Higher the tendency to loss a proton, higher will be the acidic character. Besides it, higher the stability of conjugate base, more will be acidic charater. Among the given carboxylate ion $\left(\mathrm{RCOO}^{-}\right)$is stabilized by resonance, thus it is more stable and hence, $\mathrm{RCOOH}$ is the most acidic, $\mathrm{C}_{2} \mathrm{H}_{2}$, on the other hand, gives $\mathrm{HC} \equiv \mathrm{C}^{-}$ion which is not so stable, thus it is a weak acid. Alcohols are more acidic as compared to ethyne but less acidic as compared to water. Thus, the order of acidic character is $\mathrm{RCOOH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{ROH}>\mathrm{C}_{2} \mathrm{H}_{2}$
UP CPMT-2010
GENERAL ORGANIC CHEMISTRY
231590
Which of the following is the strongest acid?
1 $\mathrm{C}_{2} \mathrm{H}_{6}$
2 $\mathrm{C}_{6} \mathrm{H}_{6}$
3 $\mathrm{CH} \equiv \mathrm{CH}$
4 $\mathrm{CH}_{3} \mathrm{OH}$
Explanation:
(D): $\mathrm{CH}_{3} \mathrm{OH}$ (methyl alcohol) among the given compounds, has the highest tendency to donate a proton, hence it is the strongest acid. $\underset{\text { methanol }}{\mathrm{CH}_{3} \mathrm{OH}} \rightleftharpoons \underset{\text { methoxideion }}{\mathrm{CH}_{3} \mathrm{O}^{-}}+\mathrm{H}^{+}$
UP CPMT-2009
GENERAL ORGANIC CHEMISTRY
231591
$\mathrm{C}-\mathrm{C}$ bond order in benzene is
1 1
2 2
3 Between 1 and 2
4 None of these
Explanation:
Number of bonds between two atoms is called bond order. Reasonating structures of benzene $\rightarrow\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ $\therefore$ The $\mathrm{C}-\mathrm{C}$ bond is between the double and single bond due to the resonance so its bond order is 1.5.
1 $\mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} 1$
2 $\mathrm{CH}_3 \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
3 $\mathrm{CH}_{3} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} \mathrm{l}$
4 $\mathrm{CH}_3 \dot{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
Explanation:
In homolytic, the covalent bond is broken in such a way that each resulting species known as free radical. $\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{Cl} \underset{\text { fission }}{\stackrel{\text { Homolytic }}{\longrightarrow}} \mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2} \text { and } \dot{\mathrm{C}} 1$
Higher the tendency to loss a proton, higher will be the acidic character. Besides it, higher the stability of conjugate base, more will be acidic charater. Among the given carboxylate ion $\left(\mathrm{RCOO}^{-}\right)$is stabilized by resonance, thus it is more stable and hence, $\mathrm{RCOOH}$ is the most acidic, $\mathrm{C}_{2} \mathrm{H}_{2}$, on the other hand, gives $\mathrm{HC} \equiv \mathrm{C}^{-}$ion which is not so stable, thus it is a weak acid. Alcohols are more acidic as compared to ethyne but less acidic as compared to water. Thus, the order of acidic character is $\mathrm{RCOOH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{ROH}>\mathrm{C}_{2} \mathrm{H}_{2}$
UP CPMT-2010
GENERAL ORGANIC CHEMISTRY
231590
Which of the following is the strongest acid?
1 $\mathrm{C}_{2} \mathrm{H}_{6}$
2 $\mathrm{C}_{6} \mathrm{H}_{6}$
3 $\mathrm{CH} \equiv \mathrm{CH}$
4 $\mathrm{CH}_{3} \mathrm{OH}$
Explanation:
(D): $\mathrm{CH}_{3} \mathrm{OH}$ (methyl alcohol) among the given compounds, has the highest tendency to donate a proton, hence it is the strongest acid. $\underset{\text { methanol }}{\mathrm{CH}_{3} \mathrm{OH}} \rightleftharpoons \underset{\text { methoxideion }}{\mathrm{CH}_{3} \mathrm{O}^{-}}+\mathrm{H}^{+}$
UP CPMT-2009
GENERAL ORGANIC CHEMISTRY
231591
$\mathrm{C}-\mathrm{C}$ bond order in benzene is
1 1
2 2
3 Between 1 and 2
4 None of these
Explanation:
Number of bonds between two atoms is called bond order. Reasonating structures of benzene $\rightarrow\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ $\therefore$ The $\mathrm{C}-\mathrm{C}$ bond is between the double and single bond due to the resonance so its bond order is 1.5.
