04. Motion Under Gravity
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Motion in One Dimensions

141785 A ball when thrown upward from a tower with a given velocity takes time \(t_{1}\) to reach the ground. The same ball when thrown downward with same velocity from the tower takes time \(t_{2}\) to reach the ground. If the ball is dropped freely from the same tower, the time taken to reach the ground will be

1 \(t_{1}-t_{2}\)
2 \(\frac{t_{1}+t_{2}}{2}\)
3 \(\sqrt{t_{1} \times t_{2}}\)
4 \(\sqrt{\mathrm{t}_{1}^{2}-\mathrm{t}_{2}^{2}}\)
SCRA-2015
Motion in One Dimensions

141786 A body dropped from top of a tower fall through \(60 \mathrm{~m}\) during the last two seconds of its fall. The height of tower is : \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

1 \(95 \mathrm{~m}\)
2 \(60 \mathrm{~m}\)
3 \(80 \mathrm{~m}\)
4 \(90 \mathrm{~m}\)
UPSEE - 2005
Motion in One Dimensions

141787 The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

1 \(1: 2: 3\)
2 \(1: 5: 9\)
3 \(1: 3: 5\)
4 \(\sqrt{1}: \sqrt{2}: \sqrt{3}\)
5 \(1: 4: 9\)
Kerala CEE- 2014
Motion in One Dimensions

141788 A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be \(10 \mathrm{~m} / \mathrm{s}\), then the maximum height attained by the stone is (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(3 \mathrm{~m}\)
2 \(15 \mathrm{~m}\)
3 \(1 \mathrm{~m}\)
4 \(10 \mathrm{~m}\)
JCECE-2014
Motion in One Dimensions

141789 A ball is released from the top of a tower of height \(h\) meters. It takes \(T\) seconds to reach the ground. What is the position of the ball at \(\frac{T}{3}\) second

1 \(\frac{8 \mathrm{~h}}{9}\) meters from the ground
2 \(\frac{7 \mathrm{~h}}{9}\) meters from the ground
3 \(\frac{\mathrm{h}}{9}\) meters from the ground
4 \(\frac{17 \mathrm{~h}}{18}\) meters from the ground
AIIMS-2012
NEET DIGITAL LIBRARY
Motion in One Dimensions

141785 A ball when thrown upward from a tower with a given velocity takes time \(t_{1}\) to reach the ground. The same ball when thrown downward with same velocity from the tower takes time \(t_{2}\) to reach the ground. If the ball is dropped freely from the same tower, the time taken to reach the ground will be

1 \(t_{1}-t_{2}\)
2 \(\frac{t_{1}+t_{2}}{2}\)
3 \(\sqrt{t_{1} \times t_{2}}\)
4 \(\sqrt{\mathrm{t}_{1}^{2}-\mathrm{t}_{2}^{2}}\)
SCRA-2015
Motion in One Dimensions

141786 A body dropped from top of a tower fall through \(60 \mathrm{~m}\) during the last two seconds of its fall. The height of tower is : \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

1 \(95 \mathrm{~m}\)
2 \(60 \mathrm{~m}\)
3 \(80 \mathrm{~m}\)
4 \(90 \mathrm{~m}\)
UPSEE - 2005
Motion in One Dimensions

141787 The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

1 \(1: 2: 3\)
2 \(1: 5: 9\)
3 \(1: 3: 5\)
4 \(\sqrt{1}: \sqrt{2}: \sqrt{3}\)
5 \(1: 4: 9\)
Kerala CEE- 2014
Motion in One Dimensions

141788 A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be \(10 \mathrm{~m} / \mathrm{s}\), then the maximum height attained by the stone is (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(3 \mathrm{~m}\)
2 \(15 \mathrm{~m}\)
3 \(1 \mathrm{~m}\)
4 \(10 \mathrm{~m}\)
JCECE-2014
Motion in One Dimensions

141789 A ball is released from the top of a tower of height \(h\) meters. It takes \(T\) seconds to reach the ground. What is the position of the ball at \(\frac{T}{3}\) second

1 \(\frac{8 \mathrm{~h}}{9}\) meters from the ground
2 \(\frac{7 \mathrm{~h}}{9}\) meters from the ground
3 \(\frac{\mathrm{h}}{9}\) meters from the ground
4 \(\frac{17 \mathrm{~h}}{18}\) meters from the ground
AIIMS-2012
Join With Us for More Updates
Motion in One Dimensions

141785 A ball when thrown upward from a tower with a given velocity takes time \(t_{1}\) to reach the ground. The same ball when thrown downward with same velocity from the tower takes time \(t_{2}\) to reach the ground. If the ball is dropped freely from the same tower, the time taken to reach the ground will be

1 \(t_{1}-t_{2}\)
2 \(\frac{t_{1}+t_{2}}{2}\)
3 \(\sqrt{t_{1} \times t_{2}}\)
4 \(\sqrt{\mathrm{t}_{1}^{2}-\mathrm{t}_{2}^{2}}\)
SCRA-2015
Motion in One Dimensions

141786 A body dropped from top of a tower fall through \(60 \mathrm{~m}\) during the last two seconds of its fall. The height of tower is : \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

1 \(95 \mathrm{~m}\)
2 \(60 \mathrm{~m}\)
3 \(80 \mathrm{~m}\)
4 \(90 \mathrm{~m}\)
UPSEE - 2005
Motion in One Dimensions

