05. Type of Cell
ELECTROCHEMISTRY

276265 In electrolysis of $\mathrm{NaCl}$ when $\mathrm{Pt}$ electrode is taken then $\mathrm{H}_{2}$ is liberated at cathode while with Hg electrode if forms sodium amalgam

1 $\mathrm{Hg}$ is more inert that $\mathrm{Pt}$
2 more voltage is required to reduce $\mathrm{H}^{+}$at $\mathrm{Hg}$ than at $\mathrm{Pt}$
3 $\mathrm{Na}$ is dissolved in $\mathrm{Hg}$ while it does not dissolved in $\mathrm{Pt}$
4 concentration of $\mathrm{H}^{+}$ions is larger when $\mathrm{Pt}$ electrode is taken
ELECTROCHEMISTRY

276266 On the basis of the information available from the reaction $\frac{4}{3} \mathrm{Al}+\mathrm{O}_{2} \rightarrow \frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3}, \Delta \mathrm{G}=-827 \mathrm{~kJ}$ $\mathrm{mol}^{-1}$ of $\mathrm{O}_{2}$, the minimum emf required to carry out an electrolysis of $\mathrm{Al}_{2} \mathrm{O}_{3}$ is $(\mathrm{F}=\mathbf{9 6 5 0 0} \mathrm{C}$ $\mathrm{mol}^{-1}$ )

1 $2.14 \mathrm{~V}$
2 $4.28 \mathrm{~V}$
3 $6.42 \mathrm{~V}$
4 $8.56 \mathrm{~V}$
ELECTROCHEMISTRY

276267 The standard emf of a galvanic cell involving cell reaction with $n=2$ is found to be $0.295 \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. The equilibrium constant of the reaction would be

1 $2.0 \times 10^{11}$
2 $4.0 \times 10^{12}$
3 $1.0 \times 10^{2}$
4 $1.0× 10^{10}$
(Given, $\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$
$\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
ELECTROCHEMISTRY

276259 In a electrochemical cell, the reaction will be feasible when

1 $\Delta \mathrm{G}=-\mathrm{ve}, \mathrm{E}=+\mathrm{ve}$
2 $\Delta \mathrm{G}=+\mathrm{ve}, \mathrm{E}=-\mathrm{ve}$
3 $\Delta \mathrm{G}=0, \mathrm{E}=-\mathrm{ve}$
4 $\Delta \mathrm{G}=0, \mathrm{E}=0$
ELECTROCHEMISTRY

276265 In electrolysis of $\mathrm{NaCl}$ when $\mathrm{Pt}$ electrode is taken then $\mathrm{H}_{2}$ is liberated at cathode while with Hg electrode if forms sodium amalgam

1 $\mathrm{Hg}$ is more inert that $\mathrm{Pt}$
2 more voltage is required to reduce $\mathrm{H}^{+}$at $\mathrm{Hg}$ than at $\mathrm{Pt}$
3 $\mathrm{Na}$ is dissolved in $\mathrm{Hg}$ while it does not dissolved in $\mathrm{Pt}$
4 concentration of $\mathrm{H}^{+}$ions is larger when $\mathrm{Pt}$ electrode is taken
ELECTROCHEMISTRY

276266 On the basis of the information available from the reaction $\frac{4}{3} \mathrm{Al}+\mathrm{O}_{2} \rightarrow \frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3}, \Delta \mathrm{G}=-827 \mathrm{~kJ}$ $\mathrm{mol}^{-1}$ of $\mathrm{O}_{2}$, the minimum emf required to carry out an electrolysis of $\mathrm{Al}_{2} \mathrm{O}_{3}$ is $(\mathrm{F}=\mathbf{9 6 5 0 0} \mathrm{C}$ $\mathrm{mol}^{-1}$ )

1 $2.14 \mathrm{~V}$
2 $4.28 \mathrm{~V}$
3 $6.42 \mathrm{~V}$
4 $8.56 \mathrm{~V}$
ELECTROCHEMISTRY

276267 The standard emf of a galvanic cell involving cell reaction with $n=2$ is found to be $0.295 \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. The equilibrium constant of the reaction would be

1 $2.0 \times 10^{11}$
2 $4.0 \times 10^{12}$
3 $1.0 \times 10^{2}$
4 $1.0× 10^{10}$
(Given, $\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$
$\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
ELECTROCHEMISTRY

276259 In a electrochemical cell, the reaction will be feasible when

1 $\Delta \mathrm{G}=-\mathrm{ve}, \mathrm{E}=+\mathrm{ve}$
2 $\Delta \mathrm{G}=+\mathrm{ve}, \mathrm{E}=-\mathrm{ve}$
3 $\Delta \mathrm{G}=0, \mathrm{E}=-\mathrm{ve}$
4 $\Delta \mathrm{G}=0, \mathrm{E}=0$
ELECTROCHEMISTRY