1 $\mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} 1$
2 $\mathrm{CH}_3 \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
3 $\mathrm{CH}_{3} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} \mathrm{l}$
4 $\mathrm{CH}_3 \dot{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
Explanation:
In homolytic, the covalent bond is broken in such a way that each resulting species known as free radical. $\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{Cl} \underset{\text { fission }}{\stackrel{\text { Homolytic }}{\longrightarrow}} \mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2} \text { and } \dot{\mathrm{C}} 1$
Higher the tendency to loss a proton, higher will be the acidic character. Besides it, higher the stability of conjugate base, more will be acidic charater. Among the given carboxylate ion $\left(\mathrm{RCOO}^{-}\right)$is stabilized by resonance, thus it is more stable and hence, $\mathrm{RCOOH}$ is the most acidic, $\mathrm{C}_{2} \mathrm{H}_{2}$, on the other hand, gives $\mathrm{HC} \equiv \mathrm{C}^{-}$ion which is not so stable, thus it is a weak acid. Alcohols are more acidic as compared to ethyne but less acidic as compared to water. Thus, the order of acidic character is $\mathrm{RCOOH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{ROH}>\mathrm{C}_{2} \mathrm{H}_{2}$
UP CPMT-2010
GENERAL ORGANIC CHEMISTRY
231590
Which of the following is the strongest acid?
1 $\mathrm{C}_{2} \mathrm{H}_{6}$
2 $\mathrm{C}_{6} \mathrm{H}_{6}$
3 $\mathrm{CH} \equiv \mathrm{CH}$
4 $\mathrm{CH}_{3} \mathrm{OH}$
Explanation:
(D): $\mathrm{CH}_{3} \mathrm{OH}$ (methyl alcohol) among the given compounds, has the highest tendency to donate a proton, hence it is the strongest acid. $\underset{\text { methanol }}{\mathrm{CH}_{3} \mathrm{OH}} \rightleftharpoons \underset{\text { methoxideion }}{\mathrm{CH}_{3} \mathrm{O}^{-}}+\mathrm{H}^{+}$
UP CPMT-2009
GENERAL ORGANIC CHEMISTRY
231591
$\mathrm{C}-\mathrm{C}$ bond order in benzene is
1 1
2 2
3 Between 1 and 2
4 None of these
Explanation:
Number of bonds between two atoms is called bond order. Reasonating structures of benzene $\rightarrow\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ $\therefore$ The $\mathrm{C}-\mathrm{C}$ bond is between the double and single bond due to the resonance so its bond order is 1.5.
1 $\mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} 1$
2 $\mathrm{CH}_3 \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
3 $\mathrm{CH}_{3} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} \mathrm{l}$
4 $\mathrm{CH}_3 \dot{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
Explanation:
In homolytic, the covalent bond is broken in such a way that each resulting species known as free radical. $\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{Cl} \underset{\text { fission }}{\stackrel{\text { Homolytic }}{\longrightarrow}} \mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2} \text { and } \dot{\mathrm{C}} 1$
Higher the tendency to loss a proton, higher will be the acidic character. Besides it, higher the stability of conjugate base, more will be acidic charater. Among the given carboxylate ion $\left(\mathrm{RCOO}^{-}\right)$is stabilized by resonance, thus it is more stable and hence, $\mathrm{RCOOH}$ is the most acidic, $\mathrm{C}_{2} \mathrm{H}_{2}$, on the other hand, gives $\mathrm{HC} \equiv \mathrm{C}^{-}$ion which is not so stable, thus it is a weak acid. Alcohols are more acidic as compared to ethyne but less acidic as compared to water. Thus, the order of acidic character is $\mathrm{RCOOH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{ROH}>\mathrm{C}_{2} \mathrm{H}_{2}$
UP CPMT-2010
GENERAL ORGANIC CHEMISTRY
231590
Which of the following is the strongest acid?
1 $\mathrm{C}_{2} \mathrm{H}_{6}$
2 $\mathrm{C}_{6} \mathrm{H}_{6}$
3 $\mathrm{CH} \equiv \mathrm{CH}$
4 $\mathrm{CH}_{3} \mathrm{OH}$
Explanation:
(D): $\mathrm{CH}_{3} \mathrm{OH}$ (methyl alcohol) among the given compounds, has the highest tendency to donate a proton, hence it is the strongest acid. $\underset{\text { methanol }}{\mathrm{CH}_{3} \mathrm{OH}} \rightleftharpoons \underset{\text { methoxideion }}{\mathrm{CH}_{3} \mathrm{O}^{-}}+\mathrm{H}^{+}$
UP CPMT-2009
GENERAL ORGANIC CHEMISTRY
231591
$\mathrm{C}-\mathrm{C}$ bond order in benzene is
1 1
2 2
3 Between 1 and 2
4 None of these
Explanation:
Number of bonds between two atoms is called bond order. Reasonating structures of benzene $\rightarrow\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ $\therefore$ The $\mathrm{C}-\mathrm{C}$ bond is between the double and single bond due to the resonance so its bond order is 1.5.
1 $\mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} 1$
2 $\mathrm{CH}_3 \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
3 $\mathrm{CH}_{3} \stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{2}$ and $\dot{\mathrm{C}} \mathrm{l}$
4 $\mathrm{CH}_3 \dot{\mathrm{C}} \mathrm{H}_2$ and $\mathrm{Cl}^{\ominus}$
Explanation:
In homolytic, the covalent bond is broken in such a way that each resulting species known as free radical. $\mathrm{CH}_{3} \mathrm{CH}_{2}-\mathrm{Cl} \underset{\text { fission }}{\stackrel{\text { Homolytic }}{\longrightarrow}} \mathrm{CH}_{3} \dot{\mathrm{C}} \mathrm{H}_{2} \text { and } \dot{\mathrm{C}} 1$
