278772
Which statement is NOT correct for ptoluenesulphonyl chloride?
1 It is known as hinsberg's reagent
2 It is used to distinguish primary and secondary amines
3 On treatment with secondary amine, it leads to a product that is soluble in alkali
4 It doesn't react with tertiary amines
Explanation:
The chemical formula of p-toluenesulphonyl chloride is given as- (a) p-toluenesulphonyl chloride is the substituted Hinsberg's reagent. (b) Hinsberg's test is used for the detection and distinction of primary, secondary and tertiary amines in a given sample. Hence statement is true. (c) p-toluenesulphonyl chloride on treatment with secondary amine the product of this reaction is insoluble in alkali. Thus, statement is false (d) p-toluenesulphonyl chloride does not react with tertiary amines.
JEE Main-26.06.2022 Shift-II
AMINES
278773
The reaction of with bromine and
KOH gives $\mathrm{RNH}_{2}$ as the end product. Which one of the following is the intermediate product formed in this reaction?
1
2 $\mathrm{R}-\mathrm{NH}-\mathrm{Br}$
3 $\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$
4
Explanation:
The conversion of amide into amine with $\mathrm{Br}_{2}$ and $\mathrm{KOH}$ given by the Hoffmann's Bromamide degradation. Alkylisocyanate
JEE Main-25.06.2022 Shift-I
AMINES
278774 Consider the above reactions, the product $A$ and product $B$ respectively are;
1
2
3
4
Explanation:
JEE Main-29.06.2022 Shift-I
AMINES
278779
With respect to the following reaction, consider the given statements:
1 (A) and (C) are correct statements.
2 (A) and (D) are correct statements.
3 (B) and (D) are correct statements.
4 (B) and (C) are correct statements.
Explanation:
Nitration of aniline gives otho, para and meta nitro anilines but para and also meta are formed in significant amounts, meta isomer is formed due to the formation of anilinium ion,
\(\mathrm{H}_2 \mathrm{SO}_4\) is strong acid, hence
]**
AMINES
278788 Correct statement about the given chemical reaction is
1 __ $\ddot{\mathrm{N}} \mathrm{H}_{2}$ group is ortho and para directing so product (B) is not possible
2 reaction is possible and compound (B) will be the major product
3 the reaction will form sulphonated product instead of nitration.
4 reaction is possible and compound (A) will be major product
Explanation:
Reaction is possible and compound (A) will be major product. Due to formation of anilinium ion by acid base reaction m-product is form as considerable amount.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because in acidic (strong) medium aniline is present as anilinium ion.
278772
Which statement is NOT correct for ptoluenesulphonyl chloride?
1 It is known as hinsberg's reagent
2 It is used to distinguish primary and secondary amines
3 On treatment with secondary amine, it leads to a product that is soluble in alkali
4 It doesn't react with tertiary amines
Explanation:
The chemical formula of p-toluenesulphonyl chloride is given as- (a) p-toluenesulphonyl chloride is the substituted Hinsberg's reagent. (b) Hinsberg's test is used for the detection and distinction of primary, secondary and tertiary amines in a given sample. Hence statement is true. (c) p-toluenesulphonyl chloride on treatment with secondary amine the product of this reaction is insoluble in alkali. Thus, statement is false (d) p-toluenesulphonyl chloride does not react with tertiary amines.
JEE Main-26.06.2022 Shift-II
AMINES
278773
The reaction of with bromine and
KOH gives $\mathrm{RNH}_{2}$ as the end product. Which one of the following is the intermediate product formed in this reaction?
1
2 $\mathrm{R}-\mathrm{NH}-\mathrm{Br}$
3 $\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$
4
Explanation:
The conversion of amide into amine with $\mathrm{Br}_{2}$ and $\mathrm{KOH}$ given by the Hoffmann's Bromamide degradation. Alkylisocyanate
JEE Main-25.06.2022 Shift-I
AMINES
278774 Consider the above reactions, the product $A$ and product $B$ respectively are;
1
2
3
4
Explanation:
JEE Main-29.06.2022 Shift-I
AMINES
278779
With respect to the following reaction, consider the given statements:
1 (A) and (C) are correct statements.
2 (A) and (D) are correct statements.
3 (B) and (D) are correct statements.
