04. Cells, Internal Resistance and Cell Combination, Thermocouple
Current Electricity

152515 A carbon resistor of $(47 \pm 4.7) \mathrm{k} \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be

1 Yellow - Green - Violet - Gold
2 Yellow - Violet - Orange - Silver
3 Violet - Yellow - Orange - Silver
4 Green - Orange - Violet - Gold
Current Electricity

152516 Two cells, having the same emf are connected in series through an external resistance $R$. Cells have internal resistances $r_{1}$ and $r_{2} \quad\left(r_{1}>\right.$ $\left.r_{2}\right)$ respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of $R$ is

1 $r_{1}-r_{2}$
2 $\frac{r_{1}+r_{2}}{2}$
3 $\frac{r_{1}-r_{2}}{2}$
4 $r_{1}+r_{2}$
Current Electricity

152517 The resistance of the platinum wire of a platinum resistance thermometer at the ice point is $5 \Omega$ and at steam point is $5.23 \Omega$. When the thermometer is inserted in a hot bath, the resistance of the platinum wire will be $5.795 \Omega$. Calculate the temperature of the bath.

1 $3.456{ }^{\circ} \mathrm{C}$
2 $34.565^{\circ} \mathrm{C}$
3 $345.65^{\circ} \mathrm{C}$
4 $45.65^{\circ} \mathrm{C}$
Current Electricity

152518 A resistance $R$ is connected to ' $n$ ' identical cells. If the current in the resistance is same whether the cells are connected either in series or in parallel, then the internal resistance $(r)$ of each cell is

1 $r=\frac{R}{n}$
2 $\mathrm{r}=\mathrm{nR}$
3 $\mathrm{r}=\mathrm{R}$
4 $\quad r=\frac{1}{R}$
Current Electricity

152515 A carbon resistor of $(47 \pm 4.7) \mathrm{k} \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be

1 Yellow - Green - Violet - Gold
2 Yellow - Violet - Orange - Silver
3 Violet - Yellow - Orange - Silver
4 Green - Orange - Violet - Gold
Current Electricity

152516 Two cells, having the same emf are connected in series through an external resistance $R$. Cells have internal resistances $r_{1}$ and $r_{2} \quad\left(r_{1}>\right.$ $\left.r_{2}\right)$ respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of $R$ is

1 $r_{1}-r_{2}$
2 $\frac{r_{1}+r_{2}}{2}$
3 $\frac{r_{1}-r_{2}}{2}$
4 $r_{1}+r_{2}$
Current Electricity

152517 The resistance of the platinum wire of a platinum resistance thermometer at the ice point is $5 \Omega$ and at steam point is $5.23 \Omega$. When the thermometer is inserted in a hot bath, the resistance of the platinum wire will be $5.795 \Omega$. Calculate the temperature of the bath.

1 $3.456{ }^{\circ} \mathrm{C}$
2 $34.565^{\circ} \mathrm{C}$
3 $345.65^{\circ} \mathrm{C}$
4 $45.65^{\circ} \mathrm{C}$
Current Electricity

152518 A resistance $R$ is connected to ' $n$ ' identical cells. If the current in the resistance is same whether the cells are connected either in series or in parallel, then the internal resistance $(r)$ of each cell is

1 $r=\frac{R}{n}$
2 $\mathrm{r}=\mathrm{nR}$
3 $\mathrm{r}=\mathrm{R}$
4 $\quad r=\frac{1}{R}$
Current Electricity

152515 A carbon resistor of $(47 \pm 4.7) \mathrm{k} \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be

1 Yellow - Green - Violet - Gold
2 Yellow - Violet - Orange - Silver
3 Violet - Yellow - Orange - Silver
4 Green - Orange - Violet - Gold
Current Electricity

152516 Two cells, having the same emf are connected in series through an external resistance $R$. Cells have internal resistances $r_{1}$ and $r_{2} \quad\left(r_{1}>\right.$ $\left.r_{2}\right)$ respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of $R$ is

1 $r_{1}-r_{2}$
2 $\frac{r_{1}+r_{2}}{2}$
3 $\frac{r_{1}-r_{2}}{2}$
4 $r_{1}+r_{2}$
Current Electricity

152517 The resistance of the platinum wire of a platinum resistance thermometer at the ice point is $5 \Omega$ and at steam point is $5.23 \Omega$. When the thermometer is inserted in a hot bath, the resistance of the platinum wire will be $5.795 \Omega$. Calculate the temperature of the bath.

1 $3.456{ }^{\circ} \mathrm{C}$
2 $34.565^{\circ} \mathrm{C}$
3 $345.65^{\circ} \mathrm{C}$
4 $45.65^{\circ} \mathrm{C}$
Current Electricity

152518 A resistance $R$ is connected to ' $n$ ' identical cells. If the current in the resistance is same whether the cells are connected either in series or in parallel, then the internal resistance $(r)$ of each cell is

1 $r=\frac{R}{n}$
2 $\mathrm{r}=\mathrm{nR}$
3 $\mathrm{r}=\mathrm{R}$
4 $\quad r=\frac{1}{R}$
Current Electricity

152515 A carbon resistor of $(47 \pm 4.7) \mathrm{k} \Omega$ is to be marked with rings of different colours for its identification. The colour code sequence will be

1 Yellow - Green - Violet - Gold
2 Yellow - Violet - Orange - Silver
3 Violet - Yellow - Orange - Silver
4 Green - Orange - Violet - Gold
Current Electricity

152516 Two cells, having the same emf are connected in series through an external resistance $R$. Cells have internal resistances $r_{1}$ and $r_{2} \quad\left(r_{1}>\right.$ $\left.r_{2}\right)$ respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of $R$ is

1 $r_{1}-r_{2}$
2 $\frac{r_{1}+r_{2}}{2}$
3 $\frac{r_{1}-r_{2}}{2}$
4 $r_{1}+r_{2}$
Current Electricity

152517 The resistance of the platinum wire of a platinum resistance thermometer at the ice point is $5 \Omega$ and at steam point is $5.23 \Omega$. When the thermometer is inserted in a hot bath, the resistance of the platinum wire will be $5.795 \Omega$. Calculate the temperature of the bath.

1 $3.456{ }^{\circ} \mathrm{C}$
2 $34.565^{\circ} \mathrm{C}$
3 $345.65^{\circ} \mathrm{C}$
4 $45.65^{\circ} \mathrm{C}$
Current Electricity

152518 A resistance $R$ is connected to ' $n$ ' identical cells. If the current in the resistance is same whether the cells are connected either in series or in parallel, then the internal resistance $(r)$ of each cell is

1 $r=\frac{R}{n}$
2 $\mathrm{r}=\mathrm{nR}$
3 $\mathrm{r}=\mathrm{R}$
4 $\quad r=\frac{1}{R}$