146197 A wooden box of mass \(8 \mathrm{~kg}\) slides down an inclined plane of inclination \(30^{\circ}\) to the horizontal with a constant acceleration of 0.4 \(\mathrm{m} \mathrm{s}^{-2}\). What is the force of friction between the box and inclined plane? \(\left[\mathbf{g}=\mathbf{1 0} \mathbf{~ m ~ s}^{-2}\right]\)
146198
Block A of weight \(100 \mathrm{~kg}\) rests on a block \(B\) and is tied with horizontal string to the wall at C. Block B is of \(200 \mathrm{~kg}\). The coefficient of friction between \(A\) and \(B\) is 0.25 and that between \(B\) and surface is \(\frac{1}{3}\). The horizontal force \(F\) necessary to move the block \(B\) should be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
146200
A time varying horizontal force (in Newton) \(F\) \(=8|\sin (4 \pi \mathrm{t})|\) is acting on a stationary block of mass \(2 \mathrm{~kg}\) as shown. Friction coefficient between the block and ground is \(\mu=0.5\) and \(g\) \(=10 \mathrm{~m} / \mathrm{s}^{2}\). Then resulting motion of the block will be
\(2 \mathrm{~kg} \rightarrow \mathrm{F}\)
146197 A wooden box of mass \(8 \mathrm{~kg}\) slides down an inclined plane of inclination \(30^{\circ}\) to the horizontal with a constant acceleration of 0.4 \(\mathrm{m} \mathrm{s}^{-2}\). What is the force of friction between the box and inclined plane? \(\left[\mathbf{g}=\mathbf{1 0} \mathbf{~ m ~ s}^{-2}\right]\)
146198
Block A of weight \(100 \mathrm{~kg}\) rests on a block \(B\) and is tied with horizontal string to the wall at C. Block B is of \(200 \mathrm{~kg}\). The coefficient of friction between \(A\) and \(B\) is 0.25 and that between \(B\) and surface is \(\frac{1}{3}\). The horizontal force \(F\) necessary to move the block \(B\) should be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
146200
A time varying horizontal force (in Newton) \(F\) \(=8|\sin (4 \pi \mathrm{t})|\) is acting on a stationary block of mass \(2 \mathrm{~kg}\) as shown. Friction coefficient between the block and ground is \(\mu=0.5\) and \(g\) \(=10 \mathrm{~m} / \mathrm{s}^{2}\). Then resulting motion of the block will be
\(2 \mathrm{~kg} \rightarrow \mathrm{F}\)
146197 A wooden box of mass \(8 \mathrm{~kg}\) slides down an inclined plane of inclination \(30^{\circ}\) to the horizontal with a constant acceleration of 0.4 \(\mathrm{m} \mathrm{s}^{-2}\). What is the force of friction between the box and inclined plane? \(\left[\mathbf{g}=\mathbf{1 0} \mathbf{~ m ~ s}^{-2}\right]\)
146198
Block A of weight \(100 \mathrm{~kg}\) rests on a block \(B\) and is tied with horizontal string to the wall at C. Block B is of \(200 \mathrm{~kg}\). The coefficient of friction between \(A\) and \(B\) is 0.25 and that between \(B\) and surface is \(\frac{1}{3}\). The horizontal force \(F\) necessary to move the block \(B\) should be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
146200
A time varying horizontal force (in Newton) \(F\) \(=8|\sin (4 \pi \mathrm{t})|\) is acting on a stationary block of mass \(2 \mathrm{~kg}\) as shown. Friction coefficient between the block and ground is \(\mu=0.5\) and \(g\) \(=10 \mathrm{~m} / \mathrm{s}^{2}\). Then resulting motion of the block will be
\(2 \mathrm{~kg} \rightarrow \mathrm{F}\)
146197 A wooden box of mass \(8 \mathrm{~kg}\) slides down an inclined plane of inclination \(30^{\circ}\) to the horizontal with a constant acceleration of 0.4 \(\mathrm{m} \mathrm{s}^{-2}\). What is the force of friction between the box and inclined plane? \(\left[\mathbf{g}=\mathbf{1 0} \mathbf{~ m ~ s}^{-2}\right]\)
146198
Block A of weight \(100 \mathrm{~kg}\) rests on a block \(B\) and is tied with horizontal string to the wall at C. Block B is of \(200 \mathrm{~kg}\). The coefficient of friction between \(A\) and \(B\) is 0.25 and that between \(B\) and surface is \(\frac{1}{3}\). The horizontal force \(F\) necessary to move the block \(B\) should be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
146200
A time varying horizontal force (in Newton) \(F\) \(=8|\sin (4 \pi \mathrm{t})|\) is acting on a stationary block of mass \(2 \mathrm{~kg}\) as shown. Friction coefficient between the block and ground is \(\mu=0.5\) and \(g\) \(=10 \mathrm{~m} / \mathrm{s}^{2}\). Then resulting motion of the block will be
\(2 \mathrm{~kg} \rightarrow \mathrm{F}\)
146197 A wooden box of mass \(8 \mathrm{~kg}\) slides down an inclined plane of inclination \(30^{\circ}\) to the horizontal with a constant acceleration of 0.4 \(\mathrm{m} \mathrm{s}^{-2}\). What is the force of friction between the box and inclined plane? \(\left[\mathbf{g}=\mathbf{1 0} \mathbf{~ m ~ s}^{-2}\right]\)
146198
Block A of weight \(100 \mathrm{~kg}\) rests on a block \(B\) and is tied with horizontal string to the wall at C. Block B is of \(200 \mathrm{~kg}\). The coefficient of friction between \(A\) and \(B\) is 0.25 and that between \(B\) and surface is \(\frac{1}{3}\). The horizontal force \(F\) necessary to move the block \(B\) should be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
146200
A time varying horizontal force (in Newton) \(F\) \(=8|\sin (4 \pi \mathrm{t})|\) is acting on a stationary block of mass \(2 \mathrm{~kg}\) as shown. Friction coefficient between the block and ground is \(\mu=0.5\) and \(g\) \(=10 \mathrm{~m} / \mathrm{s}^{2}\). Then resulting motion of the block will be
\(2 \mathrm{~kg} \rightarrow \mathrm{F}\)