02. Resistivity
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Current Electricity

152158 Find the resistance of a hollow cylindrical conductor of length $1.0 \mathrm{~mm}$ and $2.0 \mathrm{~mm}$ respectively. The resistivity of the material is $2.0 \times 10^{-8} \Omega \mathrm{m}$.

1 $2.1 \times 10^{-3} \Omega$
2 $1.3 \times 10^{-4} \Omega$
3 $3.2 \times 10^{-4} \Omega$
4 $4.6 \times 10^{-2} \Omega$
Current Electricity

152159 Wires $A$ and $B$ have resistivities $\rho_{A}$ and $\rho_{B},\left(\rho_{B}\right.$ $=2 \rho_{\mathrm{A}}$ ) and have lengths $l_{\mathrm{A}}$ and $l_{\mathrm{B}}$. If the diameter of the wire $B$ is twice that of $A$ and the two wires have same resistance, then $\frac{l_{\mathrm{B}}}{l_{\mathrm{A}}}$ is

1 2
2 1
3 $\frac{1}{2}$
4 $\frac{1}{4}$
Current Electricity

152160 The specific resistance of a wire is $\rho$, its volume is $3 \mathrm{~m}^{3}$ and its resistance is $3 \Omega$, then its length will be-

1 $\frac{3}{\sqrt{\rho}}$
2 $\frac{\sqrt{3}}{\rho}$
3 $\frac{5}{\sqrt{\rho}}$
4 $\frac{\sqrt{5}}{\rho}$
Current Electricity

152161 A certain electrical conductor has a square cross-section, $2.0 \mathrm{~mm}$ on a side, and is $12 \mathrm{~m}$ long. The resistance between its ends is $0.072 \Omega$. The resistivity of its material is equal to

1 $2.4 \times 10^{-6} \Omega \mathrm{m}$
2 $1.2 \times 10^{-6} \Omega \mathrm{m}$
3 $1.2 \times 10^{-8} \Omega \mathrm{m}$
4 $2.4 \times 10^{-8} \Omega \mathrm{m}$
Current Electricity

152158 Find the resistance of a hollow cylindrical conductor of length $1.0 \mathrm{~mm}$ and $2.0 \mathrm{~mm}$ respectively. The resistivity of the material is $2.0 \times 10^{-8} \Omega \mathrm{m}$.

1 $2.1 \times 10^{-3} \Omega$
2 $1.3 \times 10^{-4} \Omega$
3 $3.2 \times 10^{-4} \Omega$
4 $4.6 \times 10^{-2} \Omega$
Current Electricity

152159 Wires $A$ and $B$ have resistivities $\rho_{A}$ and $\rho_{B},\left(\rho_{B}\right.$ $=2 \rho_{\mathrm{A}}$ ) and have lengths $l_{\mathrm{A}}$ and $l_{\mathrm{B}}$. If the diameter of the wire $B$ is twice that of $A$ and the two wires have same resistance, then $\frac{l_{\mathrm{B}}}{l_{\mathrm{A}}}$ is

1 2
2 1
3 $\frac{1}{2}$
4 $\frac{1}{4}$
Current Electricity

152160 The specific resistance of a wire is $\rho$, its volume is $3 \mathrm{~m}^{3}$ and its resistance is $3 \Omega$, then its length will be-

1 $\frac{3}{\sqrt{\rho}}$
2 $\frac{\sqrt{3}}{\rho}$
3 $\frac{5}{\sqrt{\rho}}$
4 $\frac{\sqrt{5}}{\rho}$
Current Electricity

152161 A certain electrical conductor has a square cross-section, $2.0 \mathrm{~mm}$ on a side, and is $12 \mathrm{~m}$ long. The resistance between its ends is $0.072 \Omega$. The resistivity of its material is equal to

1 $2.4 \times 10^{-6} \Omega \mathrm{m}$
2 $1.2 \times 10^{-6} \Omega \mathrm{m}$
3 $1.2 \times 10^{-8} \Omega \mathrm{m}$
4 $2.4 \times 10^{-8} \Omega \mathrm{m}$
Current Electricity

152158 Find the resistance of a hollow cylindrical conductor of length $1.0 \mathrm{~mm}$ and $2.0 \mathrm{~mm}$ respectively. The resistivity of the material is $2.0 \times 10^{-8} \Omega \mathrm{m}$.