4 (B) and (C) are correct statements.
Explanation:
Nitration of aniline gives otho, para and meta nitro anilines but para and also meta are formed in significant amounts, meta isomer is formed due to the formation of anilinium ion,
\(\mathrm{H}_2 \mathrm{SO}_4\) is strong acid, hence
]**
AMINES
278788 Correct statement about the given chemical reaction is
1 __ $\ddot{\mathrm{N}} \mathrm{H}_{2}$ group is ortho and para directing so product (B) is not possible
2 reaction is possible and compound (B) will be the major product
3 the reaction will form sulphonated product instead of nitration.
4 reaction is possible and compound (A) will be major product
Explanation:
Reaction is possible and compound (A) will be major product. Due to formation of anilinium ion by acid base reaction m-product is form as considerable amount.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because in acidic (strong) medium aniline is present as anilinium ion.
278772
Which statement is NOT correct for ptoluenesulphonyl chloride?
1 It is known as hinsberg's reagent
2 It is used to distinguish primary and secondary amines
3 On treatment with secondary amine, it leads to a product that is soluble in alkali
4 It doesn't react with tertiary amines
Explanation:
The chemical formula of p-toluenesulphonyl chloride is given as- (a) p-toluenesulphonyl chloride is the substituted Hinsberg's reagent. (b) Hinsberg's test is used for the detection and distinction of primary, secondary and tertiary amines in a given sample. Hence statement is true. (c) p-toluenesulphonyl chloride on treatment with secondary amine the product of this reaction is insoluble in alkali. Thus, statement is false (d) p-toluenesulphonyl chloride does not react with tertiary amines.
JEE Main-26.06.2022 Shift-II
AMINES
278773
The reaction of with bromine and
KOH gives $\mathrm{RNH}_{2}$ as the end product. Which one of the following is the intermediate product formed in this reaction?
1
2 $\mathrm{R}-\mathrm{NH}-\mathrm{Br}$
3 $\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$
4
Explanation:
The conversion of amide into amine with $\mathrm{Br}_{2}$ and $\mathrm{KOH}$ given by the Hoffmann's Bromamide degradation. Alkylisocyanate
JEE Main-25.06.2022 Shift-I
AMINES
278774 Consider the above reactions, the product $A$ and product $B$ respectively are;
1
2
3
4
Explanation:
JEE Main-29.06.2022 Shift-I
AMINES
278779
With respect to the following reaction, consider the given statements:
1 (A) and (C) are correct statements.
2 (A) and (D) are correct statements.
3 (B) and (D) are correct statements.
4 (B) and (C) are correct statements.
Explanation:
Nitration of aniline gives otho, para and meta nitro anilines but para and also meta are formed in significant amounts, meta isomer is formed due to the formation of anilinium ion,
\(\mathrm{H}_2 \mathrm{SO}_4\) is strong acid, hence
]**
AMINES
278788 Correct statement about the given chemical reaction is
1 __ $\ddot{\mathrm{N}} \mathrm{H}_{2}$ group is ortho and para directing so product (B) is not possible
2 reaction is possible and compound (B) will be the major product
3 the reaction will form sulphonated product instead of nitration.
4 reaction is possible and compound (A) will be major product
Explanation:
Reaction is possible and compound (A) will be major product. Due to formation of anilinium ion by acid base reaction m-product is form as considerable amount.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because in acidic (strong) medium aniline is present as anilinium ion.
278772
Which statement is NOT correct for ptoluenesulphonyl chloride?
1 It is known as hinsberg's reagent
2 It is used to distinguish primary and secondary amines
3 On treatment with secondary amine, it leads to a product that is soluble in alkali
4 It doesn't react with tertiary amines
Explanation:
The chemical formula of p-toluenesulphonyl chloride is given as- (a) p-toluenesulphonyl chloride is the substituted Hinsberg's reagent. (b) Hinsberg's test is used for the detection and distinction of primary, secondary and tertiary amines in a given sample. Hence statement is true. (c) p-toluenesulphonyl chloride on treatment with secondary amine the product of this reaction is insoluble in alkali. Thus, statement is false (d) p-toluenesulphonyl chloride does not react with tertiary amines.
