148997 A bullet of mass $50 \mathrm{~g}$ is fired from a riffle of mass $2 \mathrm{Kg}$ and the total kinetic energy produced by the explosion is $2050 \mathrm{~J}$. The kinetic energy of the bullet is

148999 The kinetic energy $K$ of a particle moving along a circle of radius $R$ depends on the distance covered $s$, as $K=a^{2}$, where, $a$ is a constant. Then the force acting on the particle is-

149000 A small object of mass of $100 \mathrm{gm}$ moves in a circular path. At a given instant velocity of the object is $10 \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}$ and acceleration is $(20 \hat{\mathbf{i}}+10 \hat{\mathbf{j}})$ $\mathrm{m} / \mathrm{s}^{2}$. At this instant of time, rate of change of kinetic energy of the object is

149001 The potential energy of a conservative system is given by $V(x)=\left(x^{2}-3 x\right)$ joule, where $x$ is measured in metre. Then its equilibrium position is at

148997 A bullet of mass $50 \mathrm{~g}$ is fired from a riffle of mass $2 \mathrm{Kg}$ and the total kinetic energy produced by the explosion is $2050 \mathrm{~J}$. The kinetic energy of the bullet is

148999 The kinetic energy $K$ of a particle moving along a circle of radius $R$ depends on the distance covered $s$, as $K=a^{2}$, where, $a$ is a constant. Then the force acting on the particle is-

149000 A small object of mass of $100 \mathrm{gm}$ moves in a circular path. At a given instant velocity of the object is $10 \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}$ and acceleration is $(20 \hat{\mathbf{i}}+10 \hat{\mathbf{j}})$ $\mathrm{m} / \mathrm{s}^{2}$. At this instant of time, rate of change of kinetic energy of the object is

149001 The potential energy of a conservative system is given by $V(x)=\left(x^{2}-3 x\right)$ joule, where $x$ is measured in metre. Then its equilibrium position is at

148997 A bullet of mass $50 \mathrm{~g}$ is fired from a riffle of mass $2 \mathrm{Kg}$ and the total kinetic energy produced by the explosion is $2050 \mathrm{~J}$. The kinetic energy of the bullet is

148999 The kinetic energy $K$ of a particle moving along a circle of radius $R$ depends on the distance covered $s$, as $K=a^{2}$, where, $a$ is a constant. Then the force acting on the particle is-

149000 A small object of mass of $100 \mathrm{gm}$ moves in a circular path. At a given instant velocity of the object is $10 \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}$ and acceleration is $(20 \hat{\mathbf{i}}+10 \hat{\mathbf{j}})$ $\mathrm{m} / \mathrm{s}^{2}$. At this instant of time, rate of change of kinetic energy of the object is

149001 The potential energy of a conservative system is given by $V(x)=\left(x^{2}-3 x\right)$ joule, where $x$ is measured in metre. Then its equilibrium position is at

148997 A bullet of mass $50 \mathrm{~g}$ is fired from a riffle of mass $2 \mathrm{Kg}$ and the total kinetic energy produced by the explosion is $2050 \mathrm{~J}$. The kinetic energy of the bullet is

148999 The kinetic energy $K$ of a particle moving along a circle of radius $R$ depends on the distance covered $s$, as $K=a^{2}$, where, $a$ is a constant. Then the force acting on the particle is-

149000 A small object of mass of $100 \mathrm{gm}$ moves in a circular path. At a given instant velocity of the object is $10 \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}$ and acceleration is $(20 \hat{\mathbf{i}}+10 \hat{\mathbf{j}})$ $\mathrm{m} / \mathrm{s}^{2}$. At this instant of time, rate of change of kinetic energy of the object is

149001 The potential energy of a conservative system is given by $V(x)=\left(x^{2}-3 x\right)$ joule, where $x$ is measured in metre. Then its equilibrium position is at