148559 A Carnot engine with efficiency $\eta$ operates between two heat reservoirs with temperatures $T_{1}$ and $T_{2}$, where $T_{1}>T_{2}$. If only $T_{1}$ is changed by $0.4 \%$, the change in efficiency is $\Delta \eta_{1}$, whereas if only $T_{2}$ is changed by $0.2 \%$, the efficiency is changed by $\Delta \eta_{2}$. The ratio $\frac{\Delta \eta_{1}}{\Delta \eta_{2}}$ is approximately.

148561 A Carnot engine whose efficiency is $40 \%$, receives heat at $500 \mathrm{~K}$. If the efficiency is to be $\mathbf{5 0 \%}$, the source temperature for the same exhaust temperature is

148562 A Carnot engine absorbs heat from a reservoir maintained at temperature $1000 \mathrm{~K}$. The engine rejects heat to a reservoir whose temperature is T. If the magnitude of a absorbed heat is $400 \mathrm{~J}$ and work performed is $300 \mathrm{~J}$, then the value of $T$ is

148564 A Carnot engine takes heat from a reservoir at $627^{\circ} \mathrm{C}$ and rejects heat to a sink at $27^{\circ} \mathrm{C}$. Its efficiency will be

148559 A Carnot engine with efficiency $\eta$ operates between two heat reservoirs with temperatures $T_{1}$ and $T_{2}$, where $T_{1}>T_{2}$. If only $T_{1}$ is changed by $0.4 \%$, the change in efficiency is $\Delta \eta_{1}$, whereas if only $T_{2}$ is changed by $0.2 \%$, the efficiency is changed by $\Delta \eta_{2}$. The ratio $\frac{\Delta \eta_{1}}{\Delta \eta_{2}}$ is approximately.

148561 A Carnot engine whose efficiency is $40 \%$, receives heat at $500 \mathrm{~K}$. If the efficiency is to be $\mathbf{5 0 \%}$, the source temperature for the same exhaust temperature is

148562 A Carnot engine absorbs heat from a reservoir maintained at temperature $1000 \mathrm{~K}$. The engine rejects heat to a reservoir whose temperature is T. If the magnitude of a absorbed heat is $400 \mathrm{~J}$ and work performed is $300 \mathrm{~J}$, then the value of $T$ is

148564 A Carnot engine takes heat from a reservoir at $627^{\circ} \mathrm{C}$ and rejects heat to a sink at $27^{\circ} \mathrm{C}$. Its efficiency will be

148559 A Carnot engine with efficiency $\eta$ operates between two heat reservoirs with temperatures $T_{1}$ and $T_{2}$, where $T_{1}>T_{2}$. If only $T_{1}$ is changed by $0.4 \%$, the change in efficiency is $\Delta \eta_{1}$, whereas if only $T_{2}$ is changed by $0.2 \%$, the efficiency is changed by $\Delta \eta_{2}$. The ratio $\frac{\Delta \eta_{1}}{\Delta \eta_{2}}$ is approximately.

148561 A Carnot engine whose efficiency is $40 \%$, receives heat at $500 \mathrm{~K}$. If the efficiency is to be $\mathbf{5 0 \%}$, the source temperature for the same exhaust temperature is

148562 A Carnot engine absorbs heat from a reservoir maintained at temperature $1000 \mathrm{~K}$. The engine rejects heat to a reservoir whose temperature is T. If the magnitude of a absorbed heat is $400 \mathrm{~J}$ and work performed is $300 \mathrm{~J}$, then the value of $T$ is

148564 A Carnot engine takes heat from a reservoir at $627^{\circ} \mathrm{C}$ and rejects heat to a sink at $27^{\circ} \mathrm{C}$. Its efficiency will be

148559 A Carnot engine with efficiency $\eta$ operates between two heat reservoirs with temperatures $T_{1}$ and $T_{2}$, where $T_{1}>T_{2}$. If only $T_{1}$ is changed by $0.4 \%$, the change in efficiency is $\Delta \eta_{1}$, whereas if only $T_{2}$ is changed by $0.2 \%$, the efficiency is changed by $\Delta \eta_{2}$. The ratio $\frac{\Delta \eta_{1}}{\Delta \eta_{2}}$ is approximately.

148561 A Carnot engine whose efficiency is $40 \%$, receives heat at $500 \mathrm{~K}$. If the efficiency is to be $\mathbf{5 0 \%}$, the source temperature for the same exhaust temperature is

148562 A Carnot engine absorbs heat from a reservoir maintained at temperature $1000 \mathrm{~K}$. The engine rejects heat to a reservoir whose temperature is T. If the magnitude of a absorbed heat is $400 \mathrm{~J}$ and work performed is $300 \mathrm{~J}$, then the value of $T$ is

148564 A Carnot engine takes heat from a reservoir at $627^{\circ} \mathrm{C}$ and rejects heat to a sink at $27^{\circ} \mathrm{C}$. Its efficiency will be