232326 Which one of the following is aromatic?
It is not a aromatic compound because it has $4 \pi$ electron and does not follow Huckel's rule.
It is also an anti-aromatic compound because it does follow Huckel's rule is $(4 n+2) \pi e^{-}$.
It is an aromatic compound because one carbon atom is $\mathrm{sp}^{3}$ hybridized so it also does not follow criteria of aromaticity.
It is a aromatic compound because it follow Huckel's rule and having $(4 n+2) \pi$ electrons where, $\mathrm{n}=0,1,2,3, \ldots \ldots$
232326 Which one of the following is aromatic?
It is not a aromatic compound because it has $4 \pi$ electron and does not follow Huckel's rule.
It is also an anti-aromatic compound because it does follow Huckel's rule is $(4 n+2) \pi e^{-}$.
It is an aromatic compound because one carbon atom is $\mathrm{sp}^{3}$ hybridized so it also does not follow criteria of aromaticity.
It is a aromatic compound because it follow Huckel's rule and having $(4 n+2) \pi$ electrons where, $\mathrm{n}=0,1,2,3, \ldots \ldots$
232326 Which one of the following is aromatic?
It is not a aromatic compound because it has $4 \pi$ electron and does not follow Huckel's rule.
It is also an anti-aromatic compound because it does follow Huckel's rule is $(4 n+2) \pi e^{-}$.
It is an aromatic compound because one carbon atom is $\mathrm{sp}^{3}$ hybridized so it also does not follow criteria of aromaticity.
It is a aromatic compound because it follow Huckel's rule and having $(4 n+2) \pi$ electrons where, $\mathrm{n}=0,1,2,3, \ldots \ldots$
232326 Which one of the following is aromatic?
It is not a aromatic compound because it has $4 \pi$ electron and does not follow Huckel's rule.
It is also an anti-aromatic compound because it does follow Huckel's rule is $(4 n+2) \pi e^{-}$.
It is an aromatic compound because one carbon atom is $\mathrm{sp}^{3}$ hybridized so it also does not follow criteria of aromaticity.
It is a aromatic compound because it follow Huckel's rule and having $(4 n+2) \pi$ electrons where, $\mathrm{n}=0,1,2,3, \ldots \ldots$
