Alkene react with excess of hydrogen bromide $(\mathrm{HBr})$ to form major product 1,2-dibromo propane. In the reaction $-\mathrm{Br}$ added in the place of double bond and $-\mathrm{OH}$ is removed for $-\mathrm{Br}$ group.
**[Kerala CEE-29.08.2021]**
HALOALKANES AND HALOARENES
91103
For the following reactions : Where
1 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}$ (A)
2 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
3 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
4 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})$
Explanation:
is bulky group, therefore it cannot attack $\therefore$ it will act like base. $\mathrm{k}_{\mathrm{s}}<<\mathrm{k}_{\mathrm{e}}$ $\mu_{\mathrm{B}}$ will be very small (A) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$will act like nucleophile as $\begin{aligned} & \therefore \mu_{\mathrm{A}} \text { will be large } \\ & \therefore \mu_{\mathrm{A}}>\mu_{\mathrm{B}} \text { and } \mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A}) \end{aligned}$
7 Jan Shift-I]**
HALOALKANES AND HALOARENES
91098
Identify the major product of the following reaction
1
2
3
4
Explanation:
Shift-I]**
HALOALKANES AND HALOARENES
91100
The major product (A) formed in the reaction given below is:
1
2
3
4
Explanation:
**[JEE MAINS 2021
HALOALKANES AND HALOARENES
91104
The major product of the following reaction is:
Alkene react with excess of hydrogen bromide $(\mathrm{HBr})$ to form major product 1,2-dibromo propane. In the reaction $-\mathrm{Br}$ added in the place of double bond and $-\mathrm{OH}$ is removed for $-\mathrm{Br}$ group.
**[Kerala CEE-29.08.2021]**
HALOALKANES AND HALOARENES
91103
For the following reactions : Where
1 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}$ (A)
2 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
3 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
4 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})$
Explanation:
is bulky group, therefore it cannot attack $\therefore$ it will act like base. $\mathrm{k}_{\mathrm{s}}<<\mathrm{k}_{\mathrm{e}}$ $\mu_{\mathrm{B}}$ will be very small (A) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$will act like nucleophile as $\begin{aligned} & \therefore \mu_{\mathrm{A}} \text { will be large } \\ & \therefore \mu_{\mathrm{A}}>\mu_{\mathrm{B}} \text { and } \mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A}) \end{aligned}$
7 Jan Shift-I]**
HALOALKANES AND HALOARENES
91098
Identify the major product of the following reaction
1
2
3
4
Explanation:
Shift-I]**
HALOALKANES AND HALOARENES
91100
The major product (A) formed in the reaction given below is:
1
2
3
4
Explanation:
**[JEE MAINS 2021
HALOALKANES AND HALOARENES
91104
The major product of the following reaction is:
Alkene react with excess of hydrogen bromide $(\mathrm{HBr})$ to form major product 1,2-dibromo propane. In the reaction $-\mathrm{Br}$ added in the place of double bond and $-\mathrm{OH}$ is removed for $-\mathrm{Br}$ group.
**[Kerala CEE-29.08.2021]**
HALOALKANES AND HALOARENES
91103
For the following reactions : Where
1 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}$ (A)
2 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
3 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
4 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})$
Explanation:
is bulky group, therefore it cannot attack $\therefore$ it will act like base. $\mathrm{k}_{\mathrm{s}}<<\mathrm{k}_{\mathrm{e}}$ $\mu_{\mathrm{B}}$ will be very small (A) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$will act like nucleophile as $\begin{aligned} & \therefore \mu_{\mathrm{A}} \text { will be large } \\ & \therefore \mu_{\mathrm{A}}>\mu_{\mathrm{B}} \text { and } \mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A}) \end{aligned}$
7 Jan Shift-I]**
HALOALKANES AND HALOARENES
91098
Identify the major product of the following reaction
1
2
3
4
Explanation:
Shift-I]**
HALOALKANES AND HALOARENES
91100
The major product (A) formed in the reaction given below is:
1
2
3
4
Explanation:
**[JEE MAINS 2021
HALOALKANES AND HALOARENES
91104
The major product of the following reaction is:
Alkene react with excess of hydrogen bromide $(\mathrm{HBr})$ to form major product 1,2-dibromo propane. In the reaction $-\mathrm{Br}$ added in the place of double bond and $-\mathrm{OH}$ is removed for $-\mathrm{Br}$ group.
**[Kerala CEE-29.08.2021]**
HALOALKANES AND HALOARENES
91103
For the following reactions : Where
1 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}$ (A)
2 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
3 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
4 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})$
Explanation:
is bulky group, therefore it cannot attack $\therefore$ it will act like base. $\mathrm{k}_{\mathrm{s}}<<\mathrm{k}_{\mathrm{e}}$ $\mu_{\mathrm{B}}$ will be very small (A) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$will act like nucleophile as $\begin{aligned} & \therefore \mu_{\mathrm{A}} \text { will be large } \\ & \therefore \mu_{\mathrm{A}}>\mu_{\mathrm{B}} \text { and } \mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A}) \end{aligned}$
7 Jan Shift-I]**
HALOALKANES AND HALOARENES
91098
Identify the major product of the following reaction
1
2
3
4
Explanation:
Shift-I]**
HALOALKANES AND HALOARENES
91100
The major product (A) formed in the reaction given below is:
1
2
3
4
Explanation:
**[JEE MAINS 2021
HALOALKANES AND HALOARENES
91104
The major product of the following reaction is:
Alkene react with excess of hydrogen bromide $(\mathrm{HBr})$ to form major product 1,2-dibromo propane. In the reaction $-\mathrm{Br}$ added in the place of double bond and $-\mathrm{OH}$ is removed for $-\mathrm{Br}$ group.
**[Kerala CEE-29.08.2021]**
HALOALKANES AND HALOARENES
91103
For the following reactions : Where
1 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}$ (A)
2 $\mu_{\mathrm{B}}>\mu_{\mathrm{A}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
3 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{A})>\mathrm{k}_{\mathrm{e}}$ (B)
4 $\mu_{\mathrm{A}}>\mu_{\mathrm{B}}$ and $\mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A})$
Explanation:
is bulky group, therefore it cannot attack $\therefore$ it will act like base. $\mathrm{k}_{\mathrm{s}}<<\mathrm{k}_{\mathrm{e}}$ $\mu_{\mathrm{B}}$ will be very small (A) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}$will act like nucleophile as $\begin{aligned} & \therefore \mu_{\mathrm{A}} \text { will be large } \\ & \therefore \mu_{\mathrm{A}}>\mu_{\mathrm{B}} \text { and } \mathrm{k}_{\mathrm{e}}(\mathrm{B})>\mathrm{k}_{\mathrm{e}}(\mathrm{A}) \end{aligned}$
7 Jan Shift-I]**
HALOALKANES AND HALOARENES
91098
Identify the major product of the following reaction
1
2
3
4
Explanation:
Shift-I]**
HALOALKANES AND HALOARENES
91100
The major product (A) formed in the reaction given below is:
1
2
3
4
Explanation:
**[JEE MAINS 2021
HALOALKANES AND HALOARENES
91104
The major product of the following reaction is:
