09. Heat Engine, Carnot’s Cycle and Refrigeration (COP)
« Previous Topic: 08. Free Expansion Process Next Topic: 10. Second Law of thermodynamics and Entropy »
Join With Us for More Updates
Thermodynamics

148525 A refrigerator with coefficient of performance $\frac{1}{3}$ releases $200 \mathrm{~J}$ of heat to a hot reservoir. Then the work done on the working substance is

1 $\frac{100}{3} \mathrm{~J}$
2 $100 \mathrm{~J}$
3 $\frac{200}{3} \mathrm{~J}$
4 $150 \mathrm{~J}$
5 $50 \mathrm{~J}$
Kerala CEE - 2010
Thermodynamics

148526 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $27^{\circ} \mathrm{C}$. If the work done by the engine when it transfers heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$, the quantity of heat absorbed by the engine from the reservoir is

1 $16.8 \times 10^{6} \mathrm{~J}$
2 $4 \times 10^{6} \mathrm{~J}$
3 $7.6 \times 10^{6} \mathrm{~J}$
4 $4.25 \times 10^{6} \mathrm{~J}$
5 $20.8 \times 10^{6} \mathrm{~J}$
AIEEE 2003
Thermodynamics

148527 A Carnot engine with sink's temperature at $17^{\circ} \mathrm{C}$ has $50 \%$ efficiency. By how much should its source temperature be changed to increase its efficiency to $60 \%$

1 $225 \mathrm{~K}$
2 $128^{\circ} \mathrm{C}$
3 $580 \mathrm{~K}$
4 $145 \mathrm{~K}$
Kerala CEE 2007
Thermodynamics

148529 In a Carnot's cycle, the working substance absorbs heat $Q_{1}$ at temperature $T_{1}$ and rejects heat $Q_{2}$ at temperature $T_{2}$. The change of entropy during the Carnot's cycle is

1 $\frac{Q_{1}}{T_{1}}$
2 $\frac{\mathrm{Q}_{2}}{\mathrm{~T}_{2}}$
3 $\frac{Q_{1}}{T_{1}}+\frac{Q_{2}}{T_{2}}$
4 Zero
UPSEE - 2011
For More Updates join with Us
Thermodynamics

148525 A refrigerator with coefficient of performance $\frac{1}{3}$ releases $200 \mathrm{~J}$ of heat to a hot reservoir. Then the work done on the working substance is

1 $\frac{100}{3} \mathrm{~J}$
2 $100 \mathrm{~J}$
3 $\frac{200}{3} \mathrm{~J}$
4 $150 \mathrm{~J}$
5 $50 \mathrm{~J}$
Kerala CEE - 2010
Thermodynamics

148526 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $27^{\circ} \mathrm{C}$. If the work done by the engine when it transfers heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$, the quantity of heat absorbed by the engine from the reservoir is

1 $16.8 \times 10^{6} \mathrm{~J}$
2 $4 \times 10^{6} \mathrm{~J}$
3 $7.6 \times 10^{6} \mathrm{~J}$
4 $4.25 \times 10^{6} \mathrm{~J}$
5 $20.8 \times 10^{6} \mathrm{~J}$
AIEEE 2003
Thermodynamics

148527 A Carnot engine with sink's temperature at $17^{\circ} \mathrm{C}$ has $50 \%$ efficiency. By how much should its source temperature be changed to increase its efficiency to $60 \%$

1 $225 \mathrm{~K}$
2 $128^{\circ} \mathrm{C}$
3 $580 \mathrm{~K}$
4 $145 \mathrm{~K}$
Kerala CEE 2007
Thermodynamics

148529 In a Carnot's cycle, the working substance absorbs heat $Q_{1}$ at temperature $T_{1}$ and rejects heat $Q_{2}$ at temperature $T_{2}$. The change of entropy during the Carnot's cycle is

1 $\frac{Q_{1}}{T_{1}}$
2 $\frac{\mathrm{Q}_{2}}{\mathrm{~T}_{2}}$
3 $\frac{Q_{1}}{T_{1}}+\frac{Q_{2}}{T_{2}}$
4 Zero
UPSEE - 2011
NEET DIGITAL LIBRARY
Thermodynamics