141787 The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

1 \(1: 2: 3\)
2 \(1: 5: 9\)
3 \(1: 3: 5\)
4 \(\sqrt{1}: \sqrt{2}: \sqrt{3}\)
5 \(1: 4: 9\)
Kerala CEE- 2014
Motion in One Dimensions

141788 A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be \(10 \mathrm{~m} / \mathrm{s}\), then the maximum height attained by the stone is (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(3 \mathrm{~m}\)
2 \(15 \mathrm{~m}\)
3 \(1 \mathrm{~m}\)
4 \(10 \mathrm{~m}\)
JCECE-2014
Motion in One Dimensions

141789 A ball is released from the top of a tower of height \(h\) meters. It takes \(T\) seconds to reach the ground. What is the position of the ball at \(\frac{T}{3}\) second

1 \(\frac{8 \mathrm{~h}}{9}\) meters from the ground
2 \(\frac{7 \mathrm{~h}}{9}\) meters from the ground
3 \(\frac{\mathrm{h}}{9}\) meters from the ground
4 \(\frac{17 \mathrm{~h}}{18}\) meters from the ground
AIIMS-2012
For More Updates join with Us
Motion in One Dimensions

141785 A ball when thrown upward from a tower with a given velocity takes time \(t_{1}\) to reach the ground. The same ball when thrown downward with same velocity from the tower takes time \(t_{2}\) to reach the ground. If the ball is dropped freely from the same tower, the time taken to reach the ground will be

1 \(t_{1}-t_{2}\)
2 \(\frac{t_{1}+t_{2}}{2}\)
3 \(\sqrt{t_{1} \times t_{2}}\)
4 \(\sqrt{\mathrm{t}_{1}^{2}-\mathrm{t}_{2}^{2}}\)
SCRA-2015
Motion in One Dimensions

141786 A body dropped from top of a tower fall through \(60 \mathrm{~m}\) during the last two seconds of its fall. The height of tower is : \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

1 \(95 \mathrm{~m}\)
2 \(60 \mathrm{~m}\)
3 \(80 \mathrm{~m}\)
4 \(90 \mathrm{~m}\)
UPSEE - 2005
Motion in One Dimensions

141787 The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

1 \(1: 2: 3\)
2 \(1: 5: 9\)
3 \(1: 3: 5\)
4 \(\sqrt{1}: \sqrt{2}: \sqrt{3}\)
5 \(1: 4: 9\)
Kerala CEE- 2014
Motion in One Dimensions

141788 A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be \(10 \mathrm{~m} / \mathrm{s}\), then the maximum height attained by the stone is (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(3 \mathrm{~m}\)
2 \(15 \mathrm{~m}\)
3 \(1 \mathrm{~m}\)
4 \(10 \mathrm{~m}\)
JCECE-2014
Motion in One Dimensions

141789 A ball is released from the top of a tower of height \(h\) meters. It takes \(T\) seconds to reach the ground. What is the position of the ball at \(\frac{T}{3}\) second

1 \(\frac{8 \mathrm{~h}}{9}\) meters from the ground
2 \(\frac{7 \mathrm{~h}}{9}\) meters from the ground
3 \(\frac{\mathrm{h}}{9}\) meters from the ground
4 \(\frac{17 \mathrm{~h}}{18}\) meters from the ground
AIIMS-2012
NEET DIGITAL LIBRARY
Motion in One Dimensions

141785 A ball when thrown upward from a tower with a given velocity takes time \(t_{1}\) to reach the ground. The same ball when thrown downward with same velocity from the tower takes time \(t_{2}\) to reach the ground. If the ball is dropped freely from the same tower, the time taken to reach the ground will be

1 \(t_{1}-t_{2}\)
2 \(\frac{t_{1}+t_{2}}{2}\)
3 \(\sqrt{t_{1} \times t_{2}}\)
4 \(\sqrt{\mathrm{t}_{1}^{2}-\mathrm{t}_{2}^{2}}\)
SCRA-2015
Motion in One Dimensions

141786 A body dropped from top of a tower fall through \(60 \mathrm{~m}\) during the last two seconds of its fall. The height of tower is : \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

1 \(95 \mathrm{~m}\)
2 \(60 \mathrm{~m}\)
3 \(80 \mathrm{~m}\)
4 \(90 \mathrm{~m}\)
UPSEE - 2005
Motion in One Dimensions

141787 The ratio of distance traversed in successive intervals of time when a body falls freely under gravity from certain height is

1 \(1: 2: 3\)
2 \(1: 5: 9\)
3 \(1: 3: 5\)
4 \(\sqrt{1}: \sqrt{2}: \sqrt{3}\)
5 \(1: 4: 9\)
Kerala CEE- 2014
Motion in One Dimensions

141788 A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be \(10 \mathrm{~m} / \mathrm{s}\), then the maximum height attained by the stone is (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\) )

1 \(3 \mathrm{~m}\)
2 \(15 \mathrm{~m}\)
3 \(1 \mathrm{~m}\)
4 \(10 \mathrm{~m}\)
JCECE-2014
Motion in One Dimensions

141789 A ball is released from the top of a tower of height \(h\) meters. It takes \(T\) seconds to reach the ground. What is the position of the ball at \(\frac{T}{3}\) second

1 \(\frac{8 \mathrm{~h}}{9}\) meters from the ground
2 \(\frac{7 \mathrm{~h}}{9}\) meters from the ground
3 \(\frac{\mathrm{h}}{9}\) meters from the ground
4 \(\frac{17 \mathrm{~h}}{18}\) meters from the ground
AIIMS-2012