1 $2.1 \times 10^{-3} \Omega$
2 $1.3 \times 10^{-4} \Omega$
3 $3.2 \times 10^{-4} \Omega$
4 $4.6 \times 10^{-2} \Omega$
Current Electricity

152159 Wires $A$ and $B$ have resistivities $\rho_{A}$ and $\rho_{B},\left(\rho_{B}\right.$ $=2 \rho_{\mathrm{A}}$ ) and have lengths $l_{\mathrm{A}}$ and $l_{\mathrm{B}}$. If the diameter of the wire $B$ is twice that of $A$ and the two wires have same resistance, then $\frac{l_{\mathrm{B}}}{l_{\mathrm{A}}}$ is

1 2
2 1
3 $\frac{1}{2}$
4 $\frac{1}{4}$
Current Electricity

152160 The specific resistance of a wire is $\rho$, its volume is $3 \mathrm{~m}^{3}$ and its resistance is $3 \Omega$, then its length will be-

1 $\frac{3}{\sqrt{\rho}}$
2 $\frac{\sqrt{3}}{\rho}$
3 $\frac{5}{\sqrt{\rho}}$
4 $\frac{\sqrt{5}}{\rho}$
Current Electricity

152161 A certain electrical conductor has a square cross-section, $2.0 \mathrm{~mm}$ on a side, and is $12 \mathrm{~m}$ long. The resistance between its ends is $0.072 \Omega$. The resistivity of its material is equal to

1 $2.4 \times 10^{-6} \Omega \mathrm{m}$
2 $1.2 \times 10^{-6} \Omega \mathrm{m}$
3 $1.2 \times 10^{-8} \Omega \mathrm{m}$
4 $2.4 \times 10^{-8} \Omega \mathrm{m}$
Current Electricity

152158 Find the resistance of a hollow cylindrical conductor of length $1.0 \mathrm{~mm}$ and $2.0 \mathrm{~mm}$ respectively. The resistivity of the material is $2.0 \times 10^{-8} \Omega \mathrm{m}$.

1 $2.1 \times 10^{-3} \Omega$
2 $1.3 \times 10^{-4} \Omega$
3 $3.2 \times 10^{-4} \Omega$
4 $4.6 \times 10^{-2} \Omega$
Current Electricity

152159 Wires $A$ and $B$ have resistivities $\rho_{A}$ and $\rho_{B},\left(\rho_{B}\right.$ $=2 \rho_{\mathrm{A}}$ ) and have lengths $l_{\mathrm{A}}$ and $l_{\mathrm{B}}$. If the diameter of the wire $B$ is twice that of $A$ and the two wires have same resistance, then $\frac{l_{\mathrm{B}}}{l_{\mathrm{A}}}$ is

1 2
2 1
3 $\frac{1}{2}$
4 $\frac{1}{4}$
Current Electricity

152160 The specific resistance of a wire is $\rho$, its volume is $3 \mathrm{~m}^{3}$ and its resistance is $3 \Omega$, then its length will be-

1 $\frac{3}{\sqrt{\rho}}$
2 $\frac{\sqrt{3}}{\rho}$
3 $\frac{5}{\sqrt{\rho}}$
4 $\frac{\sqrt{5}}{\rho}$
Current Electricity

152161 A certain electrical conductor has a square cross-section, $2.0 \mathrm{~mm}$ on a side, and is $12 \mathrm{~m}$ long. The resistance between its ends is $0.072 \Omega$. The resistivity of its material is equal to

1 $2.4 \times 10^{-6} \Omega \mathrm{m}$
2 $1.2 \times 10^{-6} \Omega \mathrm{m}$
3 $1.2 \times 10^{-8} \Omega \mathrm{m}$
4 $2.4 \times 10^{-8} \Omega \mathrm{m}$