279098
The decreasing order of basicity of the following amines
1 (III) \(>\) (I) \(>\) (II) \(>\) (IV)
2 (III) \(>\) (II) \(>\) (I) \(>\) (IV)
3 (I) \(>\) (III) \(>\) (IV) \(>\) (II)
4 (II) \(>\) (III) \(>\) (IV) \(>\) (I)
Explanation:
Basicity \(\propto\) Localized lone pair \(\propto \frac{1}{\% \text { s character }}\) In case of (II) and (III), (IV) is more basic because \(\mathrm{N}\) is \(\mathrm{sp}^3\) hybridised i.e \% s character is lesser than \(\mathrm{N}\) of (II) which is \(\mathrm{sp}^2\) hybridised In case of (I) and (IV), (I) is most basic because in case of (IV) lone pair of nitrogen participates in resonance which provide aromatic character to the ring. So, if lone pair of (IV) is donated then its aromaticity is disturbed. Hence (IV) is least basic in nature. Basic strength:- (III) \(>\) (II) \(>\) (I) \(>\) (IV)
JEE Main 2020
AMINES
279100
Arrange the following amines in the decreasing order of basicity:
1 I \(>\) II \(>\) III
2 III \(>\) II \(>\) I
3 I \(>\) III \(>\) II
4 III \(>\) I \(>\) II
Explanation:
Basicity \(\propto\) localized lone pair \(\propto \frac{1}{\% \text { s character }}\) Therefore, correct order of basicity is III \(>\) I \(>\) II
JEE Main 2019
AMINES
279097 The product ' \(B\) ' is
1
2
3
4
Explanation:
Exp:
JEE Main 29.07.2022 Shift-I
AMINES
279099
Compound \([\mathrm{X}]\) M.F \(\mathrm{C}_7 \mathrm{H}_7 \mathrm{NO}\) reacts with \(\mathrm{Br}_{2^{-}}\) \(\mathrm{KOH}\) to yield compound \([\mathrm{Y}]\) which gives mustard oil reaction. The structures of \([\mathrm{X}]\) and \([\mathrm{Y}]\) are
1 acetamide, ethylamine
2 benzamide, aniline
3 benzamide, anicidine
4 nitrosobenzene, aniline
Explanation:
\(1^{\text {st }}\) step of the reaction is known as Hoffmann Bromamide reaction in which alkanamide converts into alkyl amine in presence of \(\mathrm{Br}_2\) and \(\mathrm{KOH}\).
CG PET -2019
AMINES
279101
When tetrahydrofuran is treated with excess \(\mathrm{HI}\), the product formed is
279098
The decreasing order of basicity of the following amines
1 (III) \(>\) (I) \(>\) (II) \(>\) (IV)
2 (III) \(>\) (II) \(>\) (I) \(>\) (IV)
3 (I) \(>\) (III) \(>\) (IV) \(>\) (II)
4 (II) \(>\) (III) \(>\) (IV) \(>\) (I)
Explanation:
Basicity \(\propto\) Localized lone pair \(\propto \frac{1}{\% \text { s character }}\) In case of (II) and (III), (IV) is more basic because \(\mathrm{N}\) is \(\mathrm{sp}^3\) hybridised i.e \% s character is lesser than \(\mathrm{N}\) of (II) which is \(\mathrm{sp}^2\) hybridised In case of (I) and (IV), (I) is most basic because in case of (IV) lone pair of nitrogen participates in resonance which provide aromatic character to the ring. So, if lone pair of (IV) is donated then its aromaticity is disturbed. Hence (IV) is least basic in nature. Basic strength:- (III) \(>\) (II) \(>\) (I) \(>\) (IV)
JEE Main 2020
AMINES
279100
Arrange the following amines in the decreasing order of basicity:
1 I \(>\) II \(>\) III
2 III \(>\) II \(>\) I
3 I \(>\) III \(>\) II
4 III \(>\) I \(>\) II
Explanation:
Basicity \(\propto\) localized lone pair \(\propto \frac{1}{\% \text { s character }}\) Therefore, correct order of basicity is III \(>\) I \(>\) II
JEE Main 2019
AMINES
279097 The product ' \(B\) ' is
1
2
3
4
Explanation:
Exp:
JEE Main 29.07.2022 Shift-I
AMINES
279099
Compound \([\mathrm{X}]\) M.F \(\mathrm{C}_7 \mathrm{H}_7 \mathrm{NO}\) reacts with \(\mathrm{Br}_{2^{-}}\) \(\mathrm{KOH}\) to yield compound \([\mathrm{Y}]\) which gives mustard oil reaction. The structures of \([\mathrm{X}]\) and \([\mathrm{Y}]\) are
1 acetamide, ethylamine
2 benzamide, aniline
3 benzamide, anicidine
4 nitrosobenzene, aniline
Explanation:
\(1^{\text {st }}\) step of the reaction is known as Hoffmann Bromamide reaction in which alkanamide converts into alkyl amine in presence of \(\mathrm{Br}_2\) and \(\mathrm{KOH}\).
