ELECTROCHEMISTRY
276283
Specific conductance of $0.1 \mathrm{MHNO}_{3}$ is $6.3 \times 10^{-2} \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. The molar conductance of the solution is
1 $6.300 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
2 $63.0 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
3 $630 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
4 $315 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
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Explanation:
Given that, Concentration of nitric acid $=0.1 \mathrm{M}$ Specific conductance, $\mathrm{K}=6.3 \times 10^{-2} \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$ Molar conductance, $\lambda=\frac{\mathrm{K} \times 1000}{\mathrm{C}}$ $\begin{aligned} & =\frac{6.3 \times 10^{-2} \times 1000}{0.1} \\ & =630 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1} \mathrm{~mol}^{-1} \end{aligned}$