141657 A particle is moving on a circular path with a constant speed \(v\). It's change of velocity as it moves from \(A\) to \(B\) in the figure is-

141658 Particle \(A\) (which is located at the origin at time \(t=0\) ) is moving along the \(x\) - axis with a constant velocity \(1 \mathrm{~ms}^{-1}\). Another particle \(B\) is moving along the \(y\)-axis according to, \(y=c^{3}\); \(c=1 \mathrm{~ms}^{-1}\). Then the velocity of \(A\) relative to \(B\) at \(\mathbf{t}=\mathbf{1}\) is

141659 The variation of induced emf \((F)\) with time ( \(t\) ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

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141660 Two cars \(A\) and \(B\) initially at rest are moving in same direction with accelerations \(a_{1}\) and \(a_{2}\) respectively. After a certain time, they achieve velocities \(v_{1}\) and \(v_{2}\) respectively and separated are by a distance of \(50 \mathrm{~m}\). If \(\left(a_{1}-a_{2}\right)=4 \mathrm{~m} / \mathrm{s}^{2}\), then the quantity \(\left(v_{1}-v_{2}\right)\) will be

141657 A particle is moving on a circular path with a constant speed \(v\). It's change of velocity as it moves from \(A\) to \(B\) in the figure is-

141658 Particle \(A\) (which is located at the origin at time \(t=0\) ) is moving along the \(x\) - axis with a constant velocity \(1 \mathrm{~ms}^{-1}\). Another particle \(B\) is moving along the \(y\)-axis according to, \(y=c^{3}\); \(c=1 \mathrm{~ms}^{-1}\). Then the velocity of \(A\) relative to \(B\) at \(\mathbf{t}=\mathbf{1}\) is

141659 The variation of induced emf \((F)\) with time ( \(t\) ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

1

2

3

4

141660 Two cars \(A\) and \(B\) initially at rest are moving in same direction with accelerations \(a_{1}\) and \(a_{2}\) respectively. After a certain time, they achieve velocities \(v_{1}\) and \(v_{2}\) respectively and separated are by a distance of \(50 \mathrm{~m}\). If \(\left(a_{1}-a_{2}\right)=4 \mathrm{~m} / \mathrm{s}^{2}\), then the quantity \(\left(v_{1}-v_{2}\right)\) will be

141657 A particle is moving on a circular path with a constant speed \(v\). It's change of velocity as it moves from \(A\) to \(B\) in the figure is-

141658 Particle \(A\) (which is located at the origin at time \(t=0\) ) is moving along the \(x\) - axis with a constant velocity \(1 \mathrm{~ms}^{-1}\). Another particle \(B\) is moving along the \(y\)-axis according to, \(y=c^{3}\); \(c=1 \mathrm{~ms}^{-1}\). Then the velocity of \(A\) relative to \(B\) at \(\mathbf{t}=\mathbf{1}\) is

141659 The variation of induced emf \((F)\) with time ( \(t\) ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

1

2

3

4

141660 Two cars \(A\) and \(B\) initially at rest are moving in same direction with accelerations \(a_{1}\) and \(a_{2}\) respectively. After a certain time, they achieve velocities \(v_{1}\) and \(v_{2}\) respectively and separated are by a distance of \(50 \mathrm{~m}\). If \(\left(a_{1}-a_{2}\right)=4 \mathrm{~m} / \mathrm{s}^{2}\), then the quantity \(\left(v_{1}-v_{2}\right)\) will be

141657 A particle is moving on a circular path with a constant speed \(v\). It's change of velocity as it moves from \(A\) to \(B\) in the figure is-

141658 Particle \(A\) (which is located at the origin at time \(t=0\) ) is moving along the \(x\) - axis with a constant velocity \(1 \mathrm{~ms}^{-1}\). Another particle \(B\) is moving along the \(y\)-axis according to, \(y=c^{3}\); \(c=1 \mathrm{~ms}^{-1}\). Then the velocity of \(A\) relative to \(B\) at \(\mathbf{t}=\mathbf{1}\) is

141659 The variation of induced emf \((F)\) with time ( \(t\) ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

1

2

3

4

141660 Two cars \(A\) and \(B\) initially at rest are moving in same direction with accelerations \(a_{1}\) and \(a_{2}\) respectively. After a certain time, they achieve velocities \(v_{1}\) and \(v_{2}\) respectively and separated are by a distance of \(50 \mathrm{~m}\). If \(\left(a_{1}-a_{2}\right)=4 \mathrm{~m} / \mathrm{s}^{2}\), then the quantity \(\left(v_{1}-v_{2}\right)\) will be