139824 When two resistors of resistances \(R_{1}=(200 \pm 2)\) \(\Omega\) and \(R_{2}=(400 \pm 4) \Omega\) are connected in series, the equivalent resistance of the combination is

139825 The period of oscillation of a simple pendulum is \(T=2 \pi \sqrt{\frac{L}{g}}\). Measured value of \(L\) is \(1.0 \mathrm{~m}\) from metre scale having a minimum division of \(1 \mathrm{~mm}\) and time of one complete oscillation is \(1.95 \mathrm{~s}\) measured from stopwatch of \(0.01 \mathrm{~s}\) resolution. The percentage error in the determination of \(\mathbf{g}\) will be

139826 In order to determine the Young's modulus of a wire of radius \(0.2 \mathrm{~cm}\) (measured using a scale of least count \(=0.001 \mathrm{~cm}\) ) and length \(1 \mathrm{~m}\) ( measured using a scale of least count \(=1 \mathrm{~mm}\) ), a weight of mass \(1 \mathrm{~kg}\) (measured using a scale of least count \(=1 \mathrm{~g}\) ) was hanged to get the elongation of \(0.5 \mathrm{~cm}\) (measured using a scale of least count \(0.001 \mathrm{~cm}\) ). What will be the fractional error in the value of Young's modulus determined by this experiment ?

139827 If the length of the pendulum in pendulum clock increases by \(0.1 \%\), then the error in time per day is

139824 When two resistors of resistances \(R_{1}=(200 \pm 2)\) \(\Omega\) and \(R_{2}=(400 \pm 4) \Omega\) are connected in series, the equivalent resistance of the combination is

139825 The period of oscillation of a simple pendulum is \(T=2 \pi \sqrt{\frac{L}{g}}\). Measured value of \(L\) is \(1.0 \mathrm{~m}\) from metre scale having a minimum division of \(1 \mathrm{~mm}\) and time of one complete oscillation is \(1.95 \mathrm{~s}\) measured from stopwatch of \(0.01 \mathrm{~s}\) resolution. The percentage error in the determination of \(\mathbf{g}\) will be

139826 In order to determine the Young's modulus of a wire of radius \(0.2 \mathrm{~cm}\) (measured using a scale of least count \(=0.001 \mathrm{~cm}\) ) and length \(1 \mathrm{~m}\) ( measured using a scale of least count \(=1 \mathrm{~mm}\) ), a weight of mass \(1 \mathrm{~kg}\) (measured using a scale of least count \(=1 \mathrm{~g}\) ) was hanged to get the elongation of \(0.5 \mathrm{~cm}\) (measured using a scale of least count \(0.001 \mathrm{~cm}\) ). What will be the fractional error in the value of Young's modulus determined by this experiment ?

139827 If the length of the pendulum in pendulum clock increases by \(0.1 \%\), then the error in time per day is

139824 When two resistors of resistances \(R_{1}=(200 \pm 2)\) \(\Omega\) and \(R_{2}=(400 \pm 4) \Omega\) are connected in series, the equivalent resistance of the combination is

139825 The period of oscillation of a simple pendulum is \(T=2 \pi \sqrt{\frac{L}{g}}\). Measured value of \(L\) is \(1.0 \mathrm{~m}\) from metre scale having a minimum division of \(1 \mathrm{~mm}\) and time of one complete oscillation is \(1.95 \mathrm{~s}\) measured from stopwatch of \(0.01 \mathrm{~s}\) resolution. The percentage error in the determination of \(\mathbf{g}\) will be

139826 In order to determine the Young's modulus of a wire of radius \(0.2 \mathrm{~cm}\) (measured using a scale of least count \(=0.001 \mathrm{~cm}\) ) and length \(1 \mathrm{~m}\) ( measured using a scale of least count \(=1 \mathrm{~mm}\) ), a weight of mass \(1 \mathrm{~kg}\) (measured using a scale of least count \(=1 \mathrm{~g}\) ) was hanged to get the elongation of \(0.5 \mathrm{~cm}\) (measured using a scale of least count \(0.001 \mathrm{~cm}\) ). What will be the fractional error in the value of Young's modulus determined by this experiment ?

139827 If the length of the pendulum in pendulum clock increases by \(0.1 \%\), then the error in time per day is

139824 When two resistors of resistances \(R_{1}=(200 \pm 2)\) \(\Omega\) and \(R_{2}=(400 \pm 4) \Omega\) are connected in series, the equivalent resistance of the combination is

139825 The period of oscillation of a simple pendulum is \(T=2 \pi \sqrt{\frac{L}{g}}\). Measured value of \(L\) is \(1.0 \mathrm{~m}\) from metre scale having a minimum division of \(1 \mathrm{~mm}\) and time of one complete oscillation is \(1.95 \mathrm{~s}\) measured from stopwatch of \(0.01 \mathrm{~s}\) resolution. The percentage error in the determination of \(\mathbf{g}\) will be

139826 In order to determine the Young's modulus of a wire of radius \(0.2 \mathrm{~cm}\) (measured using a scale of least count \(=0.001 \mathrm{~cm}\) ) and length \(1 \mathrm{~m}\) ( measured using a scale of least count \(=1 \mathrm{~mm}\) ), a weight of mass \(1 \mathrm{~kg}\) (measured using a scale of least count \(=1 \mathrm{~g}\) ) was hanged to get the elongation of \(0.5 \mathrm{~cm}\) (measured using a scale of least count \(0.001 \mathrm{~cm}\) ). What will be the fractional error in the value of Young's modulus determined by this experiment ?

139827 If the length of the pendulum in pendulum clock increases by \(0.1 \%\), then the error in time per day is