138321 At what height $h$ above earth, the value of $g$ becomes $g / 2$ ? ( $R=$ Radius of earth)

138322 The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is

138323 Find the acceleration of our galaxy, due to the nearest comparably sized galaxy. The approximate masses of each galaxy is $8 \times 10^{11}$ solar mass and they are separated by 2 million light-years. Each galaxy has a diameter of 100000 light year.
(Assume, 1 light year $\approx 10^{16} \mathrm{~m}$, gravitational constant, $G \approx 10^{-10}\left(\frac{\mathrm{Nm}^{2}}{\mathrm{~kg}^{2}}\right)$ and mass of sun $\left.=2.0 \times 10^{30} \mathrm{~kg}\right)$

138325 The density of newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal is that at the surface of the earth. If the radius of the earth is $R$, the radius of the planet would be

138321 At what height $h$ above earth, the value of $g$ becomes $g / 2$ ? ( $R=$ Radius of earth)

138322 The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is

138323 Find the acceleration of our galaxy, due to the nearest comparably sized galaxy. The approximate masses of each galaxy is $8 \times 10^{11}$ solar mass and they are separated by 2 million light-years. Each galaxy has a diameter of 100000 light year.
(Assume, 1 light year $\approx 10^{16} \mathrm{~m}$, gravitational constant, $G \approx 10^{-10}\left(\frac{\mathrm{Nm}^{2}}{\mathrm{~kg}^{2}}\right)$ and mass of sun $\left.=2.0 \times 10^{30} \mathrm{~kg}\right)$

138325 The density of newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal is that at the surface of the earth. If the radius of the earth is $R$, the radius of the planet would be

138321 At what height $h$ above earth, the value of $g$ becomes $g / 2$ ? ( $R=$ Radius of earth)

138322 The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is

138323 Find the acceleration of our galaxy, due to the nearest comparably sized galaxy. The approximate masses of each galaxy is $8 \times 10^{11}$ solar mass and they are separated by 2 million light-years. Each galaxy has a diameter of 100000 light year.
(Assume, 1 light year $\approx 10^{16} \mathrm{~m}$, gravitational constant, $G \approx 10^{-10}\left(\frac{\mathrm{Nm}^{2}}{\mathrm{~kg}^{2}}\right)$ and mass of sun $\left.=2.0 \times 10^{30} \mathrm{~kg}\right)$

138325 The density of newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal is that at the surface of the earth. If the radius of the earth is $R$, the radius of the planet would be

138321 At what height $h$ above earth, the value of $g$ becomes $g / 2$ ? ( $R=$ Radius of earth)

138322 The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is

138323 Find the acceleration of our galaxy, due to the nearest comparably sized galaxy. The approximate masses of each galaxy is $8 \times 10^{11}$ solar mass and they are separated by 2 million light-years. Each galaxy has a diameter of 100000 light year.
(Assume, 1 light year $\approx 10^{16} \mathrm{~m}$, gravitational constant, $G \approx 10^{-10}\left(\frac{\mathrm{Nm}^{2}}{\mathrm{~kg}^{2}}\right)$ and mass of sun $\left.=2.0 \times 10^{30} \mathrm{~kg}\right)$

138325 The density of newly discovered planet is twice that of the earth. The acceleration due to gravity at the surface of the planet is equal is that at the surface of the earth. If the radius of the earth is $R$, the radius of the planet would be