152144 Two wires $A$ and $B$ are of same lengths but different radii made up of copper and iron respectively. They carry same current under the same potential difference. If specific resistance of copper and iron is $1.7 \times 10^{-8} \Omega \mathrm{m}$ and $1.0 \times 10^{-7} \Omega \mathrm{m}$ respectively, the ratio of their radii $r_{B} / r_{A}$ will be

152145 Two wires of same metal have same length, but their cross-sections are in the ratio 3: 1. They are joined in series. The resistance of thicker wire is $10 \Omega$. The total resistance of the combination will be

152146 Lengths of two wires are $50 \mathrm{~cm}, 100 \mathrm{~cm}$ respectively and their diameters are $1 \mathrm{~mm}, 2$ $\mathrm{mm}$ then ratio between their specific resistances is

152147 Equal potential are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio $r$ (iron)/r (copper) of their radii must be (Given that : specific resistance of iron $=1.0 \times 10^{-7} \Omega-m$ and specific resistance of copper $=1.7 \times 10^{-8} \Omega-\mathrm{m}$ )

152144 Two wires $A$ and $B$ are of same lengths but different radii made up of copper and iron respectively. They carry same current under the same potential difference. If specific resistance of copper and iron is $1.7 \times 10^{-8} \Omega \mathrm{m}$ and $1.0 \times 10^{-7} \Omega \mathrm{m}$ respectively, the ratio of their radii $r_{B} / r_{A}$ will be

152145 Two wires of same metal have same length, but their cross-sections are in the ratio 3: 1. They are joined in series. The resistance of thicker wire is $10 \Omega$. The total resistance of the combination will be

152146 Lengths of two wires are $50 \mathrm{~cm}, 100 \mathrm{~cm}$ respectively and their diameters are $1 \mathrm{~mm}, 2$ $\mathrm{mm}$ then ratio between their specific resistances is

152147 Equal potential are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio $r$ (iron)/r (copper) of their radii must be (Given that : specific resistance of iron $=1.0 \times 10^{-7} \Omega-m$ and specific resistance of copper $=1.7 \times 10^{-8} \Omega-\mathrm{m}$ )

152144 Two wires $A$ and $B$ are of same lengths but different radii made up of copper and iron respectively. They carry same current under the same potential difference. If specific resistance of copper and iron is $1.7 \times 10^{-8} \Omega \mathrm{m}$ and $1.0 \times 10^{-7} \Omega \mathrm{m}$ respectively, the ratio of their radii $r_{B} / r_{A}$ will be

152145 Two wires of same metal have same length, but their cross-sections are in the ratio 3: 1. They are joined in series. The resistance of thicker wire is $10 \Omega$. The total resistance of the combination will be

152146 Lengths of two wires are $50 \mathrm{~cm}, 100 \mathrm{~cm}$ respectively and their diameters are $1 \mathrm{~mm}, 2$ $\mathrm{mm}$ then ratio between their specific resistances is

152147 Equal potential are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio $r$ (iron)/r (copper) of their radii must be (Given that : specific resistance of iron $=1.0 \times 10^{-7} \Omega-m$ and specific resistance of copper $=1.7 \times 10^{-8} \Omega-\mathrm{m}$ )

152144 Two wires $A$ and $B$ are of same lengths but different radii made up of copper and iron respectively. They carry same current under the same potential difference. If specific resistance of copper and iron is $1.7 \times 10^{-8} \Omega \mathrm{m}$ and $1.0 \times 10^{-7} \Omega \mathrm{m}$ respectively, the ratio of their radii $r_{B} / r_{A}$ will be

152145 Two wires of same metal have same length, but their cross-sections are in the ratio 3: 1. They are joined in series. The resistance of thicker wire is $10 \Omega$. The total resistance of the combination will be

152146 Lengths of two wires are $50 \mathrm{~cm}, 100 \mathrm{~cm}$ respectively and their diameters are $1 \mathrm{~mm}, 2$ $\mathrm{mm}$ then ratio between their specific resistances is

152147 Equal potential are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio $r$ (iron)/r (copper) of their radii must be (Given that : specific resistance of iron $=1.0 \times 10^{-7} \Omega-m$ and specific resistance of copper $=1.7 \times 10^{-8} \Omega-\mathrm{m}$ )