QBManager

HALOALKANES AND HALOARENES

90857 The correct sequence of bond enthalpy of ' $C$ $X^{'}$ bond is

1

{CH}_{3} - Cl > {CH}_{3} - F > {CH}_{3} - Br > {CH}_{3} - I

2

{CH}_{3} - F < {CH}_{3} - Cl < {CH}_{3} - Br > {CH}_{3} - I

3

{CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

4

{CH}_{3} - F < {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

Explanation:

The correct sequence of bond enthalpy of 'C $X$ ' bond is-
${CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I$

**[NEET 2021]**

HALOALKANES AND HALOARENES

90936 Compound ' $A$ ' on treatment with zinc forms ethane, 'A' also reacts with alc. $KOH$ to give vinyl bromide.
The compound ' $A$ ' is

1 1 -bromoethene

2 1,1-dibromoethene

3 1,2-dibromoethene

4 1,2-dibromoethene

**[AMU-2006]**

HALOALKANES AND HALOARENES

90832 This question contains statement $- I$ : and statement-II, of the four choices given after the statements. Choose the one that best describes the two statements.
Statement- I : Aromatic acids do not undergo Friedel-Crafts reaction.
Statement- II : $- COOH$ is m-directing group.

1 Statement-I is false, Statement-II is true

2 Statement-I is true, Statement-II is true, Statement-II is correct explanation of statement - I

3 Statement-I is true, Statement-II is true, Statement-II is not a correct explanation of statement - I

4 Statement - I is true, Statement

- II

is false

Explanation:

Aromatic carboxylic acids do not undergo Friedel-crafts reaction because the - $COOH$ group is deactivating and the catalyst ${AlCl}_{3}$ gets bonded to $COOH$ group.
$- COOH$ group is Meta directing because it is electronwithdrawing group with $- R$ effect. There is +ve charge on ortho and para positions. So, electrophilic substitution takes place at Meta position. Here, both statements are true but statement II is not correct explanation of statement I.

**[TS EAMCETCG PET-22.05.2022]**

HALOALKANES AND HALOARENES

90834 In Friedel-Crafts alkylation of aniline, one gets

1 Alkylated product with ortho and para substitution.

2 Secondary amine after acidic treatment.

3 An amide product.

4 Positively charged nitrogen at benzene ring.

Shift-II]**

HALOALKANES AND HALOARENES

90857 The correct sequence of bond enthalpy of ' $C$ $X^{'}$ bond is

1

{CH}_{3} - Cl > {CH}_{3} - F > {CH}_{3} - Br > {CH}_{3} - I

2

{CH}_{3} - F < {CH}_{3} - Cl < {CH}_{3} - Br > {CH}_{3} - I

3

{CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

4

{CH}_{3} - F < {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

Explanation:

The correct sequence of bond enthalpy of 'C $X$ ' bond is-
${CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I$

**[NEET 2021]**

HALOALKANES AND HALOARENES

90936 Compound ' $A$ ' on treatment with zinc forms ethane, 'A' also reacts with alc. $KOH$ to give vinyl bromide.
The compound ' $A$ ' is

1 1 -bromoethene

2 1,1-dibromoethene

3 1,2-dibromoethene

4 1,2-dibromoethene

**[AMU-2006]**

HALOALKANES AND HALOARENES

90832 This question contains statement $- I$ : and statement-II, of the four choices given after the statements. Choose the one that best describes the two statements.
Statement- I : Aromatic acids do not undergo Friedel-Crafts reaction.
Statement- II : $- COOH$ is m-directing group.

1 Statement-I is false, Statement-II is true

2 Statement-I is true, Statement-II is true, Statement-II is correct explanation of statement - I

3 Statement-I is true, Statement-II is true, Statement-II is not a correct explanation of statement - I

4 Statement - I is true, Statement

- II

is false

Explanation:

Aromatic carboxylic acids do not undergo Friedel-crafts reaction because the - $COOH$ group is deactivating and the catalyst ${AlCl}_{3}$ gets bonded to $COOH$ group.
$- COOH$ group is Meta directing because it is electronwithdrawing group with $- R$ effect. There is +ve charge on ortho and para positions. So, electrophilic substitution takes place at Meta position. Here, both statements are true but statement II is not correct explanation of statement I.

