148925 If the linear momentum is increased by $50 \%$, the kinetic energy will increase by:

148926 A bullet of mass $20 \mathrm{~g}$ and moving with $600 \mathrm{~m} / \mathrm{s}$ collides with a block of mass $4 \mathrm{~kg}$ hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 $\mathrm{m}$ after collision?

148927 The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25 \mathrm{~kg}$ and initial velocity is $2 \mathrm{~m} / \mathrm{s}$. When the distance covered by the body is $4 \mathrm{~m}$, its kinetic energy would be

148928 If potential energy is given by $U=\frac{a}{r^{2}}-\frac{b}{r}$. Then find out maximum force. (Given $a=2, b=4$ )

148929 A ball of mass $2 \mathrm{~kg}$ is thrown from a tall building with velocity,
$\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ at time $\mathbf{t}=\mathbf{0} ~ s$.
Change in the potential energy of the ball after, $t=8 \mathrm{~s}$ is (The ball is assumed to be in air during its motion between $0 \mathrm{~s}$ and $8 \mathrm{~s}$, $\hat{i}$ is along the horizontal and $\hat{j}$ is along the vertical direction. (Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )

148925 If the linear momentum is increased by $50 \%$, the kinetic energy will increase by:

148926 A bullet of mass $20 \mathrm{~g}$ and moving with $600 \mathrm{~m} / \mathrm{s}$ collides with a block of mass $4 \mathrm{~kg}$ hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 $\mathrm{m}$ after collision?

148927 The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25 \mathrm{~kg}$ and initial velocity is $2 \mathrm{~m} / \mathrm{s}$. When the distance covered by the body is $4 \mathrm{~m}$, its kinetic energy would be

148928 If potential energy is given by $U=\frac{a}{r^{2}}-\frac{b}{r}$. Then find out maximum force. (Given $a=2, b=4$ )

148929 A ball of mass $2 \mathrm{~kg}$ is thrown from a tall building with velocity,
$\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ at time $\mathbf{t}=\mathbf{0} ~ s$.
Change in the potential energy of the ball after, $t=8 \mathrm{~s}$ is (The ball is assumed to be in air during its motion between $0 \mathrm{~s}$ and $8 \mathrm{~s}$, $\hat{i}$ is along the horizontal and $\hat{j}$ is along the vertical direction. (Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )

148925 If the linear momentum is increased by $50 \%$, the kinetic energy will increase by:

148926 A bullet of mass $20 \mathrm{~g}$ and moving with $600 \mathrm{~m} / \mathrm{s}$ collides with a block of mass $4 \mathrm{~kg}$ hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 $\mathrm{m}$ after collision?

148927 The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25 \mathrm{~kg}$ and initial velocity is $2 \mathrm{~m} / \mathrm{s}$. When the distance covered by the body is $4 \mathrm{~m}$, its kinetic energy would be

148928 If potential energy is given by $U=\frac{a}{r^{2}}-\frac{b}{r}$. Then find out maximum force. (Given $a=2, b=4$ )

148929 A ball of mass $2 \mathrm{~kg}$ is thrown from a tall building with velocity,
$\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ at time $\mathbf{t}=\mathbf{0} ~ s$.
Change in the potential energy of the ball after, $t=8 \mathrm{~s}$ is (The ball is assumed to be in air during its motion between $0 \mathrm{~s}$ and $8 \mathrm{~s}$, $\hat{i}$ is along the horizontal and $\hat{j}$ is along the vertical direction. (Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )

148925 If the linear momentum is increased by $50 \%$, the kinetic energy will increase by:

148926 A bullet of mass $20 \mathrm{~g}$ and moving with $600 \mathrm{~m} / \mathrm{s}$ collides with a block of mass $4 \mathrm{~kg}$ hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 $\mathrm{m}$ after collision?

148927 The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25 \mathrm{~kg}$ and initial velocity is $2 \mathrm{~m} / \mathrm{s}$. When the distance covered by the body is $4 \mathrm{~m}$, its kinetic energy would be

148928 If potential energy is given by $U=\frac{a}{r^{2}}-\frac{b}{r}$. Then find out maximum force. (Given $a=2, b=4$ )

148929 A ball of mass $2 \mathrm{~kg}$ is thrown from a tall building with velocity,
$\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ at time $\mathbf{t}=\mathbf{0} ~ s$.
Change in the potential energy of the ball after, $t=8 \mathrm{~s}$ is (The ball is assumed to be in air during its motion between $0 \mathrm{~s}$ and $8 \mathrm{~s}$, $\hat{i}$ is along the horizontal and $\hat{j}$ is along the vertical direction. (Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )

148925 If the linear momentum is increased by $50 \%$, the kinetic energy will increase by:

148926 A bullet of mass $20 \mathrm{~g}$ and moving with $600 \mathrm{~m} / \mathrm{s}$ collides with a block of mass $4 \mathrm{~kg}$ hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 $\mathrm{m}$ after collision?

148927 The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25 \mathrm{~kg}$ and initial velocity is $2 \mathrm{~m} / \mathrm{s}$. When the distance covered by the body is $4 \mathrm{~m}$, its kinetic energy would be

148928 If potential energy is given by $U=\frac{a}{r^{2}}-\frac{b}{r}$. Then find out maximum force. (Given $a=2, b=4$ )

148929 A ball of mass $2 \mathrm{~kg}$ is thrown from a tall building with velocity,
$\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}$ at time $\mathbf{t}=\mathbf{0} ~ s$.
Change in the potential energy of the ball after, $t=8 \mathrm{~s}$ is (The ball is assumed to be in air during its motion between $0 \mathrm{~s}$ and $8 \mathrm{~s}$, $\hat{i}$ is along the horizontal and $\hat{j}$ is along the vertical direction. (Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )