141783
A staircase has 5 steps each \(10 \mathrm{~cm}\) high and \(10 \mathrm{~cm}\) wide. What is the minimum horizontal velocity to be given to the ball so that it hits directly the lowest plane from the top of the staircase? \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
1 \(2 \mathrm{~ms}^{-1}\)
2 \(1 \mathrm{~ms}^{-1}\)
3 \(\sqrt{2} \mathrm{~ms}^{-1}\)
4 \(1 / 2 \mathrm{~ms}^{-1}\)
Explanation:
C \(\mathrm{y}=10 \mathrm{~cm}\) \(\mathrm{x}=10 \mathrm{~cm}\) \(\mathrm{~h}=5\) \(\mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^{2}\) Distance travelled is vertical direction \(\mathrm{y}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}\) \(\mathrm{t}^{2}=\frac{5 \times \frac{1}{10}}{5}=\frac{1}{10}\) \(\mathrm{t}=\frac{1}{\sqrt{10}}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}==5 \mathrm{t}^{2}\) Distance travelled in the horizontal direction is \(\mathrm{hx} \simeq \mathrm{ut}\) \(5 \times \frac{1}{10}=\mathrm{u} \times \frac{1}{\sqrt{10}}\) \(\mathrm{u}=\frac{5 \times \sqrt{10}}{10}\) \(\mathrm{u}=\sqrt{2}\)
NDA (II) 2012
Motion in One Dimensions
141740
Two balls of same size but the density of one is greater than that of the other are dropped from the same height, then which ball will reach the earth first (air resistance is negligible)?
1 Heavy ball
2 Light ball
3 Both simultaneously
4 Will depend upon the density of the balls
Explanation:
C We know that, \(\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2} \Rightarrow \mathrm{t}=\sqrt{\frac{2(\mathrm{~s}-\mathrm{ut})}{\mathrm{g}}}\) Since, \(\mathrm{s}, \mathrm{u}\) and \(\mathrm{g}\) are same for both, Hence, both ball will reach the earth in same time.
J and K-CET- 2004
Motion in One Dimensions
141760
A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represent the velocity time plot for the period ball remains in air?
1
2
3
4
Explanation:
A \(\mathrm{v}=\mathrm{u}-\mathrm{gt}\) correct figure: During upward position velocity is decreasing and become zero and magnitude of velocity is increasing in downward direction.
DCE- 2007
Motion in One Dimensions
141771
If a ball is thrown vertically upwards with speed \(u\), the distance covered during the last \(t\) sec of its ascent is
1 \(\mathrm{ut}-\frac{1}{2} \mathrm{gt}^{2}\)
2 \((u+g t) t\)
3 ut
4 \(\frac{1}{2} \mathrm{gt}^{2}\)
Explanation:
D We know that, \(\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{h}=0 \times \mathrm{t}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{~h}=\frac{1}{2} \mathrm{gt}^{2}\)
141783
A staircase has 5 steps each \(10 \mathrm{~cm}\) high and \(10 \mathrm{~cm}\) wide. What is the minimum horizontal velocity to be given to the ball so that it hits directly the lowest plane from the top of the staircase? \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
1 \(2 \mathrm{~ms}^{-1}\)
2 \(1 \mathrm{~ms}^{-1}\)
3 \(\sqrt{2} \mathrm{~ms}^{-1}\)
4 \(1 / 2 \mathrm{~ms}^{-1}\)
Explanation:
C \(\mathrm{y}=10 \mathrm{~cm}\) \(\mathrm{x}=10 \mathrm{~cm}\) \(\mathrm{~h}=5\) \(\mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^{2}\) Distance travelled is vertical direction \(\mathrm{y}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}\) \(\mathrm{t}^{2}=\frac{5 \times \frac{1}{10}}{5}=\frac{1}{10}\) \(\mathrm{t}=\frac{1}{\sqrt{10}}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}==5 \mathrm{t}^{2}\) Distance travelled in the horizontal direction is \(\mathrm{hx} \simeq \mathrm{ut}\) \(5 \times \frac{1}{10}=\mathrm{u} \times \frac{1}{\sqrt{10}}\) \(\mathrm{u}=\frac{5 \times \sqrt{10}}{10}\) \(\mathrm{u}=\sqrt{2}\)
NDA (II) 2012
Motion in One Dimensions
141740
Two balls of same size but the density of one is greater than that of the other are dropped from the same height, then which ball will reach the earth first (air resistance is negligible)?
1 Heavy ball
2 Light ball
3 Both simultaneously
4 Will depend upon the density of the balls
Explanation:
C We know that, \(\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2} \Rightarrow \mathrm{t}=\sqrt{\frac{2(\mathrm{~s}-\mathrm{ut})}{\mathrm{g}}}\) Since, \(\mathrm{s}, \mathrm{u}\) and \(\mathrm{g}\) are same for both, Hence, both ball will reach the earth in same time.
J and K-CET- 2004
Motion in One Dimensions
141760
A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represent the velocity time plot for the period ball remains in air?
1
2
3
4
Explanation:
A \(\mathrm{v}=\mathrm{u}-\mathrm{gt}\) correct figure: During upward position velocity is decreasing and become zero and magnitude of velocity is increasing in downward direction.
DCE- 2007
Motion in One Dimensions
141771
If a ball is thrown vertically upwards with speed \(u\), the distance covered during the last \(t\) sec of its ascent is
1 \(\mathrm{ut}-\frac{1}{2} \mathrm{gt}^{2}\)
2 \((u+g t) t\)
3 ut
4 \(\frac{1}{2} \mathrm{gt}^{2}\)
Explanation:
D We know that, \(\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{h}=0 \times \mathrm{t}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{~h}=\frac{1}{2} \mathrm{gt}^{2}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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Motion in One Dimensions
141783
A staircase has 5 steps each \(10 \mathrm{~cm}\) high and \(10 \mathrm{~cm}\) wide. What is the minimum horizontal velocity to be given to the ball so that it hits directly the lowest plane from the top of the staircase? \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
1 \(2 \mathrm{~ms}^{-1}\)
2 \(1 \mathrm{~ms}^{-1}\)
3 \(\sqrt{2} \mathrm{~ms}^{-1}\)
4 \(1 / 2 \mathrm{~ms}^{-1}\)
Explanation:
C \(\mathrm{y}=10 \mathrm{~cm}\) \(\mathrm{x}=10 \mathrm{~cm}\) \(\mathrm{~h}=5\) \(\mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^{2}\) Distance travelled is vertical direction \(\mathrm{y}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}\) \(\mathrm{t}^{2}=\frac{5 \times \frac{1}{10}}{5}=\frac{1}{10}\) \(\mathrm{t}=\frac{1}{\sqrt{10}}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}==5 \mathrm{t}^{2}\) Distance travelled in the horizontal direction is \(\mathrm{hx} \simeq \mathrm{ut}\) \(5 \times \frac{1}{10}=\mathrm{u} \times \frac{1}{\sqrt{10}}\) \(\mathrm{u}=\frac{5 \times \sqrt{10}}{10}\) \(\mathrm{u}=\sqrt{2}\)
NDA (II) 2012
Motion in One Dimensions
141740
Two balls of same size but the density of one is greater than that of the other are dropped from the same height, then which ball will reach the earth first (air resistance is negligible)?
1 Heavy ball
2 Light ball
3 Both simultaneously
4 Will depend upon the density of the balls
Explanation:
C We know that, \(\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2} \Rightarrow \mathrm{t}=\sqrt{\frac{2(\mathrm{~s}-\mathrm{ut})}{\mathrm{g}}}\) Since, \(\mathrm{s}, \mathrm{u}\) and \(\mathrm{g}\) are same for both, Hence, both ball will reach the earth in same time.
J and K-CET- 2004
Motion in One Dimensions
141760
A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represent the velocity time plot for the period ball remains in air?
1
2
3
4
Explanation:
A \(\mathrm{v}=\mathrm{u}-\mathrm{gt}\) correct figure: During upward position velocity is decreasing and become zero and magnitude of velocity is increasing in downward direction.
DCE- 2007
Motion in One Dimensions
141771
If a ball is thrown vertically upwards with speed \(u\), the distance covered during the last \(t\) sec of its ascent is
1 \(\mathrm{ut}-\frac{1}{2} \mathrm{gt}^{2}\)
2 \((u+g t) t\)
3 ut
4 \(\frac{1}{2} \mathrm{gt}^{2}\)
Explanation:
D We know that, \(\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{h}=0 \times \mathrm{t}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{~h}=\frac{1}{2} \mathrm{gt}^{2}\)
141783
A staircase has 5 steps each \(10 \mathrm{~cm}\) high and \(10 \mathrm{~cm}\) wide. What is the minimum horizontal velocity to be given to the ball so that it hits directly the lowest plane from the top of the staircase? \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
1 \(2 \mathrm{~ms}^{-1}\)
2 \(1 \mathrm{~ms}^{-1}\)
3 \(\sqrt{2} \mathrm{~ms}^{-1}\)
4 \(1 / 2 \mathrm{~ms}^{-1}\)
Explanation:
C \(\mathrm{y}=10 \mathrm{~cm}\) \(\mathrm{x}=10 \mathrm{~cm}\) \(\mathrm{~h}=5\) \(\mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^{2}\) Distance travelled is vertical direction \(\mathrm{y}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \mathrm{gt}^{2}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}\) \(\mathrm{t}^{2}=\frac{5 \times \frac{1}{10}}{5}=\frac{1}{10}\) \(\mathrm{t}=\frac{1}{\sqrt{10}}\) \(\mathrm{hy}=1 / 2 \times 10 \times \mathrm{t}^{2}==5 \mathrm{t}^{2}\) Distance travelled in the horizontal direction is \(\mathrm{hx} \simeq \mathrm{ut}\) \(5 \times \frac{1}{10}=\mathrm{u} \times \frac{1}{\sqrt{10}}\) \(\mathrm{u}=\frac{5 \times \sqrt{10}}{10}\) \(\mathrm{u}=\sqrt{2}\)
NDA (II) 2012
Motion in One Dimensions
141740
Two balls of same size but the density of one is greater than that of the other are dropped from the same height, then which ball will reach the earth first (air resistance is negligible)?
1 Heavy ball
2 Light ball
3 Both simultaneously
4 Will depend upon the density of the balls
Explanation:
C We know that, \(\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2} \Rightarrow \mathrm{t}=\sqrt{\frac{2(\mathrm{~s}-\mathrm{ut})}{\mathrm{g}}}\) Since, \(\mathrm{s}, \mathrm{u}\) and \(\mathrm{g}\) are same for both, Hence, both ball will reach the earth in same time.
J and K-CET- 2004
Motion in One Dimensions
141760
A ball is thrown vertically upward. Ignoring the air resistance, which one of the following plot represent the velocity time plot for the period ball remains in air?
1
2
3
4
Explanation:
A \(\mathrm{v}=\mathrm{u}-\mathrm{gt}\) correct figure: During upward position velocity is decreasing and become zero and magnitude of velocity is increasing in downward direction.
DCE- 2007
Motion in One Dimensions
141771
If a ball is thrown vertically upwards with speed \(u\), the distance covered during the last \(t\) sec of its ascent is
1 \(\mathrm{ut}-\frac{1}{2} \mathrm{gt}^{2}\)
2 \((u+g t) t\)
3 ut
4 \(\frac{1}{2} \mathrm{gt}^{2}\)
Explanation:
D We know that, \(\mathrm{h}=\mathrm{ut}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{h}=0 \times \mathrm{t}+\frac{1}{2} \mathrm{gt}^{2}\) \(\mathrm{~h}=\frac{1}{2} \mathrm{gt}^{2}\)