232264
Four compounds, Toluene (I) o-Dichlorobenzene (II), mDichlorobenzene (III) and p-Dichlorobenzene (IV) are arranged in order of increasing dipole moment. The correct order is
1 IV $<$ I $<$ II $<$ III
2 I $<$ II $<$ III $<$ IV
3 II $<$ IV $<$ III $<$ I
4 IV $<$ III $<$ II $<$ I
Explanation:
(A): The increasing order of dipole moment is IV $<$ I $<$ II $<$ III o-m-p has $\alpha=60^{\circ}, 120^{\circ}$ and $180^{\circ}$. Thus the resultant vector for p-derivative is zero because symmetrical bond length of $\mathrm{C}-\mathrm{Cl}$. Hence it is non-polar. The dipole moment of m-dichlorobenzene is more than toulene due to electro negativity of chlorine is more than methyl group. In the lost, the o-dichlro benzene has larger dipole moment due to lower bond angle than m-isomer. $\mu_{R}=\sqrt{\mu_{1}^{2}+\mu_{2}^{2}+2 \mu_{1} \mu_{2} \cos \alpha}$ Where $\alpha$ is bond angle between two substituent.
AMU-2012]
GENERAL ORGANIC CHEMISTRY
232265
Which one of the following compound will have the highest dipole moment?
1
2
3
4
Explanation:
(C): The highest dipole moment in the molecule is Because as we know that mesomeric effect is dominating over Inductive effect and $-\mathrm{OH}$ group show $+\mathrm{H}$ effect while $\mathrm{NO}_{2}$ Show $-\mathrm{M}$ effect. Thus they has net dipole moment in same direction. So option (c) has highest dipole moment mesomeric effect. If bidirectional nature of conjugated system converted into unidirectional with the help of an atom called mesomeric effect.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232266
Which of the following molecules does not have net dipole moment ?
1 $\mathrm{CH}_{3}-\mathrm{Br}$
2 $\mathrm{CH}_{2} \mathrm{Cl}_{2}$
3 $\mathrm{HCOOH}$
4
Explanation:
(D) : It has net dipole moment zero because $\mathrm{C}-\mathrm{C}-\mathrm{H}$ bond are equal and it is non polor.
232264
Four compounds, Toluene (I) o-Dichlorobenzene (II), mDichlorobenzene (III) and p-Dichlorobenzene (IV) are arranged in order of increasing dipole moment. The correct order is
1 IV $<$ I $<$ II $<$ III
2 I $<$ II $<$ III $<$ IV
3 II $<$ IV $<$ III $<$ I
4 IV $<$ III $<$ II $<$ I
Explanation:
(A): The increasing order of dipole moment is IV $<$ I $<$ II $<$ III o-m-p has $\alpha=60^{\circ}, 120^{\circ}$ and $180^{\circ}$. Thus the resultant vector for p-derivative is zero because symmetrical bond length of $\mathrm{C}-\mathrm{Cl}$. Hence it is non-polar. The dipole moment of m-dichlorobenzene is more than toulene due to electro negativity of chlorine is more than methyl group. In the lost, the o-dichlro benzene has larger dipole moment due to lower bond angle than m-isomer. $\mu_{R}=\sqrt{\mu_{1}^{2}+\mu_{2}^{2}+2 \mu_{1} \mu_{2} \cos \alpha}$ Where $\alpha$ is bond angle between two substituent.
AMU-2012]
GENERAL ORGANIC CHEMISTRY
232265
Which one of the following compound will have the highest dipole moment?
1
2
3
4
Explanation:
(C): The highest dipole moment in the molecule is Because as we know that mesomeric effect is dominating over Inductive effect and $-\mathrm{OH}$ group show $+\mathrm{H}$ effect while $\mathrm{NO}_{2}$ Show $-\mathrm{M}$ effect. Thus they has net dipole moment in same direction. So option (c) has highest dipole moment mesomeric effect. If bidirectional nature of conjugated system converted into unidirectional with the help of an atom called mesomeric effect.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232266
Which of the following molecules does not have net dipole moment ?
1 $\mathrm{CH}_{3}-\mathrm{Br}$
2 $\mathrm{CH}_{2} \mathrm{Cl}_{2}$
3 $\mathrm{HCOOH}$
4
Explanation:
(D) : It has net dipole moment zero because $\mathrm{C}-\mathrm{C}-\mathrm{H}$ bond are equal and it is non polor.
232264
Four compounds, Toluene (I) o-Dichlorobenzene (II), mDichlorobenzene (III) and p-Dichlorobenzene (IV) are arranged in order of increasing dipole moment. The correct order is
1 IV $<$ I $<$ II $<$ III
2 I $<$ II $<$ III $<$ IV
3 II $<$ IV $<$ III $<$ I
4 IV $<$ III $<$ II $<$ I
Explanation:
(A): The increasing order of dipole moment is IV $<$ I $<$ II $<$ III o-m-p has $\alpha=60^{\circ}, 120^{\circ}$ and $180^{\circ}$. Thus the resultant vector for p-derivative is zero because symmetrical bond length of $\mathrm{C}-\mathrm{Cl}$. Hence it is non-polar. The dipole moment of m-dichlorobenzene is more than toulene due to electro negativity of chlorine is more than methyl group. In the lost, the o-dichlro benzene has larger dipole moment due to lower bond angle than m-isomer. $\mu_{R}=\sqrt{\mu_{1}^{2}+\mu_{2}^{2}+2 \mu_{1} \mu_{2} \cos \alpha}$ Where $\alpha$ is bond angle between two substituent.
AMU-2012]
GENERAL ORGANIC CHEMISTRY
232265
Which one of the following compound will have the highest dipole moment?
1
2
3
4
Explanation:
(C): The highest dipole moment in the molecule is Because as we know that mesomeric effect is dominating over Inductive effect and $-\mathrm{OH}$ group show $+\mathrm{H}$ effect while $\mathrm{NO}_{2}$ Show $-\mathrm{M}$ effect. Thus they has net dipole moment in same direction. So option (c) has highest dipole moment mesomeric effect. If bidirectional nature of conjugated system converted into unidirectional with the help of an atom called mesomeric effect.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232266
Which of the following molecules does not have net dipole moment ?
1 $\mathrm{CH}_{3}-\mathrm{Br}$
2 $\mathrm{CH}_{2} \mathrm{Cl}_{2}$
3 $\mathrm{HCOOH}$
4
Explanation:
(D) : It has net dipole moment zero because $\mathrm{C}-\mathrm{C}-\mathrm{H}$ bond are equal and it is non polor.
