274161
The number of unpaired electrons in the square planar $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ ion are
1 2
2 1
3 0
4 3
Explanation:
(C) : $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ Let, $\mathrm{x}$ be the oxidation state of Pt. $\mathrm{x}+4(-1)=-2$ $\mathrm{x}=+2$ $\mathrm{Pt}^{2+}=[\mathrm{Xe}] 5 \mathrm{~d}^8 \quad$ (Pairing occur because Pt belongs to the $5 \mathrm{~d}$ series metal) four $\mathrm{dsp}^2$ hybrid orbital There is no unpaired electron that's why it is diamagnetic.
J and K CET-(2008)
COORDINATION COMPOUNDS
274163
Which of the following complexes are not correctly matched with hybridization of their central metal ion?
274161
The number of unpaired electrons in the square planar $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ ion are
1 2
2 1
3 0
4 3
Explanation:
(C) : $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ Let, $\mathrm{x}$ be the oxidation state of Pt. $\mathrm{x}+4(-1)=-2$ $\mathrm{x}=+2$ $\mathrm{Pt}^{2+}=[\mathrm{Xe}] 5 \mathrm{~d}^8 \quad$ (Pairing occur because Pt belongs to the $5 \mathrm{~d}$ series metal) four $\mathrm{dsp}^2$ hybrid orbital There is no unpaired electron that's why it is diamagnetic.
J and K CET-(2008)
COORDINATION COMPOUNDS
274163
Which of the following complexes are not correctly matched with hybridization of their central metal ion?
NEET Test Series from KOTA - 10 Papers In MS WORD
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COORDINATION COMPOUNDS
274161
The number of unpaired electrons in the square planar $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ ion are
1 2
2 1
3 0
4 3
Explanation:
(C) : $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ Let, $\mathrm{x}$ be the oxidation state of Pt. $\mathrm{x}+4(-1)=-2$ $\mathrm{x}=+2$ $\mathrm{Pt}^{2+}=[\mathrm{Xe}] 5 \mathrm{~d}^8 \quad$ (Pairing occur because Pt belongs to the $5 \mathrm{~d}$ series metal) four $\mathrm{dsp}^2$ hybrid orbital There is no unpaired electron that's why it is diamagnetic.
J and K CET-(2008)
COORDINATION COMPOUNDS
274163
Which of the following complexes are not correctly matched with hybridization of their central metal ion?
274161
The number of unpaired electrons in the square planar $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ ion are
1 2
2 1
3 0
4 3
Explanation:
(C) : $\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$ Let, $\mathrm{x}$ be the oxidation state of Pt. $\mathrm{x}+4(-1)=-2$ $\mathrm{x}=+2$ $\mathrm{Pt}^{2+}=[\mathrm{Xe}] 5 \mathrm{~d}^8 \quad$ (Pairing occur because Pt belongs to the $5 \mathrm{~d}$ series metal) four $\mathrm{dsp}^2$ hybrid orbital There is no unpaired electron that's why it is diamagnetic.
J and K CET-(2008)
COORDINATION COMPOUNDS
274163
Which of the following complexes are not correctly matched with hybridization of their central metal ion?