JEE Main-26.06.2022 Shift-II
AMINES
278773
The reaction of with bromine and
KOH gives $\mathrm{RNH}_{2}$ as the end product. Which one of the following is the intermediate product formed in this reaction?
1
2 $\mathrm{R}-\mathrm{NH}-\mathrm{Br}$
3 $\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$
4
Explanation:
The conversion of amide into amine with $\mathrm{Br}_{2}$ and $\mathrm{KOH}$ given by the Hoffmann's Bromamide degradation. Alkylisocyanate
JEE Main-25.06.2022 Shift-I
AMINES
278774 Consider the above reactions, the product $A$ and product $B$ respectively are;
1
2
3
4
Explanation:
JEE Main-29.06.2022 Shift-I
AMINES
278779
With respect to the following reaction, consider the given statements:
1 (A) and (C) are correct statements.
2 (A) and (D) are correct statements.
3 (B) and (D) are correct statements.
4 (B) and (C) are correct statements.
Explanation:
Nitration of aniline gives otho, para and meta nitro anilines but para and also meta are formed in significant amounts, meta isomer is formed due to the formation of anilinium ion,
\(\mathrm{H}_2 \mathrm{SO}_4\) is strong acid, hence
]**
AMINES
278788 Correct statement about the given chemical reaction is
1 __ $\ddot{\mathrm{N}} \mathrm{H}_{2}$ group is ortho and para directing so product (B) is not possible
2 reaction is possible and compound (B) will be the major product
3 the reaction will form sulphonated product instead of nitration.
4 reaction is possible and compound (A) will be major product
Explanation:
Reaction is possible and compound (A) will be major product. Due to formation of anilinium ion by acid base reaction m-product is form as considerable amount.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because in acidic (strong) medium aniline is present as anilinium ion.
278772
Which statement is NOT correct for ptoluenesulphonyl chloride?
1 It is known as hinsberg's reagent
2 It is used to distinguish primary and secondary amines
3 On treatment with secondary amine, it leads to a product that is soluble in alkali
4 It doesn't react with tertiary amines
Explanation:
The chemical formula of p-toluenesulphonyl chloride is given as- (a) p-toluenesulphonyl chloride is the substituted Hinsberg's reagent. (b) Hinsberg's test is used for the detection and distinction of primary, secondary and tertiary amines in a given sample. Hence statement is true. (c) p-toluenesulphonyl chloride on treatment with secondary amine the product of this reaction is insoluble in alkali. Thus, statement is false (d) p-toluenesulphonyl chloride does not react with tertiary amines.
JEE Main-26.06.2022 Shift-II
AMINES
278773
The reaction of with bromine and
KOH gives $\mathrm{RNH}_{2}$ as the end product. Which one of the following is the intermediate product formed in this reaction?
1
2 $\mathrm{R}-\mathrm{NH}-\mathrm{Br}$
3 $\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$
4
Explanation:
The conversion of amide into amine with $\mathrm{Br}_{2}$ and $\mathrm{KOH}$ given by the Hoffmann's Bromamide degradation. Alkylisocyanate
JEE Main-25.06.2022 Shift-I
AMINES
278774 Consider the above reactions, the product $A$ and product $B$ respectively are;
1
2
3
4
Explanation:
JEE Main-29.06.2022 Shift-I
AMINES
278779
With respect to the following reaction, consider the given statements:
1 (A) and (C) are correct statements.
2 (A) and (D) are correct statements.
3 (B) and (D) are correct statements.
4 (B) and (C) are correct statements.
Explanation:
Nitration of aniline gives otho, para and meta nitro anilines but para and also meta are formed in significant amounts, meta isomer is formed due to the formation of anilinium ion,
\(\mathrm{H}_2 \mathrm{SO}_4\) is strong acid, hence
]**
AMINES
278788 Correct statement about the given chemical reaction is
1 __ $\ddot{\mathrm{N}} \mathrm{H}_{2}$ group is ortho and para directing so product (B) is not possible
2 reaction is possible and compound (B) will be the major product
3 the reaction will form sulphonated product instead of nitration.
4 reaction is possible and compound (A) will be major product
Explanation:
Reaction is possible and compound (A) will be major product. Due to formation of anilinium ion by acid base reaction m-product is form as considerable amount.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because in acidic (strong) medium aniline is present as anilinium ion.
with bromine and
