00. Work done by Force and Power
Work, Energy and Power

148704 A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as a function of time is given by $x=\alpha t^{2}$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^{2}$. The work done during the first $4 \mathrm{~s}$ is

1 $0.96 \mathrm{~J}$
2 $0.45 \mathrm{~J}$
3 $0.49 \mathrm{~J}$
4 $0.53 \mathrm{~J}$
Work, Energy and Power

148705 The power of a pump which can pump $200 \mathrm{~kg}$ of water to a height of $200 \mathrm{~m}$ in $10 \mathrm{~s}$ is: (g=10 m/ $\left./ \mathbf{s}^{2}\right)$

1 $40 \mathrm{~kW}$
2 $80 \mathrm{~kW}$
3 $4000 \mathrm{~kW}$
4 $960 \mathrm{~kW}$
Work, Energy and Power

148706 A body moves a distance of $10 \mathrm{~m}$ along a straight line under the action of a force of $5 \mathrm{~N}$. If the work done is $25 \mathrm{~J}$ the angle which the force makes with the direction of motion of the body is

1 $0^{\circ}$
2 $30^{\circ}$
3 $60^{\circ}$
4 $90^{\circ}$
Work, Energy and Power

148707 A mass of $\mathrm{M} \mathrm{kg}$ is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $4^{\circ}$ with the initial vertical direction is

1 $\operatorname{Mg}(\sqrt{2}+1)$
2 $\operatorname{Mg} \sqrt{2}$
3 $\frac{\mathrm{Mg}}{\sqrt{2}}$
4 $\operatorname{Mg}(\sqrt{2}-1)$
Work, Energy and Power

148708 $\quad 300 \mathrm{~J}$ of work is done in sliding a $2 \mathrm{~kg}$ block up an inclined plane of height $10 \mathrm{~m}$. Taking $g=10$ $\mathrm{m} / \mathrm{s}^{2}$, work done against friction is

1 $200 \mathrm{~J}$
2 $100 \mathrm{~J}$
3 Zero
4 $1000 \mathrm{~J}$
Work, Energy and Power

148704 A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as a function of time is given by $x=\alpha t^{2}$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^{2}$. The work done during the first $4 \mathrm{~s}$ is

1 $0.96 \mathrm{~J}$
2 $0.45 \mathrm{~J}$
3 $0.49 \mathrm{~J}$
4 $0.53 \mathrm{~J}$
Work, Energy and Power

148705 The power of a pump which can pump $200 \mathrm{~kg}$ of water to a height of $200 \mathrm{~m}$ in $10 \mathrm{~s}$ is: (g=10 m/ $\left./ \mathbf{s}^{2}\right)$

1 $40 \mathrm{~kW}$
2 $80 \mathrm{~kW}$
3 $4000 \mathrm{~kW}$
4 $960 \mathrm{~kW}$
Work, Energy and Power

148706 A body moves a distance of $10 \mathrm{~m}$ along a straight line under the action of a force of $5 \mathrm{~N}$. If the work done is $25 \mathrm{~J}$ the angle which the force makes with the direction of motion of the body is

1 $0^{\circ}$
2 $30^{\circ}$
3 $60^{\circ}$
4 $90^{\circ}$
Work, Energy and Power

148707 A mass of $\mathrm{M} \mathrm{kg}$ is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $4^{\circ}$ with the initial vertical direction is

1 $\operatorname{Mg}(\sqrt{2}+1)$
2 $\operatorname{Mg} \sqrt{2}$
3 $\frac{\mathrm{Mg}}{\sqrt{2}}$
4 $\operatorname{Mg}(\sqrt{2}-1)$
Work, Energy and Power

148708 $\quad 300 \mathrm{~J}$ of work is done in sliding a $2 \mathrm{~kg}$ block up an inclined plane of height $10 \mathrm{~m}$. Taking $g=10$ $\mathrm{m} / \mathrm{s}^{2}$, work done against friction is

1 $200 \mathrm{~J}$
2 $100 \mathrm{~J}$
3 Zero
4 $1000 \mathrm{~J}$
Work, Energy and Power

148704 A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as a function of time is given by $x=\alpha t^{2}$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^{2}$. The work done during the first $4 \mathrm{~s}$ is

1 $0.96 \mathrm{~J}$
2 $0.45 \mathrm{~J}$
3 $0.49 \mathrm{~J}$
4 $0.53 \mathrm{~J}$
Work, Energy and Power

148705 The power of a pump which can pump $200 \mathrm{~kg}$ of water to a height of $200 \mathrm{~m}$ in $10 \mathrm{~s}$ is: (g=10 m/ $\left./ \mathbf{s}^{2}\right)$

1 $40 \mathrm{~kW}$
2 $80 \mathrm{~kW}$
3 $4000 \mathrm{~kW}$
4 $960 \mathrm{~kW}$
Work, Energy and Power

148706 A body moves a distance of $10 \mathrm{~m}$ along a straight line under the action of a force of $5 \mathrm{~N}$. If the work done is $25 \mathrm{~J}$ the angle which the force makes with the direction of motion of the body is

