231705
The reaction intermediate produced by homolytic cleavage of bond is called
1 carbene
2 carbocation
3 carbanion
4 free radical
Explanation:
Homolytic bond fission- when a covalent bond forming in such way that each atom forming covalent bond takes away one electron away one electron shared the cleavage of bond called hemolytic fission. **Example-** Free radical because this reaction takes place only in the presence of heat, light and peroxide bond so the reaction intermediate form is free radical.
J and K CET-(2007)
GENERAL ORGANIC CHEMISTRY
231724
Reimer-Tiemann reaction involves :
1 carbonium ion intermediate
2 carbene intermediate
3 carbanion intermediate
4 free radical intermediate
Explanation:
Reimer Tiemann reaction involve carbene as intermediate, when phenol react with chloroform in the presence of base ortho hydrobenzaldehyde is formed.
are stabilised by hyperconjugation. In $\mathrm{C}_{6} \mathrm{H}_{5} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ benzyl group is resonance stabilised. In the triphenyl methyl carbanium ion, the $\pi$ electrons of all the three benzene rings are delocalised with the vacant p-orbital of central carbon atom. So, it is resonance stabilised. Therefore, it is the most stable among the given carbanion ions. More the number of resonating structures, more will be the stability.
JCECE - 2010
GENERAL ORGANIC CHEMISTRY
231712
Which of the following is not a resonating form of benzaldehyde?
1
2
3
4
Explanation:
The resonating structure of benzadedayde is given as From the above resonating structure, we can say that structure (b) is not possible. In this case, positive charge is on the oxygen atom which is highly stable.
231705
The reaction intermediate produced by homolytic cleavage of bond is called
1 carbene
2 carbocation
3 carbanion
4 free radical
Explanation:
Homolytic bond fission- when a covalent bond forming in such way that each atom forming covalent bond takes away one electron away one electron shared the cleavage of bond called hemolytic fission. **Example-** Free radical because this reaction takes place only in the presence of heat, light and peroxide bond so the reaction intermediate form is free radical.
J and K CET-(2007)
GENERAL ORGANIC CHEMISTRY
231724
Reimer-Tiemann reaction involves :
1 carbonium ion intermediate
2 carbene intermediate
3 carbanion intermediate
4 free radical intermediate
Explanation:
Reimer Tiemann reaction involve carbene as intermediate, when phenol react with chloroform in the presence of base ortho hydrobenzaldehyde is formed.
are stabilised by hyperconjugation. In $\mathrm{C}_{6} \mathrm{H}_{5} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ benzyl group is resonance stabilised. In the triphenyl methyl carbanium ion, the $\pi$ electrons of all the three benzene rings are delocalised with the vacant p-orbital of central carbon atom. So, it is resonance stabilised. Therefore, it is the most stable among the given carbanion ions. More the number of resonating structures, more will be the stability.
JCECE - 2010
GENERAL ORGANIC CHEMISTRY
231712
Which of the following is not a resonating form of benzaldehyde?
1
2
3
4
Explanation:
The resonating structure of benzadedayde is given as From the above resonating structure, we can say that structure (b) is not possible. In this case, positive charge is on the oxygen atom which is highly stable.
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GENERAL ORGANIC CHEMISTRY
231705
The reaction intermediate produced by homolytic cleavage of bond is called
1 carbene
2 carbocation
3 carbanion
4 free radical
Explanation:
Homolytic bond fission- when a covalent bond forming in such way that each atom forming covalent bond takes away one electron away one electron shared the cleavage of bond called hemolytic fission. **Example-** Free radical because this reaction takes place only in the presence of heat, light and peroxide bond so the reaction intermediate form is free radical.
J and K CET-(2007)
GENERAL ORGANIC CHEMISTRY
231724
Reimer-Tiemann reaction involves :
1 carbonium ion intermediate
2 carbene intermediate
3 carbanion intermediate
4 free radical intermediate
Explanation:
Reimer Tiemann reaction involve carbene as intermediate, when phenol react with chloroform in the presence of base ortho hydrobenzaldehyde is formed.
are stabilised by hyperconjugation. In $\mathrm{C}_{6} \mathrm{H}_{5} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ benzyl group is resonance stabilised. In the triphenyl methyl carbanium ion, the $\pi$ electrons of all the three benzene rings are delocalised with the vacant p-orbital of central carbon atom. So, it is resonance stabilised. Therefore, it is the most stable among the given carbanion ions. More the number of resonating structures, more will be the stability.
JCECE - 2010
GENERAL ORGANIC CHEMISTRY
231712
Which of the following is not a resonating form of benzaldehyde?
1
2
3
4
Explanation:
The resonating structure of benzadedayde is given as From the above resonating structure, we can say that structure (b) is not possible. In this case, positive charge is on the oxygen atom which is highly stable.
231705
The reaction intermediate produced by homolytic cleavage of bond is called
1 carbene
2 carbocation
3 carbanion
4 free radical
Explanation:
Homolytic bond fission- when a covalent bond forming in such way that each atom forming covalent bond takes away one electron away one electron shared the cleavage of bond called hemolytic fission. **Example-** Free radical because this reaction takes place only in the presence of heat, light and peroxide bond so the reaction intermediate form is free radical.
J and K CET-(2007)
GENERAL ORGANIC CHEMISTRY
231724
Reimer-Tiemann reaction involves :
1 carbonium ion intermediate
2 carbene intermediate
3 carbanion intermediate
4 free radical intermediate
Explanation:
Reimer Tiemann reaction involve carbene as intermediate, when phenol react with chloroform in the presence of base ortho hydrobenzaldehyde is formed.
are stabilised by hyperconjugation. In $\mathrm{C}_{6} \mathrm{H}_{5} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ benzyl group is resonance stabilised. In the triphenyl methyl carbanium ion, the $\pi$ electrons of all the three benzene rings are delocalised with the vacant p-orbital of central carbon atom. So, it is resonance stabilised. Therefore, it is the most stable among the given carbanion ions. More the number of resonating structures, more will be the stability.
JCECE - 2010
GENERAL ORGANIC CHEMISTRY
231712
Which of the following is not a resonating form of benzaldehyde?
1
2
3
4
Explanation:
The resonating structure of benzadedayde is given as From the above resonating structure, we can say that structure (b) is not possible. In this case, positive charge is on the oxygen atom which is highly stable.
are stabilised by
