146144 A \(6.0 \mathrm{~kg}\) block is placed on a \(60^{\circ}\) ramp as shown in the figure. The coefficient of static friction is 0.6 . A force \(\vec{F}\) is applied that puts the block on the verge of sliding down the ramp. The value of force \(F\) in Newton is
(Given: \(\sqrt{3}=1.73\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )

146145 For a truck with 14 tyres, only 8 rear wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. If the coefficient of friction between road and each tyre is 0.6 , the maximum attainable acceleration by this truck would be \(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

146146 A \(13 \mathrm{~m}\) ladder is placed against a smooth vertical wall its lower end at a distance \(5 \mathrm{~m}\) from the wall. The minimum coefficient of friction between the ladder and the floor so that the ladder remains in equilibrium is nearly

146147 A block of mass \(100 \mathrm{~kg}\) attached to a mass less rope and the second end of the rope is pulled up by 2 men along a rough inclined plane of coefficient of friction 0.2 inclined at \(37^{\circ}\) with the horizontal. If they exert their maximum force for the block to just start moving up, the force exerted by each of them is.
\(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}, \tan 37^{\circ}\) \(\simeq 0.75\) )

146148 A body is sliding down a rough inclined plane of angle of inclination 0 for which the coefficient of friction varies with distance \(x\) as \(\mu(x)=K x\), where \(k\) is a constant. Here \(x\) is the distance moved by the body down the inclined plane. If the net force on the body will be zero at a distance \(x_{0}\). Then \(x_{0}\) will be equal to

146144 A \(6.0 \mathrm{~kg}\) block is placed on a \(60^{\circ}\) ramp as shown in the figure. The coefficient of static friction is 0.6 . A force \(\vec{F}\) is applied that puts the block on the verge of sliding down the ramp. The value of force \(F\) in Newton is
(Given: \(\sqrt{3}=1.73\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )

146145 For a truck with 14 tyres, only 8 rear wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. If the coefficient of friction between road and each tyre is 0.6 , the maximum attainable acceleration by this truck would be \(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

146146 A \(13 \mathrm{~m}\) ladder is placed against a smooth vertical wall its lower end at a distance \(5 \mathrm{~m}\) from the wall. The minimum coefficient of friction between the ladder and the floor so that the ladder remains in equilibrium is nearly

146147 A block of mass \(100 \mathrm{~kg}\) attached to a mass less rope and the second end of the rope is pulled up by 2 men along a rough inclined plane of coefficient of friction 0.2 inclined at \(37^{\circ}\) with the horizontal. If they exert their maximum force for the block to just start moving up, the force exerted by each of them is.
\(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}, \tan 37^{\circ}\) \(\simeq 0.75\) )

146148 A body is sliding down a rough inclined plane of angle of inclination 0 for which the coefficient of friction varies with distance \(x\) as \(\mu(x)=K x\), where \(k\) is a constant. Here \(x\) is the distance moved by the body down the inclined plane. If the net force on the body will be zero at a distance \(x_{0}\). Then \(x_{0}\) will be equal to

146144 A \(6.0 \mathrm{~kg}\) block is placed on a \(60^{\circ}\) ramp as shown in the figure. The coefficient of static friction is 0.6 . A force \(\vec{F}\) is applied that puts the block on the verge of sliding down the ramp. The value of force \(F\) in Newton is
(Given: \(\sqrt{3}=1.73\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )

146145 For a truck with 14 tyres, only 8 rear wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. If the coefficient of friction between road and each tyre is 0.6 , the maximum attainable acceleration by this truck would be \(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

146146 A \(13 \mathrm{~m}\) ladder is placed against a smooth vertical wall its lower end at a distance \(5 \mathrm{~m}\) from the wall. The minimum coefficient of friction between the ladder and the floor so that the ladder remains in equilibrium is nearly

146147 A block of mass \(100 \mathrm{~kg}\) attached to a mass less rope and the second end of the rope is pulled up by 2 men along a rough inclined plane of coefficient of friction 0.2 inclined at \(37^{\circ}\) with the horizontal. If they exert their maximum force for the block to just start moving up, the force exerted by each of them is.
\(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}, \tan 37^{\circ}\) \(\simeq 0.75\) )

146148 A body is sliding down a rough inclined plane of angle of inclination 0 for which the coefficient of friction varies with distance \(x\) as \(\mu(x)=K x\), where \(k\) is a constant. Here \(x\) is the distance moved by the body down the inclined plane. If the net force on the body will be zero at a distance \(x_{0}\). Then \(x_{0}\) will be equal to

146144 A \(6.0 \mathrm{~kg}\) block is placed on a \(60^{\circ}\) ramp as shown in the figure. The coefficient of static friction is 0.6 . A force \(\vec{F}\) is applied that puts the block on the verge of sliding down the ramp. The value of force \(F\) in Newton is
(Given: \(\sqrt{3}=1.73\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )

146145 For a truck with 14 tyres, only 8 rear wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. If the coefficient of friction between road and each tyre is 0.6 , the maximum attainable acceleration by this truck would be \(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

146146 A \(13 \mathrm{~m}\) ladder is placed against a smooth vertical wall its lower end at a distance \(5 \mathrm{~m}\) from the wall. The minimum coefficient of friction between the ladder and the floor so that the ladder remains in equilibrium is nearly

146147 A block of mass \(100 \mathrm{~kg}\) attached to a mass less rope and the second end of the rope is pulled up by 2 men along a rough inclined plane of coefficient of friction 0.2 inclined at \(37^{\circ}\) with the horizontal. If they exert their maximum force for the block to just start moving up, the force exerted by each of them is.
\(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}, \tan 37^{\circ}\) \(\simeq 0.75\) )

146148 A body is sliding down a rough inclined plane of angle of inclination 0 for which the coefficient of friction varies with distance \(x\) as \(\mu(x)=K x\), where \(k\) is a constant. Here \(x\) is the distance moved by the body down the inclined plane. If the net force on the body will be zero at a distance \(x_{0}\). Then \(x_{0}\) will be equal to

146144 A \(6.0 \mathrm{~kg}\) block is placed on a \(60^{\circ}\) ramp as shown in the figure. The coefficient of static friction is 0.6 . A force \(\vec{F}\) is applied that puts the block on the verge of sliding down the ramp. The value of force \(F\) in Newton is
(Given: \(\sqrt{3}=1.73\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )

146145 For a truck with 14 tyres, only 8 rear wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. If the coefficient of friction between road and each tyre is 0.6 , the maximum attainable acceleration by this truck would be \(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

146146 A \(13 \mathrm{~m}\) ladder is placed against a smooth vertical wall its lower end at a distance \(5 \mathrm{~m}\) from the wall. The minimum coefficient of friction between the ladder and the floor so that the ladder remains in equilibrium is nearly

146147 A block of mass \(100 \mathrm{~kg}\) attached to a mass less rope and the second end of the rope is pulled up by 2 men along a rough inclined plane of coefficient of friction 0.2 inclined at \(37^{\circ}\) with the horizontal. If they exert their maximum force for the block to just start moving up, the force exerted by each of them is.
\(\left(\right.\) Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}, \tan 37^{\circ}\) \(\simeq 0.75\) )

146148 A body is sliding down a rough inclined plane of angle of inclination 0 for which the coefficient of friction varies with distance \(x\) as \(\mu(x)=K x\), where \(k\) is a constant. Here \(x\) is the distance moved by the body down the inclined plane. If the net force on the body will be zero at a distance \(x_{0}\). Then \(x_{0}\) will be equal to