 \mathrm{~V}$
3 $5 \mathrm{~V}$
4 $6 \mathrm{~V}$
Current Electricity

152576 When a battery connected across a resistor of $16 \Omega$, the voltage across the resistor is $12 \mathrm{~V}$. When the same battery is connected across a resistor of $10 \Omega$, voltage across it is $11 \mathrm{~V}$. The internal resistance of the battery in $\mathrm{ohm}$ is

1 $\frac{10}{7}$
2 $\frac{20}{7}$
3 $\frac{25}{7}$
4 $\frac{30}{7}$
Current Electricity

152577 A battery of constant voltage is available. How to adjust a system of three identical capacitors to get high electrostatic energy with the given battery?

1 Three in parallel
2 Whatever may be combination, it will always have same electrostatic energy
3 Two parallel and one in series
4 Three in series
Current Electricity

152578 For driving current of $2 \mathrm{~A}$ for $6 \mathrm{~min}$ in a circuit, $1000 \mathrm{~J}$ of work is to be done. The emf of the source in the circuit is :

1 $2.03 \mathrm{~V}$
2 $2.54 \mathrm{~V}$
3 $1.25 \mathrm{~V}$
4 $1.39 \mathrm{~V}$
Current Electricity

152579 Under what conditions current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_{2}$ ? The internal resistances of the two batteries are $r_{1}$ and $r_{2}$ respectively.

1 $\mathrm{E}_{2} \mathrm{r}_{1}>\mathrm{E}_{1}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
2 $\mathrm{E}_{1} \mathrm{r}_{2}\lt\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
3 $\mathrm{E}_{2} \mathrm{r}_{2}\lt\mathrm{E}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
4 $\mathrm{E}_{1} \mathrm{r}_{1}>\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
Current Electricity

152580 A voltmeter of resistance $998 \Omega$ is connected across a cell of emf $2 \mathrm{~V}$ and internal resistance $2 \Omega$. The potential difference across the voltmeter is

1 $1.99 \mathrm{~V}$
2 $3.5 \mathrm{~V}$
3 $5 \mathrm{~V}$
4 $6 \mathrm{~V}$
Current Electricity

152576 When a battery connected across a resistor of $16 \Omega$, the voltage across the resistor is $12 \mathrm{~V}$. When the same battery is connected across a resistor of $10 \Omega$, voltage across it is $11 \mathrm{~V}$. The internal resistance of the battery in $\mathrm{ohm}$ is

1 $\frac{10}{7}$
2 $\frac{20}{7}$
3 $\frac{25}{7}$
4 $\frac{30}{7}$
Current Electricity

152577 A battery of constant voltage is available. How to adjust a system of three identical capacitors to get high electrostatic energy with the given battery?

1 Three in parallel
2 Whatever may be combination, it will always have same electrostatic energy
3 Two parallel and one in series
4 Three in series
Current Electricity

152578 For driving current of $2 \mathrm{~A}$ for $6 \mathrm{~min}$ in a circuit, $1000 \mathrm{~J}$ of work is to be done. The emf of the source in the circuit is :

1 $2.03 \mathrm{~V}$
2 $2.54 \mathrm{~V}$
3 $1.25 \mathrm{~V}$
4 $1.39 \mathrm{~V}$
Current Electricity

152579 Under what conditions current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_{2}$ ? The internal resistances of the two batteries are $r_{1}$ and $r_{2}$ respectively.

1 $\mathrm{E}_{2} \mathrm{r}_{1}>\mathrm{E}_{1}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
2 $\mathrm{E}_{1} \mathrm{r}_{2}\lt\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
3 $\mathrm{E}_{2} \mathrm{r}_{2}\lt\mathrm{E}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
4 $\mathrm{E}_{1} \mathrm{r}_{1}>\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
Current Electricity

152580 A voltmeter of resistance $998 \Omega$ is connected across a cell of emf $2 \mathrm{~V}$ and internal resistance $2 \Omega$. The potential difference across the voltmeter is

1 $1.99 \mathrm{~V}$
2 $3.5 \mathrm{~V}$
3 $5 \mathrm{~V}$
4 $6 \mathrm{~V}$
Current Electricity

152576 When a battery connected across a resistor of $16 \Omega$, the voltage across the resistor is $12 \mathrm{~V}$. When the same battery is connected across a resistor of $10 \Omega$, voltage across it is $11 \mathrm{~V}$. The internal resistance of the battery in $\mathrm{ohm}$ is

1 $\frac{10}{7}$
2 $\frac{20}{7}$
3 $\frac{25}{7}$
4 $\frac{30}{7}$
Current Electricity

152577 A battery of constant voltage is available. How to adjust a system of three identical capacitors to get high electrostatic energy with the given battery?

1 Three in parallel
2 Whatever may be combination, it will always have same electrostatic energy
3 Two parallel and one in series
4 Three in series
Current Electricity

152578 For driving current of $2 \mathrm{~A}$ for $6 \mathrm{~min}$ in a circuit, $1000 \mathrm{~J}$ of work is to be done. The emf of the source in the circuit is :

1 $2.03 \mathrm{~V}$
2 $2.54 \mathrm{~V}$
3 $1.25 \mathrm{~V}$
4 $1.39 \mathrm{~V}$
Current Electricity

152579 Under what conditions current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_{2}$ ? The internal resistances of the two batteries are $r_{1}$ and $r_{2}$ respectively.

1 $\mathrm{E}_{2} \mathrm{r}_{1}>\mathrm{E}_{1}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
2 $\mathrm{E}_{1} \mathrm{r}_{2}\lt\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
3 $\mathrm{E}_{2} \mathrm{r}_{2}\lt\mathrm{E}\left(\mathrm{R}+\mathrm{r}_{2}\right)$
4 $\mathrm{E}_{1} \mathrm{r}_{1}>\mathrm{E}_{2}\left(\mathrm{r}_{1}+\mathrm{R}\right)$
Current Electricity

152580 A voltmeter of resistance $998 \Omega$ is connected across a cell of emf $2 \mathrm{~V}$ and internal resistance $2 \Omega$. The potential difference across the voltmeter is

1 $1.99 \mathrm{~V}$
2 $3.5 \mathrm{~V}$
3 $5 \mathrm{~V}$
4 $6 \mathrm{~V}$