1 $0^{\circ}$
2 $30^{\circ}$
3 $60^{\circ}$
4 $90^{\circ}$
Work, Energy and Power

148707 A mass of $\mathrm{M} \mathrm{kg}$ is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $4^{\circ}$ with the initial vertical direction is

1 $\operatorname{Mg}(\sqrt{2}+1)$
2 $\operatorname{Mg} \sqrt{2}$
3 $\frac{\mathrm{Mg}}{\sqrt{2}}$
4 $\operatorname{Mg}(\sqrt{2}-1)$
Work, Energy and Power

148708 $\quad 300 \mathrm{~J}$ of work is done in sliding a $2 \mathrm{~kg}$ block up an inclined plane of height $10 \mathrm{~m}$. Taking $g=10$ $\mathrm{m} / \mathrm{s}^{2}$, work done against friction is

1 $200 \mathrm{~J}$
2 $100 \mathrm{~J}$
3 Zero
4 $1000 \mathrm{~J}$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Work, Energy and Power

148704 A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as a function of time is given by $x=\alpha t^{2}$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^{2}$. The work done during the first $4 \mathrm{~s}$ is

1 $0.96 \mathrm{~J}$
2 $0.45 \mathrm{~J}$
3 $0.49 \mathrm{~J}$
4 $0.53 \mathrm{~J}$
Work, Energy and Power

148705 The power of a pump which can pump $200 \mathrm{~kg}$ of water to a height of $200 \mathrm{~m}$ in $10 \mathrm{~s}$ is: (g=10 m/ $\left./ \mathbf{s}^{2}\right)$

1 $40 \mathrm{~kW}$
2 $80 \mathrm{~kW}$
3 $4000 \mathrm{~kW}$
4 $960 \mathrm{~kW}$
Work, Energy and Power

148706 A body moves a distance of $10 \mathrm{~m}$ along a straight line under the action of a force of $5 \mathrm{~N}$. If the work done is $25 \mathrm{~J}$ the angle which the force makes with the direction of motion of the body is

1 $0^{\circ}$
2 $30^{\circ}$
3 $60^{\circ}$
4 $90^{\circ}$
Work, Energy and Power

148707 A mass of $\mathrm{M} \mathrm{kg}$ is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $4^{\circ}$ with the initial vertical direction is

1 $\operatorname{Mg}(\sqrt{2}+1)$
2 $\operatorname{Mg} \sqrt{2}$
3 $\frac{\mathrm{Mg}}{\sqrt{2}}$
4 $\operatorname{Mg}(\sqrt{2}-1)$
Work, Energy and Power

148708 $\quad 300 \mathrm{~J}$ of work is done in sliding a $2 \mathrm{~kg}$ block up an inclined plane of height $10 \mathrm{~m}$. Taking $g=10$ $\mathrm{m} / \mathrm{s}^{2}$, work done against friction is

1 $200 \mathrm{~J}$
2 $100 \mathrm{~J}$
3 Zero
4 $1000 \mathrm{~J}$
Work, Energy and Power

148704 A force acts on a $30 \mathrm{~g}$ particle in such a way that the position of the particle as a function of time is given by $x=\alpha t^{2}$, where $x$ is in metre, $t$ is in seconds and $\alpha=1 \mathrm{~m} / \mathrm{s}^{2}$. The work done during the first $4 \mathrm{~s}$ is

1 $0.96 \mathrm{~J}$
2 $0.45 \mathrm{~J}$
3 $0.49 \mathrm{~J}$
4 $0.53 \mathrm{~J}$
Work, Energy and Power

148705 The power of a pump which can pump $200 \mathrm{~kg}$ of water to a height of $200 \mathrm{~m}$ in $10 \mathrm{~s}$ is: (g=10 m/ $\left./ \mathbf{s}^{2}\right)$

1 $40 \mathrm{~kW}$
2 $80 \mathrm{~kW}$
3 $4000 \mathrm{~kW}$
4 $960 \mathrm{~kW}$
Work, Energy and Power

148706 A body moves a distance of $10 \mathrm{~m}$ along a straight line under the action of a force of $5 \mathrm{~N}$. If the work done is $25 \mathrm{~J}$ the angle which the force makes with the direction of motion of the body is

1 $0^{\circ}$
2 $30^{\circ}$
3 $60^{\circ}$
4 $90^{\circ}$
Work, Energy and Power

148707 A mass of $\mathrm{M} \mathrm{kg}$ is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $4^{\circ}$ with the initial vertical direction is

1 $\operatorname{Mg}(\sqrt{2}+1)$
2 $\operatorname{Mg} \sqrt{2}$
3 $\frac{\mathrm{Mg}}{\sqrt{2}}$
4 $\operatorname{Mg}(\sqrt{2}-1)$
Work, Energy and Power

148708 $\quad 300 \mathrm{~J}$ of work is done in sliding a $2 \mathrm{~kg}$ block up an inclined plane of height $10 \mathrm{~m}$. Taking $g=10$ $\mathrm{m} / \mathrm{s}^{2}$, work done against friction is

1 $200 \mathrm{~J}$
2 $100 \mathrm{~J}$
3 Zero
4 $1000 \mathrm{~J}$