**[TS EAMCETCG PET-22.05.2022]**

HALOALKANES AND HALOARENES

90834 In Friedel-Crafts alkylation of aniline, one gets

1 Alkylated product with ortho and para substitution.

2 Secondary amine after acidic treatment.

3 An amide product.

4 Positively charged nitrogen at benzene ring.

Shift-II]**

HALOALKANES AND HALOARENES

90857 The correct sequence of bond enthalpy of ' $C$ $X^{'}$ bond is

1

{CH}_{3} - Cl > {CH}_{3} - F > {CH}_{3} - Br > {CH}_{3} - I

2

{CH}_{3} - F < {CH}_{3} - Cl < {CH}_{3} - Br > {CH}_{3} - I

3

{CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

4

{CH}_{3} - F < {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

Explanation:

The correct sequence of bond enthalpy of 'C $X$ ' bond is-
${CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I$

**[NEET 2021]**

HALOALKANES AND HALOARENES

90936 Compound ' $A$ ' on treatment with zinc forms ethane, 'A' also reacts with alc. $KOH$ to give vinyl bromide.
The compound ' $A$ ' is

1 1 -bromoethene

2 1,1-dibromoethene

3 1,2-dibromoethene

4 1,2-dibromoethene

**[AMU-2006]**

HALOALKANES AND HALOARENES

90832 This question contains statement $- I$ : and statement-II, of the four choices given after the statements. Choose the one that best describes the two statements.
Statement- I : Aromatic acids do not undergo Friedel-Crafts reaction.
Statement- II : $- COOH$ is m-directing group.

1 Statement-I is false, Statement-II is true

2 Statement-I is true, Statement-II is true, Statement-II is correct explanation of statement - I

3 Statement-I is true, Statement-II is true, Statement-II is not a correct explanation of statement - I

4 Statement - I is true, Statement

- II

is false

Explanation:

Aromatic carboxylic acids do not undergo Friedel-crafts reaction because the - $COOH$ group is deactivating and the catalyst ${AlCl}_{3}$ gets bonded to $COOH$ group.
$- COOH$ group is Meta directing because it is electronwithdrawing group with $- R$ effect. There is +ve charge on ortho and para positions. So, electrophilic substitution takes place at Meta position. Here, both statements are true but statement II is not correct explanation of statement I.

**[TS EAMCETCG PET-22.05.2022]**

HALOALKANES AND HALOARENES

90834 In Friedel-Crafts alkylation of aniline, one gets

1 Alkylated product with ortho and para substitution.

2 Secondary amine after acidic treatment.

3 An amide product.

4 Positively charged nitrogen at benzene ring.

Shift-II]**

HALOALKANES AND HALOARENES

90857 The correct sequence of bond enthalpy of ' $C$ $X^{'}$ bond is

1

{CH}_{3} - Cl > {CH}_{3} - F > {CH}_{3} - Br > {CH}_{3} - I

2

{CH}_{3} - F < {CH}_{3} - Cl < {CH}_{3} - Br > {CH}_{3} - I

3

{CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

4

{CH}_{3} - F < {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I

Explanation:

The correct sequence of bond enthalpy of 'C $X$ ' bond is-
${CH}_{3} - F > {CH}_{3} - Cl > {CH}_{3} - Br > {CH}_{3} - I$

**[NEET 2021]**

HALOALKANES AND HALOARENES

90936 Compound ' $A$ ' on treatment with zinc forms ethane, 'A' also reacts with alc. $KOH$ to give vinyl bromide.
The compound ' $A$ ' is

1 1 -bromoethene

2 1,1-dibromoethene

3 1,2-dibromoethene

4 1,2-dibromoethene

**[AMU-2006]**

HALOALKANES AND HALOARENES

90832 This question contains statement $- I$ : and statement-II, of the four choices given after the statements. Choose the one that best describes the two statements.
Statement- I : Aromatic acids do not undergo Friedel-Crafts reaction.
Statement- II : $- COOH$ is m-directing group.

1 Statement-I is false, Statement-II is true

2 Statement-I is true, Statement-II is true, Statement-II is correct explanation of statement - I

3 Statement-I is true, Statement-II is true, Statement-II is not a correct explanation of statement - I

4 Statement - I is true, Statement

- II

is false

Explanation:

Aromatic carboxylic acids do not undergo Friedel-crafts reaction because the - $COOH$ group is deactivating and the catalyst ${AlCl}_{3}$ gets bonded to $COOH$ group.
$- COOH$ group is Meta directing because it is electronwithdrawing group with $- R$ effect. There is +ve charge on ortho and para positions. So, electrophilic substitution takes place at Meta position. Here, both statements are true but statement II is not correct explanation of statement I.

**[TS EAMCETCG PET-22.05.2022]**

HALOALKANES AND HALOARENES

90834 In Friedel-Crafts alkylation of aniline, one gets

1 Alkylated product with ortho and para substitution.

2 Secondary amine after acidic treatment.

3 An amide product.

4 Positively charged nitrogen at benzene ring.

Shift-II]**