141236 The speed versus time graph of moving particle is shown in the following figure If ' \(u\) ' is the initial speed at \(t=0, v\) is the speed at time \(t\). ' \(a\) ' is the acceleration and ' \(s\) ' is the distance covered in time ' \(t\) ', then total area OABC is best described using. (Assume \(\mathrm{O}\) as origin).

141237 Points \(P, Q\) and \(R\) are in a vertical line such that \(P Q=Q R\). \(A\) ball at \(P\) is allowed to fall freely with zero initial speed. The ratio of the times of descent through \(P Q\) and \(Q R\) is

141238 \(\quad A\) and \(B\) are the ends of a ladder in contact with a vertical wall and the floor respectively as shown in the figure. Let \(u_{B}\) and \(v_{A}\) be the velocities of \(B\) and \(A\) in \(x\) and \(y\) direction respectively. At a time when the angle \(\mathrm{ABO}\) is \(60^{\circ}, u_{B}=1 \mathrm{~m} / \mathrm{s}\), then \(v_{A}\) in \(\mathrm{m} / \mathrm{s}\) is

141240 Assertion: The displacement-time graph of a body moving with uniform acceleration is a parabola.
Reason: The displacement is proportional to time for uniformly accelerated motion.

141236 The speed versus time graph of moving particle is shown in the following figure If ' \(u\) ' is the initial speed at \(t=0, v\) is the speed at time \(t\). ' \(a\) ' is the acceleration and ' \(s\) ' is the distance covered in time ' \(t\) ', then total area OABC is best described using. (Assume \(\mathrm{O}\) as origin).

141237 Points \(P, Q\) and \(R\) are in a vertical line such that \(P Q=Q R\). \(A\) ball at \(P\) is allowed to fall freely with zero initial speed. The ratio of the times of descent through \(P Q\) and \(Q R\) is

141238 \(\quad A\) and \(B\) are the ends of a ladder in contact with a vertical wall and the floor respectively as shown in the figure. Let \(u_{B}\) and \(v_{A}\) be the velocities of \(B\) and \(A\) in \(x\) and \(y\) direction respectively. At a time when the angle \(\mathrm{ABO}\) is \(60^{\circ}, u_{B}=1 \mathrm{~m} / \mathrm{s}\), then \(v_{A}\) in \(\mathrm{m} / \mathrm{s}\) is

141240 Assertion: The displacement-time graph of a body moving with uniform acceleration is a parabola.
Reason: The displacement is proportional to time for uniformly accelerated motion.

141236 The speed versus time graph of moving particle is shown in the following figure If ' \(u\) ' is the initial speed at \(t=0, v\) is the speed at time \(t\). ' \(a\) ' is the acceleration and ' \(s\) ' is the distance covered in time ' \(t\) ', then total area OABC is best described using. (Assume \(\mathrm{O}\) as origin).

141237 Points \(P, Q\) and \(R\) are in a vertical line such that \(P Q=Q R\). \(A\) ball at \(P\) is allowed to fall freely with zero initial speed. The ratio of the times of descent through \(P Q\) and \(Q R\) is

141238 \(\quad A\) and \(B\) are the ends of a ladder in contact with a vertical wall and the floor respectively as shown in the figure. Let \(u_{B}\) and \(v_{A}\) be the velocities of \(B\) and \(A\) in \(x\) and \(y\) direction respectively. At a time when the angle \(\mathrm{ABO}\) is \(60^{\circ}, u_{B}=1 \mathrm{~m} / \mathrm{s}\), then \(v_{A}\) in \(\mathrm{m} / \mathrm{s}\) is

141240 Assertion: The displacement-time graph of a body moving with uniform acceleration is a parabola.
Reason: The displacement is proportional to time for uniformly accelerated motion.

141236 The speed versus time graph of moving particle is shown in the following figure If ' \(u\) ' is the initial speed at \(t=0, v\) is the speed at time \(t\). ' \(a\) ' is the acceleration and ' \(s\) ' is the distance covered in time ' \(t\) ', then total area OABC is best described using. (Assume \(\mathrm{O}\) as origin).

141237 Points \(P, Q\) and \(R\) are in a vertical line such that \(P Q=Q R\). \(A\) ball at \(P\) is allowed to fall freely with zero initial speed. The ratio of the times of descent through \(P Q\) and \(Q R\) is

141238 \(\quad A\) and \(B\) are the ends of a ladder in contact with a vertical wall and the floor respectively as shown in the figure. Let \(u_{B}\) and \(v_{A}\) be the velocities of \(B\) and \(A\) in \(x\) and \(y\) direction respectively. At a time when the angle \(\mathrm{ABO}\) is \(60^{\circ}, u_{B}=1 \mathrm{~m} / \mathrm{s}\), then \(v_{A}\) in \(\mathrm{m} / \mathrm{s}\) is

141240 Assertion: The displacement-time graph of a body moving with uniform acceleration is a parabola.
Reason: The displacement is proportional to time for uniformly accelerated motion.