141174 A particle starts from rest. Its acceleration (a) versus time ( \(t\) ) is as shown in the figure. The maximum speed of the particle will be

141176 A time varying force acts on a ball of mass 100 \(\mathrm{g}\) for \(2 \mathrm{~ms}\). The force versus time curve is shown below. If the initial speed of the ball is \(10 \mathrm{~m} / \mathrm{s}\), then the speed of ball after \(2 \mathrm{~ms}\) is

141177 A body starts from the rest and acquires a velocity of \(10 \mathrm{~m} / \mathrm{s}\) in \(2 \mathrm{~s}\). What is the acceleration of the body and the distance travelled

141178 A rocket moves straight upward with zero initial velocity and with an acceleration \(20 \mathrm{~m} / \mathrm{s}^{2}\). It runs out of fuel and stops accelerating at the end of \(5^{\text {th }}\) sec. It reaches a maximum height and falls back to the earth. The speed when it hits the ground is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141174 A particle starts from rest. Its acceleration (a) versus time ( \(t\) ) is as shown in the figure. The maximum speed of the particle will be

141176 A time varying force acts on a ball of mass 100 \(\mathrm{g}\) for \(2 \mathrm{~ms}\). The force versus time curve is shown below. If the initial speed of the ball is \(10 \mathrm{~m} / \mathrm{s}\), then the speed of ball after \(2 \mathrm{~ms}\) is

141177 A body starts from the rest and acquires a velocity of \(10 \mathrm{~m} / \mathrm{s}\) in \(2 \mathrm{~s}\). What is the acceleration of the body and the distance travelled

141178 A rocket moves straight upward with zero initial velocity and with an acceleration \(20 \mathrm{~m} / \mathrm{s}^{2}\). It runs out of fuel and stops accelerating at the end of \(5^{\text {th }}\) sec. It reaches a maximum height and falls back to the earth. The speed when it hits the ground is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141174 A particle starts from rest. Its acceleration (a) versus time ( \(t\) ) is as shown in the figure. The maximum speed of the particle will be

141176 A time varying force acts on a ball of mass 100 \(\mathrm{g}\) for \(2 \mathrm{~ms}\). The force versus time curve is shown below. If the initial speed of the ball is \(10 \mathrm{~m} / \mathrm{s}\), then the speed of ball after \(2 \mathrm{~ms}\) is

141177 A body starts from the rest and acquires a velocity of \(10 \mathrm{~m} / \mathrm{s}\) in \(2 \mathrm{~s}\). What is the acceleration of the body and the distance travelled

141178 A rocket moves straight upward with zero initial velocity and with an acceleration \(20 \mathrm{~m} / \mathrm{s}^{2}\). It runs out of fuel and stops accelerating at the end of \(5^{\text {th }}\) sec. It reaches a maximum height and falls back to the earth. The speed when it hits the ground is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )

141174 A particle starts from rest. Its acceleration (a) versus time ( \(t\) ) is as shown in the figure. The maximum speed of the particle will be

141176 A time varying force acts on a ball of mass 100 \(\mathrm{g}\) for \(2 \mathrm{~ms}\). The force versus time curve is shown below. If the initial speed of the ball is \(10 \mathrm{~m} / \mathrm{s}\), then the speed of ball after \(2 \mathrm{~ms}\) is

141177 A body starts from the rest and acquires a velocity of \(10 \mathrm{~m} / \mathrm{s}\) in \(2 \mathrm{~s}\). What is the acceleration of the body and the distance travelled

141178 A rocket moves straight upward with zero initial velocity and with an acceleration \(20 \mathrm{~m} / \mathrm{s}^{2}\). It runs out of fuel and stops accelerating at the end of \(5^{\text {th }}\) sec. It reaches a maximum height and falls back to the earth. The speed when it hits the ground is (Take \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) )