150396 A spherical shell of \(1 \mathrm{~kg}\) mass and radius \(\mathrm{R}\) is rolling with angular speed \(\omega\) on horizontal plane (as shown in figure). The magnitude of angular momentum of the shell about the origin \(O\) is \(\frac{a}{3} R^{2} \omega\). The value of a will be

150397 As shown in the figure a circular loop is rolling without slipping horizontally with a linear speed \(v\). What is the speed of the point \(A\)

150398 A solid sphere is rolling down an inclined plane of height 21 m without slipping. The maximum velocity with which it will reach the bottom of the plane is \(\left(g=10 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

150399 The kinetic energy of a rolling ring of mass 0.3 kg about an axis passing through its center of mass and perpendicular to its plane, if its center of mass is moving with a velocity of 8 \(\mathbf{m} . \mathbf{s}^{-1}\) is -

150396 A spherical shell of \(1 \mathrm{~kg}\) mass and radius \(\mathrm{R}\) is rolling with angular speed \(\omega\) on horizontal plane (as shown in figure). The magnitude of angular momentum of the shell about the origin \(O\) is \(\frac{a}{3} R^{2} \omega\). The value of a will be

150397 As shown in the figure a circular loop is rolling without slipping horizontally with a linear speed \(v\). What is the speed of the point \(A\)

150398 A solid sphere is rolling down an inclined plane of height 21 m without slipping. The maximum velocity with which it will reach the bottom of the plane is \(\left(g=10 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

150399 The kinetic energy of a rolling ring of mass 0.3 kg about an axis passing through its center of mass and perpendicular to its plane, if its center of mass is moving with a velocity of 8 \(\mathbf{m} . \mathbf{s}^{-1}\) is -

150396 A spherical shell of \(1 \mathrm{~kg}\) mass and radius \(\mathrm{R}\) is rolling with angular speed \(\omega\) on horizontal plane (as shown in figure). The magnitude of angular momentum of the shell about the origin \(O\) is \(\frac{a}{3} R^{2} \omega\). The value of a will be

150397 As shown in the figure a circular loop is rolling without slipping horizontally with a linear speed \(v\). What is the speed of the point \(A\)

150398 A solid sphere is rolling down an inclined plane of height 21 m without slipping. The maximum velocity with which it will reach the bottom of the plane is \(\left(g=10 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

150399 The kinetic energy of a rolling ring of mass 0.3 kg about an axis passing through its center of mass and perpendicular to its plane, if its center of mass is moving with a velocity of 8 \(\mathbf{m} . \mathbf{s}^{-1}\) is -

150396 A spherical shell of \(1 \mathrm{~kg}\) mass and radius \(\mathrm{R}\) is rolling with angular speed \(\omega\) on horizontal plane (as shown in figure). The magnitude of angular momentum of the shell about the origin \(O\) is \(\frac{a}{3} R^{2} \omega\). The value of a will be

150397 As shown in the figure a circular loop is rolling without slipping horizontally with a linear speed \(v\). What is the speed of the point \(A\)

150398 A solid sphere is rolling down an inclined plane of height 21 m without slipping. The maximum velocity with which it will reach the bottom of the plane is \(\left(g=10 \mathrm{~m} . \mathrm{s}^{-2}\right)\)

150399 The kinetic energy of a rolling ring of mass 0.3 kg about an axis passing through its center of mass and perpendicular to its plane, if its center of mass is moving with a velocity of 8 \(\mathbf{m} . \mathbf{s}^{-1}\) is -