148525 A refrigerator with coefficient of performance $\frac{1}{3}$ releases $200 \mathrm{~J}$ of heat to a hot reservoir. Then the work done on the working substance is

1 $\frac{100}{3} \mathrm{~J}$
2 $100 \mathrm{~J}$
3 $\frac{200}{3} \mathrm{~J}$
4 $150 \mathrm{~J}$
5 $50 \mathrm{~J}$
Kerala CEE - 2010
Thermodynamics

148526 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $27^{\circ} \mathrm{C}$. If the work done by the engine when it transfers heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$, the quantity of heat absorbed by the engine from the reservoir is

1 $16.8 \times 10^{6} \mathrm{~J}$
2 $4 \times 10^{6} \mathrm{~J}$
3 $7.6 \times 10^{6} \mathrm{~J}$
4 $4.25 \times 10^{6} \mathrm{~J}$
5 $20.8 \times 10^{6} \mathrm{~J}$
AIEEE 2003
Thermodynamics

148527 A Carnot engine with sink's temperature at $17^{\circ} \mathrm{C}$ has $50 \%$ efficiency. By how much should its source temperature be changed to increase its efficiency to $60 \%$

1 $225 \mathrm{~K}$
2 $128^{\circ} \mathrm{C}$
3 $580 \mathrm{~K}$
4 $145 \mathrm{~K}$
Kerala CEE 2007
Thermodynamics

148529 In a Carnot's cycle, the working substance absorbs heat $Q_{1}$ at temperature $T_{1}$ and rejects heat $Q_{2}$ at temperature $T_{2}$. The change of entropy during the Carnot's cycle is

1 $\frac{Q_{1}}{T_{1}}$
2 $\frac{\mathrm{Q}_{2}}{\mathrm{~T}_{2}}$
3 $\frac{Q_{1}}{T_{1}}+\frac{Q_{2}}{T_{2}}$
4 Zero
UPSEE - 2011
Join With Us for More Updates
Thermodynamics

148525 A refrigerator with coefficient of performance $\frac{1}{3}$ releases $200 \mathrm{~J}$ of heat to a hot reservoir. Then the work done on the working substance is

1 $\frac{100}{3} \mathrm{~J}$
2 $100 \mathrm{~J}$
3 $\frac{200}{3} \mathrm{~J}$
4 $150 \mathrm{~J}$
5 $50 \mathrm{~J}$
Kerala CEE - 2010
Thermodynamics

148526 In a Carnot engine, the temperature of reservoir is $927^{\circ} \mathrm{C}$ and that of sink is $27^{\circ} \mathrm{C}$. If the work done by the engine when it transfers heat from reservoir to sink is $12.6 \times 10^{6} \mathrm{~J}$, the quantity of heat absorbed by the engine from the reservoir is

1 $16.8 \times 10^{6} \mathrm{~J}$
2 $4 \times 10^{6} \mathrm{~J}$
3 $7.6 \times 10^{6} \mathrm{~J}$
4 $4.25 \times 10^{6} \mathrm{~J}$
5 $20.8 \times 10^{6} \mathrm{~J}$
AIEEE 2003
Thermodynamics

148527 A Carnot engine with sink's temperature at $17^{\circ} \mathrm{C}$ has $50 \%$ efficiency. By how much should its source temperature be changed to increase its efficiency to $60 \%$

1 $225 \mathrm{~K}$
2 $128^{\circ} \mathrm{C}$
3 $580 \mathrm{~K}$
4 $145 \mathrm{~K}$
Kerala CEE 2007
Thermodynamics

148529 In a Carnot's cycle, the working substance absorbs heat $Q_{1}$ at temperature $T_{1}$ and rejects heat $Q_{2}$ at temperature $T_{2}$. The change of entropy during the Carnot's cycle is

1 $\frac{Q_{1}}{T_{1}}$
2 $\frac{\mathrm{Q}_{2}}{\mathrm{~T}_{2}}$
3 $\frac{Q_{1}}{T_{1}}+\frac{Q_{2}}{T_{2}}$
4 Zero
UPSEE - 2011
For More Updates join with Us