276265 In electrolysis of $\mathrm{NaCl}$ when $\mathrm{Pt}$ electrode is taken then $\mathrm{H}_{2}$ is liberated at cathode while with Hg electrode if forms sodium amalgam

1 $\mathrm{Hg}$ is more inert that $\mathrm{Pt}$
2 more voltage is required to reduce $\mathrm{H}^{+}$at $\mathrm{Hg}$ than at $\mathrm{Pt}$
3 $\mathrm{Na}$ is dissolved in $\mathrm{Hg}$ while it does not dissolved in $\mathrm{Pt}$
4 concentration of $\mathrm{H}^{+}$ions is larger when $\mathrm{Pt}$ electrode is taken
ELECTROCHEMISTRY

276266 On the basis of the information available from the reaction $\frac{4}{3} \mathrm{Al}+\mathrm{O}_{2} \rightarrow \frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3}, \Delta \mathrm{G}=-827 \mathrm{~kJ}$ $\mathrm{mol}^{-1}$ of $\mathrm{O}_{2}$, the minimum emf required to carry out an electrolysis of $\mathrm{Al}_{2} \mathrm{O}_{3}$ is $(\mathrm{F}=\mathbf{9 6 5 0 0} \mathrm{C}$ $\mathrm{mol}^{-1}$ )

1 $2.14 \mathrm{~V}$
2 $4.28 \mathrm{~V}$
3 $6.42 \mathrm{~V}$
4 $8.56 \mathrm{~V}$
ELECTROCHEMISTRY

276267 The standard emf of a galvanic cell involving cell reaction with $n=2$ is found to be $0.295 \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. The equilibrium constant of the reaction would be

1 $2.0 \times 10^{11}$
2 $4.0 \times 10^{12}$
3 $1.0 \times 10^{2}$
4 $1.0× 10^{10}$
(Given, $\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$
$\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
ELECTROCHEMISTRY

276259 In a electrochemical cell, the reaction will be feasible when

1 $\Delta \mathrm{G}=-\mathrm{ve}, \mathrm{E}=+\mathrm{ve}$
2 $\Delta \mathrm{G}=+\mathrm{ve}, \mathrm{E}=-\mathrm{ve}$
3 $\Delta \mathrm{G}=0, \mathrm{E}=-\mathrm{ve}$
4 $\Delta \mathrm{G}=0, \mathrm{E}=0$
ELECTROCHEMISTRY

276265 In electrolysis of $\mathrm{NaCl}$ when $\mathrm{Pt}$ electrode is taken then $\mathrm{H}_{2}$ is liberated at cathode while with Hg electrode if forms sodium amalgam

1 $\mathrm{Hg}$ is more inert that $\mathrm{Pt}$
2 more voltage is required to reduce $\mathrm{H}^{+}$at $\mathrm{Hg}$ than at $\mathrm{Pt}$
3 $\mathrm{Na}$ is dissolved in $\mathrm{Hg}$ while it does not dissolved in $\mathrm{Pt}$
4 concentration of $\mathrm{H}^{+}$ions is larger when $\mathrm{Pt}$ electrode is taken
ELECTROCHEMISTRY

276266 On the basis of the information available from the reaction $\frac{4}{3} \mathrm{Al}+\mathrm{O}_{2} \rightarrow \frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3}, \Delta \mathrm{G}=-827 \mathrm{~kJ}$ $\mathrm{mol}^{-1}$ of $\mathrm{O}_{2}$, the minimum emf required to carry out an electrolysis of $\mathrm{Al}_{2} \mathrm{O}_{3}$ is $(\mathrm{F}=\mathbf{9 6 5 0 0} \mathrm{C}$ $\mathrm{mol}^{-1}$ )

1 $2.14 \mathrm{~V}$
2 $4.28 \mathrm{~V}$
3 $6.42 \mathrm{~V}$
4 $8.56 \mathrm{~V}$
ELECTROCHEMISTRY

276267 The standard emf of a galvanic cell involving cell reaction with $n=2$ is found to be $0.295 \mathrm{~V}$ at $25^{\circ} \mathrm{C}$. The equilibrium constant of the reaction would be

1 $2.0 \times 10^{11}$
2 $4.0 \times 10^{12}$
3 $1.0 \times 10^{2}$
4 $1.0× 10^{10}$
(Given, $\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}$
$\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
ELECTROCHEMISTRY

276259 In a electrochemical cell, the reaction will be feasible when

1 $\Delta \mathrm{G}=-\mathrm{ve}, \mathrm{E}=+\mathrm{ve}$
2 $\Delta \mathrm{G}=+\mathrm{ve}, \mathrm{E}=-\mathrm{ve}$
3 $\Delta \mathrm{G}=0, \mathrm{E}=-\mathrm{ve}$
4 $\Delta \mathrm{G}=0, \mathrm{E}=0$