CG PET -2019
AMINES
279101
When tetrahydrofuran is treated with excess \(\mathrm{HI}\), the product formed is
279098
The decreasing order of basicity of the following amines
1 (III) \(>\) (I) \(>\) (II) \(>\) (IV)
2 (III) \(>\) (II) \(>\) (I) \(>\) (IV)
3 (I) \(>\) (III) \(>\) (IV) \(>\) (II)
4 (II) \(>\) (III) \(>\) (IV) \(>\) (I)
Explanation:
Basicity \(\propto\) Localized lone pair \(\propto \frac{1}{\% \text { s character }}\) In case of (II) and (III), (IV) is more basic because \(\mathrm{N}\) is \(\mathrm{sp}^3\) hybridised i.e \% s character is lesser than \(\mathrm{N}\) of (II) which is \(\mathrm{sp}^2\) hybridised In case of (I) and (IV), (I) is most basic because in case of (IV) lone pair of nitrogen participates in resonance which provide aromatic character to the ring. So, if lone pair of (IV) is donated then its aromaticity is disturbed. Hence (IV) is least basic in nature. Basic strength:- (III) \(>\) (II) \(>\) (I) \(>\) (IV)
JEE Main 2020
AMINES
279100
Arrange the following amines in the decreasing order of basicity:
1 I \(>\) II \(>\) III
2 III \(>\) II \(>\) I
3 I \(>\) III \(>\) II
4 III \(>\) I \(>\) II
Explanation:
Basicity \(\propto\) localized lone pair \(\propto \frac{1}{\% \text { s character }}\) Therefore, correct order of basicity is III \(>\) I \(>\) II
JEE Main 2019
AMINES
279097 The product ' \(B\) ' is
1
2
3
4
Explanation:
Exp:
JEE Main 29.07.2022 Shift-I
AMINES
279099
Compound \([\mathrm{X}]\) M.F \(\mathrm{C}_7 \mathrm{H}_7 \mathrm{NO}\) reacts with \(\mathrm{Br}_{2^{-}}\) \(\mathrm{KOH}\) to yield compound \([\mathrm{Y}]\) which gives mustard oil reaction. The structures of \([\mathrm{X}]\) and \([\mathrm{Y}]\) are
1 acetamide, ethylamine
2 benzamide, aniline
3 benzamide, anicidine
4 nitrosobenzene, aniline
Explanation:
\(1^{\text {st }}\) step of the reaction is known as Hoffmann Bromamide reaction in which alkanamide converts into alkyl amine in presence of \(\mathrm{Br}_2\) and \(\mathrm{KOH}\).
CG PET -2019
AMINES
279101
When tetrahydrofuran is treated with excess \(\mathrm{HI}\), the product formed is
279098
The decreasing order of basicity of the following amines
1 (III) \(>\) (I) \(>\) (II) \(>\) (IV)
2 (III) \(>\) (II) \(>\) (I) \(>\) (IV)
3 (I) \(>\) (III) \(>\) (IV) \(>\) (II)
4 (II) \(>\) (III) \(>\) (IV) \(>\) (I)
Explanation:
Basicity \(\propto\) Localized lone pair \(\propto \frac{1}{\% \text { s character }}\) In case of (II) and (III), (IV) is more basic because \(\mathrm{N}\) is \(\mathrm{sp}^3\) hybridised i.e \% s character is lesser than \(\mathrm{N}\) of (II) which is \(\mathrm{sp}^2\) hybridised In case of (I) and (IV), (I) is most basic because in case of (IV) lone pair of nitrogen participates in resonance which provide aromatic character to the ring. So, if lone pair of (IV) is donated then its aromaticity is disturbed. Hence (IV) is least basic in nature. Basic strength:- (III) \(>\) (II) \(>\) (I) \(>\) (IV)
JEE Main 2020
AMINES
279100
Arrange the following amines in the decreasing order of basicity:
1 I \(>\) II \(>\) III
2 III \(>\) II \(>\) I
3 I \(>\) III \(>\) II
4 III \(>\) I \(>\) II
Explanation:
Basicity \(\propto\) localized lone pair \(\propto \frac{1}{\% \text { s character }}\) Therefore, correct order of basicity is III \(>\) I \(>\) II
JEE Main 2019
AMINES
279097 The product ' \(B\) ' is
1
2
3
4
Explanation:
Exp:
JEE Main 29.07.2022 Shift-I
AMINES
279099
Compound \([\mathrm{X}]\) M.F \(\mathrm{C}_7 \mathrm{H}_7 \mathrm{NO}\) reacts with \(\mathrm{Br}_{2^{-}}\) \(\mathrm{KOH}\) to yield compound \([\mathrm{Y}]\) which gives mustard oil reaction. The structures of \([\mathrm{X}]\) and \([\mathrm{Y}]\) are
1 acetamide, ethylamine
2 benzamide, aniline
3 benzamide, anicidine
4 nitrosobenzene, aniline
Explanation:
\(1^{\text {st }}\) step of the reaction is known as Hoffmann Bromamide reaction in which alkanamide converts into alkyl amine in presence of \(\mathrm{Br}_2\) and \(\mathrm{KOH}\).
CG PET -2019
AMINES
279101
When tetrahydrofuran is treated with excess \(\mathrm{HI}\), the product formed is
279098
The decreasing order of basicity of the following amines
1 (III) \(>\) (I) \(>\) (II) \(>\) (IV)
2 (III) \(>\) (II) \(>\) (I) \(>\) (IV)
3 (I) \(>\) (III) \(>\) (IV) \(>\) (II)
4 (II) \(>\) (III) \(>\) (IV) \(>\) (I)
Explanation:
Basicity \(\propto\) Localized lone pair \(\propto \frac{1}{\% \text { s character }}\) In case of (II) and (III), (IV) is more basic because \(\mathrm{N}\) is \(\mathrm{sp}^3\) hybridised i.e \% s character is lesser than \(\mathrm{N}\) of (II) which is \(\mathrm{sp}^2\) hybridised In case of (I) and (IV), (I) is most basic because in case of (IV) lone pair of nitrogen participates in resonance which provide aromatic character to the ring. So, if lone pair of (IV) is donated then its aromaticity is disturbed. Hence (IV) is least basic in nature. Basic strength:- (III) \(>\) (II) \(>\) (I) \(>\) (IV)
JEE Main 2020
AMINES
279100
Arrange the following amines in the decreasing order of basicity:
1 I \(>\) II \(>\) III
2 III \(>\) II \(>\) I
3 I \(>\) III \(>\) II
4 III \(>\) I \(>\) II
Explanation:
Basicity \(\propto\) localized lone pair \(\propto \frac{1}{\% \text { s character }}\) Therefore, correct order of basicity is III \(>\) I \(>\) II
JEE Main 2019
AMINES
279097 The product ' \(B\) ' is
1
2
3
4
Explanation:
Exp:
JEE Main 29.07.2022 Shift-I
AMINES
279099
Compound \([\mathrm{X}]\) M.F \(\mathrm{C}_7 \mathrm{H}_7 \mathrm{NO}\) reacts with \(\mathrm{Br}_{2^{-}}\) \(\mathrm{KOH}\) to yield compound \([\mathrm{Y}]\) which gives mustard oil reaction. The structures of \([\mathrm{X}]\) and \([\mathrm{Y}]\) are
1 acetamide, ethylamine
2 benzamide, aniline
3 benzamide, anicidine
4 nitrosobenzene, aniline
Explanation:
\(1^{\text {st }}\) step of the reaction is known as Hoffmann Bromamide reaction in which alkanamide converts into alkyl amine in presence of \(\mathrm{Br}_2\) and \(\mathrm{KOH}\).
CG PET -2019
AMINES
279101
When tetrahydrofuran is treated with excess \(\mathrm{HI}\), the product formed is
